本人通过搜索目录下所有图片文件,实现列表,怎么实现分页???
代码如下:<table width="500" border="0" cellspacing="0" bordercolor="#000000">
<?php
$myDirectory = opendir("../images");
$entryName = TRUE;
while($entryName)
{
?>
<tr>
<?php
for($i = 0;$i < 3;$i++)
{
$entryName = readdir($myDirectory);
if($entryName == NULL)
break;
if($entryName == "." || $entryName == "..")
{
$i--;
continue;
}
?>
<td width="100" height="100"><div align="center">
<img src="<?php $strPath = "../images\/".$entryName; echo($strPath); ?>" width="100" height="100"></div></td>
<?php
}
?>
</tr> <?php
} }
closedir($myDirectory);
?>
</table>
代码如下:<table width="500" border="0" cellspacing="0" bordercolor="#000000">
<?php
$myDirectory = opendir("../images");
$entryName = TRUE;
while($entryName)
{
?>
<tr>
<?php
for($i = 0;$i < 3;$i++)
{
$entryName = readdir($myDirectory);
if($entryName == NULL)
break;
if($entryName == "." || $entryName == "..")
{
$i--;
continue;
}
?>
<td width="100" height="100"><div align="center">
<img src="<?php $strPath = "../images\/".$entryName; echo($strPath); ?>" width="100" height="100"></div></td>
<?php
}
?>
</tr> <?php
} }
closedir($myDirectory);
?>
</table>
解决方案 »
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