<?php
include("conn.php");
$sql="select * from 'bbs'order by desc";
$query=mysql_query($sql);
while($row=mysql_fetch_array($query)){
?>
<form name="form2" method="post" action="list.php">
用户:<?=$row[user]?> 标题:<?=row[title]?><br>
内容:<?=$row[content]?>
<?
}
?></form>Parse error: syntax error, unexpected '[', expecting ',' or ';' in E:\www\list.php on line 12错误如上- -~ 求高手帮忙。·
include("conn.php");
$sql="select * from 'bbs'order by desc";
$query=mysql_query($sql);
while($row=mysql_fetch_array($query)){
?>
<form name="form2" method="post" action="list.php">
用户:<?=$row[user]?> 标题:<?=row[title]?><br>
内容:<?=$row[content]?>
<?
}
?></form>Parse error: syntax error, unexpected '[', expecting ',' or ';' in E:\www\list.php on line 12错误如上- -~ 求高手帮忙。·
include("conn.php");
$sql="select * from 'bbs'order by desc";
$query=mysql_query($sql);
while($row=mysql_fetch_array($query)){
?>
<form name="form2" method="post" action="list.php">用户:<?php echo $row['user']; ?> 标题:<?php echo $row['title']; ?><br>
内容:<?php echo $row['content']; ?> <?php
}
?></form>
<?php
include("conn.php");
$sql="select * from 'bbs'order by desc";
$query=mysql_query($sql);
while($row=mysql_fetch_array($query)){
?>
<form name="form2" method="post" action="list.php">
用户:<?echo $row['user']; ?> 标题:<?echo $row['title']?><br>
内容:<?echo $row['content']?>
<?
}
?></form>
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in E:\www\list.php on line 6
<form name="form2" method="post" action="list.php"><?php
include("conn.php"); $sql="select * from bbs order by desc";
$query=mysql_query($sql);
while($row=mysql_fetch_array($query)){
?>
用户:<?php $row["user"]; ?> 标题:<?php row["title"]; ?><br>
内容:<?php $row["content"]; ?>
<?php
}
?></form>
order by 某个字段 desc
还有'bbs'order连在一起了
这行有问题- -!
对,,提醒我了,'bbs'又是个问题啊,应该改成`,不是'
添加也是用CONN连接的不是手动插入的·