关于24小时计时制怎么换算成am/pm的格式？

Question

小时取余.
模0为am 模1为pm

Answer 1

介意用unix时间戳 
用date函数的date('a', time())

Answer 2

mrshelly(Shelly)：
答案太抽象了。caotian2000(乡约北京)：
结果应该是固定的。如果问函数，两个都可以，最好两个都提供，^-^.

Answer 3

慢了,呵呵ls对了echo date('Y-m-d H:i:s a',strtotime('2008-08-02 00:00:00'));

Answer 4

UPDATE 表
   SET 24小时计时制 = IF(LEFT(24小时计时制, 2) > 12,
                         CONCAT(LEFT(24小时计时制, 2)-12, RIGHT(24小时计时制, 6)),
                         24小时计时制),
       t = IF(LEFT(24小时计时制, 2) > 12, 'am' , 'pm');

Answer 5

更正下：
UPDATE 表
   SET 24小时计时制 = IF(LEFT(24小时计时制, 2) > 12,
                         CONCAT(LEFT(24小时计时制, 2)-12, RIGHT(24小时计时制, 6)),
                         24小时计时制),
       `日期  am/pm`= IF(LEFT(24小时计时制, 2) > 12, 'am' , 'pm');

Answer 6

<?php
echo date('Y-m-d H:i:s A', strtotime('2008-08-02 23:59:59'));
?>

Answer 7

$drr = array(
"2008-08-02 00:00:00",
"2008-08-02 00:00:01",
"2008-08-02 00:59:59",
"2008-08-02 01:00:00",
"2008-08-02 01:00:01",
"2008-08-02 11:59:59",
"2008-08-02 12:00:00",
"2008-08-02 12:00:01",
"2008-08-02 12:59:59",
"2008-08-02 13:00:00",
"2008-08-02 13:00:01",
"2008-08-02 23:00:00",
"2008-08-02 23:00:01",
"2008-08-02 23:59:59",
);$r = array_map('conv_date',$drr);
print_r($r);function conv_date($s) {
  return strftime("%Y-%m-%d %I:%M:%S %p",strtotime($s));
}

Answer 8

echo date('Y-m-d H:i:s a',strtotime('2008-08-02 00:00:00'));!