请问 怎么使用 XmlDocument 创建一个XML字符串

Question

<?xml version="1.0" encoding="UTF-8"?><Message MsgID="1027" >
<DataRow id=1>
   <purDeptId>111</purDeptId>
   <localClassification>AAA</localClassification>
   <suppId>120010</suppId>
</DataRow>
<DataRow id=2>
   <purDeptId>2221</purDeptId>
   <localClassification>bbb</localClassification>
   <suppId>120011</suppId>
</DataRow>
</Message>
请问用C#怎么创建类似上面的XML??

Answer 1

http://blog.csdn.net/amandag/archive/2008/07/08/2623322.aspx

Answer 2

就是已知XmlDocument，怎样将其内容输出成字符串。最简单的使用XmlDocument.DocumentElement.OuterXml，但是这个不会输出最上面Xml声明。
如果需要全部Xml内容的话，用个StringWriter在XmlDocument.Save方法            XmlDocument xdoc = new XmlDocument();
            xdoc.LoadXml("<?xml version=\"1.0\" encoding=\"UTF-8\"?><root><ha>sdf</ha></root>");            StringWriter sw = new StringWriter();
            xdoc.Save(sw);
            sw.Close();
            Console.WriteLine(sw);

Answer 3

怎么感觉我没理解对问题？是创建Xml？用XmlWriter或者在XmlDocument中加入相应节点。

Answer 4

http://blog.csdn.net/amandag/archive/2008/07/08/2623322.aspx

Answer 5

楼主的意思是不是将记录集生成到XML？

Answer 6

XmlDocument xml=new XmlDocument();
xml.loadXml("<?xml version=\"1.0\" encoding=\"UTF-8\"?>"+
"<DataRow id=1>"+
   "<purDeptId>111</purDeptId>"+
   "<localClassification>AAA</localClassification>"+
   "<suppId>120010</suppId>"+
"</DataRow>"

Answer 7

     public static void Xdocument(DataTable dts,string filepath)
        {
            XmlDocument xdoc = new XmlDocument();
            XmlDeclaration dec = xdoc.CreateXmlDeclaration("1.0", "UTF-8", null);
            xdoc.AppendChild(dec);
            XmlElement root = xdoc.CreateElement("Message");
            xdoc.CreateAttribute("MsgID").Value = "\"1027\"";
            int count =1;
            XmlElement nod=null;
            foreach(DataRow dr in dts.Rows)
            {
                nod= xdoc.CreateElement("DataRow");
                nod.InnerText = (count).ToString();                XmlElement node1 = xdoc.CreateElement("purDeptId");
                node1.InnerText = dr["purDeptId"].ToString();                XmlElement node2 = xdoc.CreateElement("localClassification");
                node2.InnerText = dr["localClassification"].ToString();                XmlElement node3 = xdoc.CreateElement("suppId");
                node3.InnerText = dr["suppId"].ToString();                nod.AppendChild(node1);
                nod.AppendChild(node2);
                nod.AppendChild(node3);
                count++;
                root.AppendChild(nod);
            }
           
            xdoc.AppendChild(root);
            xdoc.Save(filepath);
           
        }调用。
            DataTable dt = new DataTable();
            dt.Columns.Add("purDeptId", typeof(int));
            dt.Columns.Add("localClassification", typeof(string));
            dt.Columns.Add("suppId", typeof(int));
            
             DataRow dr=dt.NewRow();
             dr["purDeptId"]=111;
             dr["localClassification"] = "AAA";
             dr["suppId"] = 120010;
             dt.Rows.Add(dr);             DataRow dr1 = dt.NewRow();
             dr1["purDeptId"] = 2221;
             dr1["localClassification"] = "bbb";
             dr1["suppId"] = 120010;
             dt.Rows.Add(dr1);
Xdocument(dt,@"c:\mesg.xml");