如何把一个bmp文件中的位图提取出来,生成一个Image对象 把它转成gif后用Image的构造器创建 解决方案 » 免费领取超大流量手机卡,每月29元包185G流量+100分钟通话, 中国电信官方发货 String imageFile = "a.jpg";InputStream imageIn = new FileInputStream(new File(imageFile));JPEGImageDecoder decoder = JPEGCodec.createJPEGDecoder(imageIn);BufferedImage im = decoder.decodeAsBufferedImage(); 不允许把它转化为gif格式,就是要直接处理bmp文件java中有没有处理bmp格式图形的API啊? /** loadbitmap() 方法由 Windows C 代码转换而来。 只能读取未压缩的 24 位和 8 位图像。已在 Windows 95 上用 Microsoft Paint 保存的图像对它进行了测试。如果图像不是 24 位或 8 位图像, 该程序拒绝进行任何尝试。我猜测如果先用 1100, 然后用 0011 对字节执行掩码操作,则也可将 4 位 图像包括在内。我实际上对这些图像不感兴趣。 如果尝试读取压缩图像,该例程可能失败,并产生 一个 IOException 异常。如果变量 ncompression 不为 0,则表示已经过压缩。 参数: sdir 和 sfile 是 FileDialog 的 getDirectory() 和 getFile() 方法的结果。 返回值: Image 对象,切记要检查 (Image)null !!!! */ public Image loadbitmap (String sdir, String sfile) { Image image; System.out.println("loading:"+sdir+sfile); try { FileInputStream fs=new FileInputStream(sdir+sfile); int bflen=14; // 14 字节 BITMAPFILEHEADER byte bf[]=new byte[bflen]; fs.read(bf,0,bflen); int bilen=40; // 40 字节 BITMAPINFOHEADER byte bi[]=new byte[bilen]; fs.read(bi,0,bilen); // 解释数据。 int nsize = (((int)bf[5]&0xff)<<24) | (((int)bf[4]&0xff)<<16) | (((int)bf[3]&0xff)<<8) | (int)bf[2]&0xff; System.out.println("File type is :"+(char)bf[0]+(char)bf[1]); System.out.println("Size of file is :"+nsize); int nbisize = (((int)bi[3]&0xff)<<24) | (((int)bi[2]&0xff)<<16) | (((int)bi[1]&0xff)<<8) | (int)bi[0]&0xff; System.out.println("Size of bitmapinfoheader is :"+nbisize); int nwidth = (((int)bi[7]&0xff)<<24) | (((int)bi[6]&0xff)<<16) | (((int)bi[5]&0xff)<<8) | (int)bi[4]&0xff; System.out.println("Width is :"+nwidth); int nheight = (((int)bi[11]&0xff)<<24) | (((int)bi[10]&0xff)<<16) | (((int)bi[9]&0xff)<<8) | (int)bi[8]&0xff; System.out.println("Height is :"+nheight); int nplanes = (((int)bi[13]&0xff)<<8) | (int)bi[12]&0xff; System.out.println("Planes is :"+nplanes); int nbitcount = (((int)bi[15]&0xff)<<8) | (int)bi[14]&0xff; System.out.println("BitCount is :"+nbitcount); // 查找表明压缩的非零值 int ncompression = (((int)bi[19])<<24) | (((int)bi[18])<<16) | (((int)bi[17])<<8) | (int)bi[16]; System.out.println("Compression is :"+ncompression); int nsizeimage = (((int)bi[23]&0xff)<<24) | (((int)bi[22]&0xff)<<16) | (((int)bi[21]&0xff)<<8) | (int)bi[20]&0xff; System.out.println("SizeImage is :"+nsizeimage); int nxpm = (((int)bi[27]&0xff)<<24) | (((int)bi[26]&0xff)<<16) | (((int)bi[25]&0xff)<<8) | (int)bi[24]&0xff; System.out.println("X-Pixels per meter is :"+nxpm); int nypm = (((int)bi[31]&0xff)<<24) | (((int)bi[30]&0xff)<<16) | (((int)bi[29]&0xff)<<8) | (int)bi[28]&0xff; System.out.println("Y-Pixels per meter is :"+nypm); int nclrused = (((int)bi[35]&0xff)<<24) | (((int)bi[34]&0xff)<<16) | (((int)bi[33]&0xff)<<8) | (int)bi[32]&0xff; System.out.println("Colors used are :"+nclrused); int nclrimp = (((int)bi[39]&0xff)<<24) | (((int)bi[38]&0xff)<<16) | (((int)bi[37]&0xff)<<8) | (int)bi[36]&0xff; System.out.println("Colors important are :"+nclrimp); if (nbitcount==24) { // 24 位格式不包含调色板数据,但扫描行被补足到 // 4 个字节。 int npad = (nsizeimage / nheight) - nwidth * 3; int ndata[] = new int [nheight * nwidth]; byte brgb[] = new byte [( nwidth + npad) * 3 * nheight]; fs.read (brgb, 0, (nwidth + npad) * 3 * nheight); int nindex = 0; for (int j = 0; j < nheight; j++) { for (int i = 0; i < nwidth; i++) { ndata [nwidth * (nheight - j - 1) + i] = (255&0xff)<<24 | (((int)brgb[nindex+2]&0xff)<<16) | (((int)brgb[nindex+1]&0xff)<<8) | (int)brgb[nindex]&0xff; // System.out.println("Encoded Color at (" +i+","+j+")is:"+nrgb+" (R,G,B)= (" +((int)(brgb[2]) & 0xff)+"," +((int)brgb[1]&0xff)+"," +((int)brgb[0]&0xff)+")"); nindex += 3; } nindex += npad; } image = createImage ( new MemoryImageSource (nwidth, nheight, ndata, 0, nwidth)); } else if (nbitcount == 8) { // 必须确定颜色数。如果 clrsused 参数大于 0, // 则颜色数由它决定。如果它等于 0,则根据 // bitsperpixel 计算颜色数。 int nNumColors = 0; if (nclrused > 0) { nNumColors = nclrused; } else { nNumColors = (1&0xff)<<nbitcount; } System.out.println("The number of Colors is"+nNumColors); // 某些位图不计算 sizeimage 域,请找出 // 这些情况并对它们进行修正。 if (nsizeimage == 0) { nsizeimage = ((((nwidth*nbitcount)+31) & ~31 ) >> 3); nsizeimage *= nheight; System.out.println("nsizeimage (backup) is"+nsizeimage); } // 读取调色板颜色。 int npalette[] = new int [nNumColors]; byte bpalette[] = new byte [nNumColors*4]; fs.read (bpalette, 0, nNumColors*4); int nindex8 = 0; for (int n = 0; n < nNumColors; n++) { npalette[n] = (255&0xff)<<24 | (((int)bpalette[nindex8+2]&0xff)<<16) | (((int)bpalette[nindex8+1]&0xff)<<8) | (int)bpalette[nindex8]&0xff; // System.out.println ("Palette Color "+n +" is:"+npalette[n]+" (res,R,G,B)= (" +((int)(bpalette[nindex8+3]) & 0xff)+"," +((int)(bpalette[nindex8+2]) & 0xff)+"," +((int)bpalette[nindex8+1]&0xff)+"," +((int)bpalette[nindex8]&0xff)+")"); nindex8 += 4; } // 读取图像数据(实际上是调色板的索引) // 扫描行仍被补足到 4 个字节。 