string connString = "Data Source=.;Initial Catalog=Logistics;User ID=sa ;Password=sa"; SqlConnection conn=new SqlConnection(connString);
conn.Open();
string sql = string.Format("insert into LogisticUser values ('{0}','{1}')", txtName.Text.Trim(), txtPassword.Text.Trim()); SqlCommand cmd = new SqlCommand(sql, conn);
int count = cmd.ExecuteNonQuery();
conn.Close();
在SQL server中是采用混合模式sa登陆
调试时提示:conn.Open();
用户sa 登陆失败,怎么回事呢?
conn.Open();
string sql = string.Format("insert into LogisticUser values ('{0}','{1}')", txtName.Text.Trim(), txtPassword.Text.Trim()); SqlCommand cmd = new SqlCommand(sql, conn);
int count = cmd.ExecuteNonQuery();
conn.Close();
在SQL server中是采用混合模式sa登陆
调试时提示:conn.Open();
用户sa 登陆失败,怎么回事呢?
http://hi.baidu.com/%B9%E2%D7%C5%BD%C5%D1%BE%B3%F6%BC%DE/blog/item/bda41447064cc8006b63e5aa.html