<tr align="conter">
<a>标 题:</a> 
<input type="text" name="title" value="<{$Htitle}>" size="60">
</tr>
在用POST 或 GET 获取就可以了
<a>标 题:</a> 
<input type="text" name="title" value="<{$Htitle}>" size="60">
</tr>
在用POST 或 GET 获取就可以了
$array
<input type=text value="array['Business_Owner']" name=Business_Owner>这样
$query = "SELECT Business_Owner,Business_Name, Mailing_Address,Phone_Number,Crop_Type,Crop_Location,Section,Township,Range,Quarter,Acreage FROM pesticide_sensitive_crop where userid = ".$_GET["userid"].";"; $result = mysql_query($query);
if($row = mysql_fetch_assoc($result)){
$info = $row;
}
?>
...
<input type="text" id="Business_Owner" name="Business_Owner" value="<{$info['Business_Owner']}>">
<input type="text" id="Business_Name" name="Business_Name" value="<{$info['Business_Name']}>">
<input type="text" id="Mailing_Address" name="Mailing_Address" value="<{$info['Mailing_Address']}>">
...文本框默认显示出查询出来的结果。提交表单后,获取文本框内容,修改数据库记录。我是菜鸟,一起学习
$query = "SELECT Business_Owner,Business_Name, Mailing_Address,Phone_Number,Crop_Type,Crop_Location,Section,Township,Range,Quarter,Acreage FROM pesticide_sensitive_crop where userid = ".$_GET["userid"].";";$result = mysql_query($query);
if($row = mysql_fetch_assoc($result)){
$info = $row;
}
?>
...
<input type="text" id="Business_Owner" name="Business_Owner" value=" <{$info['Business_Owner']}>">
<input type="text" id="Business_Name" name="Business_Name" value=" <{$info['Business_Name']}>">
<input type="text" id="Mailing_Address" name="Mailing_Address" value=" <{$info['Mailing_Address']}>">
...
试过了,文本域显示不出从数据库提出来的数据??
$query = "SELECT Name,Mailing_Address,City,State,Zip,Phone_Number,Cell_Number FROM pesticide_sensitive_crop WHERE Email= [email protected] ";
$result = mysql_query($query);
$array=array($result);?〉
<input type="text" id="Name" name="Name" value="$array['0']"; >
<input type="text" id="Mailing_Address" name="Mailing_Address" value="$array['1']">是不是$result = mysql_query($query);
$array=array($result); 这个地方错了?怎么把数据库取出来的值直接赋值给数组呢?
帮帮忙阿,菜鸟啊
<?php
mysql_connect("localhost", "user", "pwd") or die(mysql_error());
mysql_select_db("test") or die(mysql_error());$query = "SELECT Name,Mailing_Address,City,State,Zip,Phone_Number,Cell_Number FROM pesticide_sensitive_crop WHERE Email= [email protected] ";
$result = mysql_query($query);$row = mysql_fetch_array($result);?>
<input type="text" name="x" value="<?php echo $row[Name] ?>" />
<input type="text" name="y" value="<?php echo $row[Mailing_Address] ?>" />
<input type="text" name="z" value="<?php echo $row[City] ?>" />这样就行!