$today = getdate();
$year = $today[year];
$mon = $today[mon];
$mday = $today[mday];
echo $year."年".$mon."月".$mday."日";
$year = $today[year];
$mon = $today[mon];
$mday = $today[mday];
echo $year."年".$mon."月".$mday."日";
$thedate=date("Y-m-d");
echo $thedate;
?>范式:string date(string format, int [timestamp]);
我该怎么显示呢
netpirate(海盗)的$today = getdate();
返回的是一个数组,那样可以显示