这样接收post来的变量$_POST['变量名'];
这样接收get来的变理$_GET['变量名'];if($_POST['result'])
{
echo "Found thes entries in the database:<br>";
echo "<table width=90% align=center border=1><tr>
<td>idx</td>
<td>username</td>
<td>last name</td>
</tr>";
while($r=mysql_fetch_array($result))
{
$idex=$r["idx"];
$user=$r["username"];
$last=$r["lastname"];
echo "<tr>
<td>$idx</td>
<td>$user</td>
<td>$last</td>
</tr>";
}
echo "</table>";
}
else
{
echo "No data";
}
?>
这样接收get来的变理$_GET['变量名'];if($_POST['result'])
{
echo "Found thes entries in the database:<br>";
echo "<table width=90% align=center border=1><tr>
<td>idx</td>
<td>username</td>
<td>last name</td>
</tr>";
while($r=mysql_fetch_array($result))
{
$idex=$r["idx"];
$user=$r["username"];
$last=$r["lastname"];
echo "<tr>
<td>$idx</td>
<td>$user</td>
<td>$last</td>
</tr>";
}
echo "</table>";
}
else
{
echo "No data";
}
?>
mysql_select_db("example",$db) or die(mysql_error());
$result = mysql_query("select * from tbl", $db) or die(mysql_error());看看有没报错?
mysql_select_db("example") or die("error");
$result = mysql_query("select * from tbl";另外在Phpmyadmin里面输入你的sql看看有结果没
<head><title>Web Database Sample Index</title>
</head>
<body bgcolor=#ffffff>
<h2>Data from tbl</h2>
<?php
$link=mysql_connect("localhost","root","");
mysql_select_db("example",$link) or die ("bbbbb");
$result = mysql_query("select * from userinfo", $link) or die("aaaa");
//此处$result得到的值为什么老是falseif($result)
{
echo "Found thes entries in the database:<br>";
echo "<table width=90% align=center border=1><tr>
<td>idx</td>
<td>username</td>
<td>last name</td>
</tr>";
while($r=mysql_fetch_array($result))
{
$idex=$r["idx"];
$user=$r["username"];
$last=$r["lastname"];
echo "<tr>
<td>$idx</td>
<td>$user</td>
<td>$last</td>
</tr>";
}
echo "</table>";
}
else
{
echo "No data";
}?> </body>
</html>