我要用php上传文件,上传后要把文件从命名下,但用move_uploaded_file();的话怎样保持按照原来的文件类型来命名,但用rename的话
rename($_FILES[u_file][name],$u_name.".".$_FILES['u_file']['type']);他显示这样的错误,显示这样的错误Warning: rename(no_name.rar,牛逼application/octet-stream)[function.rename]: No such file or directory in C:\APMServ5.2.6\www\htdocs\WEB\upcomponent.php on line 64,求高手帮忙看下,先谢谢喽!
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rename($_FILES[u_file][name],$u_name.".".$_FILES['u_file']['type']);他显示这样的错误,显示这样的错误Warning: rename(no_name.rar,牛逼application/octet-stream)[function.rename]: No such file or directory in C:\APMServ5.2.6\www\htdocs\WEB\upcomponent.php on line 64,求高手帮忙看下,先谢谢喽!
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跟实际的文件类型时两码事。也就是说,如果浏览器不发送文件类型,那么,通过$_FILES['u_file']['type']也就无法正确判断上传的文件类型。
IE一般都不会正确发送文件类型信息,所以,建议lz放弃使用$_FILES['u_file']['type']判断类型,
而直接用扩展名就可以了。
$subfilename = strtolower(substr($_FILES['u_file']['type'], strrpos($_FILES['u_file']['type'], ".")+1));
$newFilename = $u_name.'.'.$subfilename;
$subfilename = strtolower(substr($_FILES['u_file']['name'], strrpos($_FILES['u_file']['name'], ".")+1));
$newFilename = $u_name.'.'.$subfilename;
$oldname=$_FILES['movieSource']['name'];
$temp=strrpos($oldname,".");
$temp1=strlen($oldname);
$fileStyle=substr($oldname,$temp,$temp1);
$basefileName=substr($oldname,0,$temp);
$md5fileName=md5($basefileName);
$timefileName=time();
$finalfileName=$md5fileName.$timefileName;$flvOut=$finalfileName.".flv";
$aviOut=$finalfileName.".avi";
$jpgOut=$finalfileName.".jpg";这是我做一个视频上传网站的时候用的.