求一个浮点数的转换方法

Question

    $price = number_format("100000000.00",2);
    echo $price;
$price输出 =》100,000,000.00，我想把$price直接转换为“亿”或“百万”为单位的字符，求方法

Answer 1

<?php
header('Content-Type: text/html;charset=utf-8');
class ChineseNumber
{
var $basical=array(0=>"零","一","二","三","四","五","六","七","八","九");
//var $basical=array(0=>"零","壹","贰","叁","肆","伍","陆","柒","捌","玖");
var $advanced=array(1=>"十","百","千");
//var $advanced=array(1=>"拾","佰","仟");
var $top=array(1=>"万","亿");var $level; // 以4位为一级// 先实现万一下的数的转换
function ParseNumber($number)
{
if ($number>999999999999) // 只能处理到千亿。
return "数字太大，无法处理。抱歉！";
if ($number==0)
return "零";for($this->level=0;$number>0.0001;$this->level++,$number=floor($number / 10000))
{
// 对于中文来说，应该是4位为一组。
// 四个变量分别对应 个、十、百、千 位。
$n1=substr($number,-1,1);
if($number>9)
$n2=substr($number,-2,1);
else
$n2=0;
if($number>99)
$n3=substr($number,-3,1);
else
$n3=0;
if($number>999)
$n4=substr($number,-4,1);
else
$n4=0;if($n4)
$parsed[$this->level].=$this->basical[$n4].$this->advanced[3];
else
if(($number/10000)>=1) // 千位为0，数值大于9999的情况
$parsed[$this->level].="零";
if($n3)
$parsed[$this->level].=$this->basical[$n3].$this->advanced[2];
else
if(!ereg("零$",$parsed[$this->level]) && ($number / 1000)>=1) // 不出现连续两个“零”的情况
$parsed[$this->level].="零";
if($n2)
$parsed[$this->level].=$this->basical[$n2].$this->advanced[1];
else
if(!ereg("零$",$parsed[$this->level]) && ($number / 100)>=1) // 不出现连续两个“零”的情况
$parsed[$this->level].="零";
if($n1)
$parsed[$this->level].=$this->basical[$n1];
}
for($this->level-=1;$this->level>=0;$this->level--)
{
$result.=$parsed[$this->level].$this->top[$this->level];
}if(ereg("零$",$result))
$result=substr($result,0,strlen($result)-2);return $result;}
};$c=new ChineseNumber();
echo $c->ParseNumber(254);?>