求一字符串转字符串数组的算法

Question

有一用分号分隔的字符串
aaac;sfa;dadd;fffffff;nt;......
现在想将这个字符串转换成字符串数组
string[] str=new string[] {"aaac","dadd","fffffff","nt",.....};
有什么比较快速的算法没有?

Answer 1

string s="aaac;sfa;dadd;fffffff;nt";
string[] str=s.split(';');

Answer 2

string s = "aaac;sfa;dadd;fffffff;nt;";
string[] str = s.Split(';');

Answer 3

#注意，编译宏默认高位为00时为8进制，版本升级时候需要谨慎修改，如SPC008版本，DCCU_SPC=8，否则编译不通过
CCFLAG:=-Wall -O2 -fno-strict-aliasing -DCCU -DCCU_V=100 -DCCU_R=001 -DCCU_SPC=1 -DCCU_C=002 -DCCU_B=16 -D__CCU_305__ -D_LIBC_REENTRANT
LDFLAG:=-w -lpthread  -DCCU CCU_OBJ_TARGET:=
CCU_OBJ_TARGET+=CLI_Server_Socket.o
CCU_OBJ_TARGET+=CLI_Server_Main.o
CCU_OBJ_TARGET+=CCU_Adapt.o
CCU_OBJ_TARGET+=CCU_485comm.o
CLI_Server_Socket.o: ${CLIDIRS}/CLI_Server_Socket.c 
$(CC) $(CCFLAG) $(INCLUDE) -D_GNU_SOURCE -o CLI_Server_Socket.o -c ${CLIDIRS}/CLI_Server_Socket.c
CLI_Server_Main.o: ${CLIDIRS}/CLI_Server_Main.c 
$(CC) $(CCFLAG) $(INCLUDE) -D_GNU_SOURCE -o CLI_Server_Main.o -c ${CLIDIRS}/CLI_Server_Main.c
CCU_485comm.o: CCU_485comm.c CCU_485comm.h CCU_Adapt.h CCU_485Init.h CCU_typedef.h
$(CC) $(CCFLAG) $(INCLUDE) -D_GNU_SOURCE -o CCU_485comm.o -c CCU_485comm.c
CCU_Adapt.o: CCU_Adapt.c  CCU_Adapt.h  CCU_typedef.h CCU_Public.h
$(CC) $(CCFLAG) $(INCLUDE) -D_GNU_SOURCE -o CCU_Adapt.o -c CCU_Adapt.c
ccu: $(CCU_OBJ_TARGET)
  $(LD) $(LDFLAG) -o $@ $(CCU_OBJ_TARGET)
  $(STRIP) ccuclear:
/bin/rm *.o
/bin/rm ccu