代码:<?php
$myNum=100;
function addresschange($number)
{
$number=$number+1;
echo $number."<br>";
}
addresschange(&$myNum);
echo $myNum;
?>提示信息:
Warning: Call-time pass-by-reference has been deprecated; If you would like to pass it by reference, modify the declaration of addresschange(). If you would like to enable call-time pass-by-reference, you can set allow_call_time_pass_reference to true in your INI file in E:\masterphp\addresschange.php on line 9
101
101这几句提示信息是什么意思啊?
$myNum=100;
function addresschange($number)
{
$number=$number+1;
echo $number."<br>";
}
addresschange(&$myNum);
echo $myNum;
?>提示信息:
Warning: Call-time pass-by-reference has been deprecated; If you would like to pass it by reference, modify the declaration of addresschange(). If you would like to enable call-time pass-by-reference, you can set allow_call_time_pass_reference to true in your INI file in E:\masterphp\addresschange.php on line 9
101
101这几句提示信息是什么意思啊?
allow_call_time_pass_reference = off那么在运行时刻传递“引用”将出现警告
你可以修改 php.ini 令
allow_call_time_pass_reference = on也可以修改代码成这样:
$myNum=100;
function addresschange(&$number)
{
$number=$number+1;
echo $number."<br>";
}addresschange($myNum);
echo $myNum;
如果你想使用运行时引用传递参数,你可以设置php.ini中的allow_call_time_pass_reference为true;可以声明成
addresschange(& $number)
可以将一个变量通过引用传递给函数,这样该函数就可以修改其参数的值。语法如下:
<?php
function foo(&$var)
{
$var++;
}$a=5;
foo($a);
// $a is 6 here
?>
注意在函数调用时没有引用符号――只有函数定义中有。光是函数定义就足够使参数通过引用来正确传递了。在最近版本的 PHP 中如果把 & 用在 foo(&$a); 中会得到一条警告说“Call-time pass-by-reference”已经过时了。