关于JSON数据解析

Question

本帖最后由 xeqtrl982 于 2010-05-11 22:39:25 编辑

Answer 1

$json = '{"orderData":{"date":"2010-05-11T01:11:33-07:00","receipt":"xxxxx","promo":{"@nil":"true"},"pmtType":"xxxxx","txnType":"SALE","item":"1","amount":"47.00","site":"seolv","affi":"xxx","country":"US","state":"xx","lastName":"xxx","firstName":"xxx","currency":"USD","email":"xxxxx.com","zip":"xxxxx","rebillAmount":"47.00","processedPayments":"1","futurePayments":"98","nextPaymentDate":"2010-06-11T00:00:00-07:00","status":"ACTIVE","accountAmount":"16.99","role":"AFFILIATE"}}';
$result = json_decode($json, true);
//echo "<pre>";
//print_r($result);
//echo "</pre>";
echo $result['orderData']['firstName'];//xxx 

Answer 2

谢楼上了，那$json是一个由多条json组成的记录呢，如何进行循环
 

Answer 3

1.$result = json_decode($json, true);2.获取json记录数，而后循环count($result['orderData'])
如
orderData的第2条记录的firstname则用
$result['orderData'][1]['firstName']来表示！

Answer 4

楼主要学会自己调试啊，除了echo还可以print_r，还可以var_dump啊，自己输出一下整个数组就很容易知道结构了！
$json = '{"orderData":{"date":"2010-05-11T01:11:33-07:00","receipt":"xxxxx","promo":{"@nil":"true"},"pmtType":"xxxxx","txnType":"SALE","item":"1","amount":"47.00","site":"seolv","affi":"xxx","country":"US","state":"xx","lastName":"xxx","firstName":"xxx","currency":"USD","email":"xxxxx.com","zip":"xxxxx","rebillAmount":"47.00","processedPayments":"1","futurePayments":"98","nextPaymentDate":"2010-06-11T00:00:00-07:00","status":"ACTIVE","accountAmount":"16.99","role":"AFFILIATE"}}';
$arr = json_decode($json,true);
print_r($arr);

Answer 5

$rs = json_decode($s);
echo $rs->orderData->firstName;完全可以