<?xml version="1.0" encoding="utf-8"?>
<configuration>
<log4net>
<logger name="LogOperationADO" lockItem="false">
<level value="DEBUG" lockItem="false"/>
<appender-ref ref="LogOperationAdoNetAppender" />
</logger>
</log4net>
</configuration>讀取這個,本來衹是讀取最深一層<level value="DEBUG" lockItem="false"/> 裡面有 lockItem="false"的節點的屬性
所以之前是這樣寫的:foreach (XmlNode no in noSel.ChildNodes)
{
foreach (XmlNode no2 in no.ChildNodes) //modify start
{
object[] paras;
isNewRow = false; if (no2.Attributes == null) //屬性=空
{
if (no2.Value != null) //值不為空
{
strDescription = no2.Value; //得到值
}
continue;
}
attLen = no2.Attributes.Count + FIXCOLNUM;
paras = new object[attLen]; if (!string.IsNullOrEmpty(strDescription))
{
paras[0] = strDescription; //節點內容放入到數組中
} for (int i = FIXCOLNUM; i < no2.Attributes.Count + FIXCOLNUM; i++)
{
XmlAttribute att = no2.Attributes[i - FIXCOLNUM]; //屬性? if (!dataGridView1.Columns.Contains(att.Name))
{
dataGridView1.Columns.Add(att.Name, att.Name);
if (att.Name.Equals("lockItem"))
{
dataGridView1.Columns[att.Name].Visible = false; //存在lockItem的內容設為不可見 } if (att.Name.Equals("type") || att.Name.Equals("ref") || att.Name.Equals("name")) //modify
{
dataGridView1.Columns[att.Name].Visible = false;
} }
if (att.Name.Equals("lockItem") && att.Value != null && att.Value.Equals("false", StringComparison.OrdinalIgnoreCase))
{
isNewRow = true;
}
paras[i] = att.Value;
} if (isNewRow) //如lockItem不為空,且值為FALSE 則加到datagridview
{
dataGridView1.Rows.Add(paras);
dataGridView1.Rows[dataGridView1.Rows.Count - 1].Tag = no2;
}
strDescription = string.Empty;
}
}
但現在要連上一節點 <logger name="LogOperationADO" lockItem="false"> 含有lockItem="false" 的節點屬性也一起讀取出來
PS:是在datagridview 上顯示出來。
應該怎麼做呢?
像上面
<logger name="LogOperationADO" lockItem="false">
<level value="DEBUG" lockItem="false"/>屬性值:"LogOperationADO" ,"DEBUG"一同放到列名為 name 的上面,
就是達不到 name 顯示 LogOperationADO ,value列 顯示 DEBUG
-----------------------------
name value
LogOperationADO
DEBUG
------------------------------
現在是這樣
-----------------------------
name value
LogOperationADO
DEBUG
------------------------------
這樣應該怎麼解決呢?