如何获取URL参数的值?

Question

http://www.123456.com/test/wang/160/2000-12-18比如我的php文件是test.php, 如何分别获取wang, 160, 及2000-12-18的值呢，谢谢！

Answer 1

用正则表达式。<?php$url = "http://www.123456.com/test/wang/160/2000-12-18";
if (preg_match('%test/(?P<p1>[^/]*)/(?P<p2>[^/]*)/(?P<p3>[^/]*)%', $url, $matches))
{
$p1 = $matches['p1'];
$p2 = $matches['p2'];
$p3 = $matches['p3'];
var_dump($p1);
var_dump($p2);
var_dump($p3);
}?>

Answer 2

有那么复杂吗，晕哦，$b=$_SERVER['REQUEST_URI'];
$a=$_SERVER['QUERY_STRING'];  这样就能得到

Answer 3

没必要正则$url = 'http://www.123456.com/test/wang/160/2000-12-18';list(,,,,$path[],$path[],$path[]) = explode('/',$url);print_r ($path);

Answer 4

$url = $_SERVER["SERVER_NAME"].$_SERVER["REQUEST_URI"];
$path = explode('/',$url);
print_r ($path);