正则匹配，怎么匹配出来空的

Question

<DIV class="jingbian_astro04 clear">
<P>1、在人群里，你的话总是不多？</P>
<P><SPAN><A href="http://astro.women.sohu.com/20100603/n272544016_3.shtml" 
target=_self>A、No</A></SPAN></P>
<P><SPAN><A href="http://astro.women.sohu.com/20100603/n272544016_2.shtml" 
target=_self>B、Yes</A></SPAN></P>
</DIV>
我写的代码：
$p_list='/\<DIV class\="jingbian_astro04 clear"\>(.*)';
$p_list.='\s+\<P\>(.*)\<\/P\>';
$p_list.='\<P\>\<SPAN\>\<A href="(.*)"';
$p_list.='target=\_self\>(.*)\<\/A\>\<\/SPAN\>\<\/P\>';
$p_list.='\s+\<\/DIV\>/';

Answer 1

$p_list='/<DIV class="jingbian_astro04 clear">(.*)';
$p_list.='s+<P>(.*)<\/P>';
$p_list.='<P><SPAN><A href="(.*)"';
$p_list.='target=_self>(.*)<\/A><\/SPAN><\/P>';
$p_list.='s+<\/DIV>/';这样试试

Answer 2

原串中的<p><span>。。这段出现了两次，你只匹配了一次。所以匹配不到。而且不该转义的地方你全转义了。$p_list='/<DIV class="jingbian_astro04 clear">(.*)\s+';
$p_list.='<P>(.*)<\/P>\s+';
$p_list.='<P><SPAN><A href="(.*)"\s+';
$p_list.='target=_self>(.*)<\/A><\/SPAN><\/P>\s+';
$p_list.='<P><SPAN><A href="(.*)"\s+';
$p_list.='target=_self>(.*)<\/A><\/SPAN><\/P>\s+';
$p_list.='<\/DIV>/isU';preg_match_all($p_list,$html,$matches);
print_r($matches);