如何获取这段的值？

Question

Array
(
    [0] => 111.193.169.58
    [1] => -
    [2] => -
    [3] => [27/Sep/2010:18:45:04
    [4] => +0800]
    [5] => GET /callbackdown.php?contentid=640&ctype=8&phoneid=2&did=&status=1&username=test123456&imei= HTTP/1.1
    [6] => 404
    [7] => 169
    [8] => -
    [9] => leyu
    [10] => -
)
如何获取
[5] => GET /callbackdown.php?contentid=640&ctype=8&phoneid=2&did=&status=1&username=test123456&imei= HTTP/1.1
contentid
ctype
phoneid
status
username
这些的值？

Answer 1

方法多呢，
用 ? 分开
再用 & 分开
再用 = 分开 就行了。还有，用 parse_str 也行。也可以构造成一个完整的 url，然后 parse_url

Answer 2

<?php
    $arr = array(   0 => "111.193.169.58",
    1 => "-",
2 => "-",
3 => "[27/Sep/2010:18:45:04",
4 => "+0800]",
5 => "GET /callbackdown.php?contentid=640&ctype=8&phoneid=2&did=&status=1&username=test123456&imei= HTTP/1.1",
6 => "404",
7 => "169",
8 => "-",
9 => "leyu",
10 => "-"
);
    $index = strpos($arr[5],'/');
$str = substr($arr[5],$index);
$arr_1 = explode('?',$str);
$arr_2 = explode('&',$arr_1[1]);
$result = array();
foreach($arr_2 as $key=>$value)
{
    $arr_3 = explode("=",$value);
$result[$arr_3[0]] = $arr_3[1];
 
}
print_r($result);
?>

Answer 3

$arr = array(   0 => "111.193.169.58",
                    1 => "-",
                    2 => "-",
                    3 => "[27/Sep/2010:18:45:04",
                    4 => "+0800]",
                    5 => "GET /callbackdown.php?contentid=640&ctype=8&phoneid=2&did=&status=1&username=test123456&imei= HTTP/1.1",
                    6 => "404",
                    7 => "169",
                    8 => "-",
                    9 => "leyu",
                    10 => "-"
                );
preg_match_all('/[\?&]([^=]+?)=([^&]+)/',$arr[5],$matches);
$match=array_combine($matches[1],$matches[2]);
print_R($match);

Answer 4

[28/Sep/2010:17:06:50
这种格式怎么转成2010-10-28 17:06:50?

Answer 5

$matches
这个值是哪里来的？

Answer 6

[28/Sep/2010:17:06:50这种格式怎么转成2010-10-28 17:06:50?