你的問題講起來挺蔴煩,要分幾步:
Database non existent
表明你訪問的數據庫不存在,估計你數據庫連接有問題。
如果phpmyadmin在首頁上可以選擇數據庫的話,證明config.inc.php中$cfgPmaAbsoluteUri的值設定有誤,把$cfgPmaAbsoluteUri的值設定成phpmyadmin所在的絕對路逕吧;如果不能選擇,就可以和上個問題有關,看看你的mysql是否啓動了。
Database non existent
表明你訪問的數據庫不存在,估計你數據庫連接有問題。
如果phpmyadmin在首頁上可以選擇數據庫的話,證明config.inc.php中$cfgPmaAbsoluteUri的值設定有誤,把$cfgPmaAbsoluteUri的值設定成phpmyadmin所在的絕對路逕吧;如果不能選擇,就可以和上個問題有關,看看你的mysql是否啓動了。
把你的代碼貼出來瞅瞅啊。
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in c:\phpdev\www\indexman.php on line 19Database non existent代码在下面
include "database.inc";$server= "localhost"; /* Address of 1&1 database server */
$userw= ""; /* FTP-username */
$passw= ""; /* FTP-Password */
/* name of database */
MYSQL_CONNECT($server, $userw, $passw) or die ( "<H3>Server unreachable</H3>");
MYSQL_SELECT_DB($database) or die ( "<H3>Database non existent</H3>");//Count number of folders in Current Block Directory
$boxesarray = array();
$indexername = array();
$secondindexername = array();
$query = "SELECT * FROM block_spec";
$result = mysql_query($query);
$row = mysql_fetch_array($result);
$blockname = $row[0];
//$blockname = "ireland";$date_array=getdate();$year2=($date_array[year]*1)+1;if (($date_array[mon]*1)<10)
{
$datem="0$date_array[mon]";}
else
{
$datem="$date_array[mon]";}if (($date_array[mday]*1)<10)
{
$dated="0$date_array[mday]";}
else
{
$dated="$date_array[mday]";}if (($date_array[hours]*1)<10) {
$timeh = "0$date_array[hours]";
}
else {
$timeh = "$date_array[hours]";
}if (($date_array[minutes]*1)<10) {
$timem = "0$date_array[minutes]";
}
else {
$timem = "$date_array[minutes]";
}if (($date_array[seconds]*1)<10) {
$times = "0$date_array[seconds]";
}
else {
$times = "$date_array[seconds]";
}$datepro="$dated/$datem/$date_array[year]";$time = "$timeh:$timem";
$time2 = "$time:$times";if ($Export != "") {
$completedboxeslist = strtoupper($completedboxeslist);$query2 = "UPDATE $completedboxeslist SET Release_Date = '$datepro'";
mysql_query($query2);
$query2 = "UPDATE $completedboxeslist SET Release_Time = '$time2'";
mysql_query($query2);
$userw= ""; /* FTP-username */
$passw= ""; /* FTP-Password */
怎么是FTP的用户和密码?
应该是数据库的才对啊,是否写错了?
MYSQL_SELECT_DB($database) or die ( "<H3>Database non existent</H3>");== >$conn = MYSQL_CONNECT($server, $userw, $passw) or die ( "<H3>Server unreachable</H3>");
MYSQL_SELECT_DB($database, $conn) or die ( "<H3>Database non existent</H3>");
$database = "你的数据库名";