php正则得到url的地址

Question

一个数组 内容是
<a href="view?v=image&p=%E9%A3%8E%E6%99%AF&b=0&x=w0&pid=ysearch" target="_blank" name="doc3_p"><img src="http://tn1.cn2.yahoo.com/image/15ba/02add37e762998965f.jpeg" onload="setImgSize(this,170,170);"></a>我只要得到 view?v=image&p=%E9%A3%8E%E6%99%AF&b=0&x=w0&pid=ysearch 正则应该怎么写

Answer 1

应该有你想要的，不知对不对
$str = '<a href="view?v=image&p=%E9%A3%8E%E6%99%AF&b=0&x=w0&pid=ysearch" target="_blank" name="doc3_p"><img src="http://tn1.cn2.yahoo.com/image/15ba/02add37e762998965f.jpeg" onload="setImgSize(this,170,170);"></a>';

preg_match_all ('|^<a href=\"(.*)\".*|U',$str,$out, PREG_PATTERN_ORDER);
print_r($out);Array
(
    [0] => Array
        (
            [0] => <a href="view?v=image&p=%E9%A3%8E%E6%99%AF&b=0&x=w0&pid=ysearch"
        )    [1] => Array
        (
            [0] => view?v=image&p=%E9%A3%8E%E6%99%AF&b=0&x=w0&pid=ysearch
        ))

Answer 2

我是这样子写的 
foreach($img as $img_url){
 
}
$img是包含有<a 等内容 我现在想要生成一个新的数组 内容就只有 href里面的内容
也就是 view?v=image&p=%E9%A3%8E%E6%99%AF&b=0&x=w0&pid=ysearch

Answer 3

//纯手写，没测试
preg_match_all('/href=[\'"]+(.*)[\'"]+/',$str,$matches);var_dump($matches[1]);

Answer 4

<?php
$str = '
<a href="view?v=image&p=%E9%A3%8E%E6%99%AF&b=0&x=w0&pid=ysearch" target="_blank" name="doc3_p">
<img src="http://tn1.cn2.yahoo.com/image/15ba/02add37e762998965f.jpeg" onload="setImgSize(this,170,170);"></a>
';
preg_match("/<a\s*href=\"(.*?)\"[^>]*>.*?<\/a>/is", $str, $aMatch);
print_r($aMatch[1]);
?>

Answer 5

<?php
$str = '<a href="view?v=image&p=%E9%A3%8E%E6%99%AF&b=0&x=w0&pid=ysearch" target="_blank" name="doc3_p"><img src="http://tn1.cn2.yahoo.com/image/15ba/02add37e762998965f.jpeg" onload="setImgSize(this,170,170);"></a>';preg_match_all('/href=(\'|"|\s)*([^\'">\s]+)/i',$str,$match);
print_r($match);preg_match_all('/src=(\'|"|\s)*([^\'">\s]+)/i',$str,$match);
print_r($match);
?>