急！！（菜鸟在线等）判断输出的问题！

Question

if($msg['all'] == "/dev/sda1")
{
}
else
{
}
实话没太明白你的意思，代码又乱又长．其实只要if else语句就可以了．

Answer 1

是不是这样if(is_dir("/disk4/") && $msg4[all]=='/dev/sda1') 
{ 
?> 
              <tr> 
                <td height="25" align="center" bgcolor="#F1F5FA">disk4 </td> 
                <td align="center" bgcolor="#F1F5FA"> <?php echo $msg4[used];?> </td> 
                <td align="center" bgcolor="#F1F5FA"> <?php echo $msg4[percent];?> </td> 
                <td align="center" bgcolor="#F1F5FA"> <?php echo $msg4[all];?> </td> 
              </tr> 
              <?php 
              }?> 
            </table> 
            <?php }else 
{ 
?> 

Answer 2

<?php if(is_dir("/disk1/")&&$msg1['all']!='/dev/sda1')
{
?>              
              <tr>
                <td height="25" align="center" bgcolor="#FFFFFF">disk1 </td>
                <td align="center" bgcolor="#FFFFFF" > <?php echo $msg1[used];?> </td>
                <td align="center" bgcolor="#FFFFFF"> <?php echo $msg1[percent];?> </td>
                <td align="center" bgcolor="#FFFFFF"> <?php echo $msg1[all];?> </td>
              </tr>
              <?php 
              }if(is_dir("/disk2/")&&$msg2['all']!='/dev/sda1')
{
?>
              <tr>
                <td height="25" align="center" bgcolor="#F1F5FA">disk2 </td>
                <td align="center" bgcolor="#F1F5FA"> <?php echo $msg2[used];?> </td>
                <td align="center" bgcolor="#F1F5FA"> <?php echo $msg2[percent];?> </td>
                <td align="center" bgcolor="#F1F5FA"> <?php echo $msg2[all];?> </td>
              </tr>
              <?php
    }if(is_dir("/disk3/")&&$msg3['all']!='/dev/sda1')
{
?>
              <tr>
                <td height="25" align="center" bgcolor="#F1F5FA">disk3 </td>
                <td align="center" bgcolor="#F1F5FA"> <?php echo $msg3[used];?> </td>
                <td align="center" bgcolor="#F1F5FA"> <?php echo $msg3[percent];?> </td>
                <td align="center" bgcolor="#F1F5FA"> <?php echo $msg3[all];?> </td>
              </tr>
            <?php
    }if(is_dir("/disk4/")&&$msg4['all']!='/dev/sda1')
{
?>
              <tr>
                <td height="25" align="center" bgcolor="#F1F5FA">disk4 </td>
                <td align="center" bgcolor="#F1F5FA"> <?php echo $msg4[used];?> </td>
                <td align="center" bgcolor="#F1F5FA"> <?php echo $msg4[percent];?> </td>
                <td align="center" bgcolor="#F1F5FA"> <?php echo $msg4[all];?> </td>
              </tr>
              <?php
              }?>
            </table>
            <?php}else
{
?>

Answer 3

//是不是这样？    <?php if(is_dir("/disk2/") && $msg2[all]!='/dev/sda1') //这
{ 
?> 
              <tr> 
                <td height="25" align="center" bgcolor="#F1F5FA">disk2 </td> 
                <td align="center" bgcolor="#F1F5FA"> <?php echo $msg2[used];?> </td> 
                <td align="center" bgcolor="#F1F5FA"> <?php echo $msg2[percent];?> </td> 
                <td align="center" bgcolor="#F1F5FA"> <?php echo $msg2[all];?> </td> 
              </tr> 
              <?php 
    }if(is_dir("/disk3/") && $msg3[all]!='/dev/sda1') //这
{ 
?> 
              <tr> 
                <td height="25" align="center" bgcolor="#F1F5FA">disk3 </td> 
                <td align="center" bgcolor="#F1F5FA"> <?php echo $msg3[used];?> </td> 
                <td align="center" bgcolor="#F1F5FA"> <?php echo $msg3[percent];?> </td> 
                <td align="center" bgcolor="#F1F5FA"> <?php echo $msg3[all];?> </td> 
              </tr> 
            <?php 
    }if(is_dir("/disk4/") && $msg4[all]!='/dev/sda1') //这
{ 
?> 
              <tr> 
                <td height="25" align="center" bgcolor="#F1F5FA">disk4 </td> 
                <td align="center" bgcolor="#F1F5FA"> <?php echo $msg4[used];?> </td> 
                <td align="center" bgcolor="#F1F5FA"> <?php echo $msg4[percent];?> </td> 
                <td align="center" bgcolor="#F1F5FA"> <?php echo $msg4[all];?> </td> 
              </tr> 
              <?php 
              }?> 
            </table> 
            <?php }else 
{ 
?>