<?
$tomorrow = mktime(0,0,0,date("m") ,date("d")+1,date("Y"));
$lastmonth = mktime(0,0,0,date("m")-1,date("d"), date("Y"));
$nextyear = mktime(0,0,0,date("m"), date("d"), date("Y")+1);
?>
$tomorrow = mktime(0,0,0,date("m") ,date("d")+1,date("Y"));
$lastmonth = mktime(0,0,0,date("m")-1,date("d"), date("Y"));
$nextyear = mktime(0,0,0,date("m"), date("d"), date("Y")+1);
?>
把2003-10-30 10:20:30这种格式的时间转化为由mktime()这个函数等到的时间形式,即转化为从1970年来的时间秒数?
有这种算法吗?
Thanks again!
$begin_time=strtotime("2003-7-15 22:25:36");//1058279136秒
$end_time=strtotime("2003-7-25 23:52:38");//1059148358秒
$time=$end_time-$begin_time;//869222秒
$lastmonth = mktime(0,0,0,date("m", mktime(0,0,0,7,1,2003))-1,date("d", mktime(0,0,0,7,1,2003)), date("Y", mktime(0,0,0,7,1,2003)));明白了吧
但是("2003-7-15 22:25:36")在我的数据库里是datetime类型的,那怎么转化呢?
xuzuning(唠叨)
能不能提供点资料,我现在可参考的资料实现少的可怜啊!
谢谢!谢谢!