急问

Question

已知:
Array
(
    [0] => prep
    [1] => date
    [2] => Array
        (
            [0] => Array
                (
                    [0] => Array
                        (
                            [0] => pro
                            [1] => Array
                                (
                                    [0] => Array
                                        (
                                            [0] => av
                                            [1] => aj
                                        )                                    [1] => pro
                                )                        )                    [1] => abc
                    [2] => Array
                        (
                            [0] => name
                            [1] => Array
                                (
                                    [0] => Array
                                        (
                                            [0] => av
                                            [1] => aj
                                        )                                    [1] => name
                                )                        )                )        ))
   
如何从已知数组生成以下形式数组:
Array
(
    [0] => Array
        (
            [0] => prep
            [1] => date
            [2] => pro
        )    [1] => Array
        (
            [0] => prep
            [1] => date
            [2] => av
            [3] => pro
        )    [2] => Array
        (
            [0] => prep
            [1] => date
            [2] => aj
            [3] => pro
        )    [3] => Array
        (
            [0] => prep
            [1] => date
            [2] => abc
        )    [4] => Array
        (
            [0] => prep
            [1] => date
            [2] => name
        )    [5] => Array
        (
            [0] => prep
            [1] => date
            [2] => av
            [3] => name
        )    [6] => Array
        (
            [0] => prep
            [1] => date
            [2] => aj
            [3] => neme
        ))

Answer 1

第一层有3个元素，其中元素2（角标为2的）又有3个元素，元素2的这3个元素之间是或的关系，即取其一即可，元素元素2的这3个元素中0和2号又是数组，这个数组里元素间的关系也是或，即取其一即可，而这个数组里的元素若
再为数组，其中元素就为与的关系，如av,aj二选一，然后加上pro是一种组合。总之就是第一层的元素3有多种
排列组合的可能性，然后我要排列出这所有可能的组合。是很乱，我都憋了好几天了也弄不出来，不知还有没有
解了，哎！盼救星阿~~~~~~~~~~~~~

Answer 2

看了半天总算明白了 根本就没有什么或的关系 就是穷举按照历便数组的组合如果环境是X86的话 深度不超过27 可以用递归 非递归算法有点复杂第一层全部需要 不参加循环
$array;//原始数据
$a = array($array[0],$array[1]); //模板
$r = array(); //结果
test($array, $a);
function test($array, $a)
{
 global $r;
 foreach($array as $tmp){
  if(!is_array($tmp)){
    $tmp2 = $a;
    $tmp2[] = $tmp;
    $r[] = $tmp2; //没有IDE也没有手册 忘了合并数组的函数
   }else {
     test($tmp, $a);
   }
 }
}

Answer 3

test($array[2], $a);失误 想着想着也给忘了