int npad8 = (nsizeimage / nheight) - nwidth; System.out.println("nPad is:"+npad8); int ndata8[] = new int [nwidth*nheight]; byte bdata[] = new byte [(nwidth+npad8)*nheight]; fs.read (bdata, 0, (nwidth+npad8)*nheight); nindex8 = 0; for (int j8 = 0; j8 < nheight; j8++) { for (int i8 = 0; i8 < nwidth; i8++) { ndata8 [nwidth*(nheight-j8-1)+i8] = npalette [((int)bdata[nindex8]&0xff)]; nindex8++; } nindex8 += npad8; } image = createImage ( new MemoryImageSource (nwidth, nheight, ndata8, 0, nwidth)); } else { System.out.println ("Not a 24-bit or 8-bit Windows Bitmap, aborting..."); image = (Image)null; } fs.close(); return image; } catch (Exception e) { System.out.println("Caught exception in loadbitmap!"); } return (Image) null; } POI,HSSFPalette的addColor抛出异常,谢谢指导 SAX解析XML时,能用Xpath吗? 在一个类中,怎样获得另外一个类的变量? SWT开发中,如何设置组件背景是透明的? 关于JavaBean概念和用法【菜鸟上路】 这个错误如何解决呢 各位请看我的问题!!!好奇怪 大家来看看这是怎么回事啊? 师傅们,帮我看看这段代码把,我用jb运行时他只向数据库中添加了两条记录。 一个非常典型的乱码问题 JAVA 中往mysql 数据库insert 一条含当前时间的记录应怎么写下面写法错在哪里? 字串转换输出?高手帮忙!!!
InputStream imageIn = new FileInputStream(new File(imageFile));
JPEGImageDecoder decoder = JPEGCodec.createJPEGDecoder(imageIn);
BufferedImage im = decoder.decodeAsBufferedImage();
就是要直接处理bmp文件java中有没有处理bmp格式图形的API啊?
loadbitmap() 方法由 Windows C 代码转换而来。
只能读取未压缩的 24 位和 8 位图像。已在
Windows 95 上用 Microsoft Paint 保存的图像
对它进行了测试。如果图像不是 24 位或 8 位图像,
该程序拒绝进行任何尝试。我猜测如果先用 1100,
然后用 0011 对字节执行掩码操作,则也可将 4 位
图像包括在内。我实际上对这些图像不感兴趣。
如果尝试读取压缩图像,该例程可能失败,并产生
一个 IOException 异常。如果变量 ncompression
不为 0,则表示已经过压缩。 参数:
sdir 和 sfile 是 FileDialog 的
getDirectory() 和 getFile() 方法的结果。 返回值:
Image 对象,切记要检查 (Image)null !!!! */
public Image loadbitmap (String sdir, String sfile)
{
Image image;
System.out.println("loading:"+sdir+sfile);
try
{
FileInputStream fs=new FileInputStream(sdir+sfile);
int bflen=14; // 14 字节 BITMAPFILEHEADER
byte bf[]=new byte[bflen];
fs.read(bf,0,bflen);
int bilen=40; // 40 字节 BITMAPINFOHEADER
byte bi[]=new byte[bilen];
fs.read(bi,0,bilen); // 解释数据。
int nsize = (((int)bf[5]&0xff)<<24)
| (((int)bf[4]&0xff)<<16)
| (((int)bf[3]&0xff)<<8)
| (int)bf[2]&0xff;
System.out.println("File type is :"+(char)bf[0]+(char)bf[1]);
System.out.println("Size of file is :"+nsize); int nbisize = (((int)bi[3]&0xff)<<24)
| (((int)bi[2]&0xff)<<16)
| (((int)bi[1]&0xff)<<8)
| (int)bi[0]&0xff;
System.out.println("Size of bitmapinfoheader is :"+nbisize); int nwidth = (((int)bi[7]&0xff)<<24)
| (((int)bi[6]&0xff)<<16)
| (((int)bi[5]&0xff)<<8)
| (int)bi[4]&0xff;
System.out.println("Width is :"+nwidth); int nheight = (((int)bi[11]&0xff)<<24)
| (((int)bi[10]&0xff)<<16)
| (((int)bi[9]&0xff)<<8)
| (int)bi[8]&0xff;
System.out.println("Height is :"+nheight); int nplanes = (((int)bi[13]&0xff)<<8) | (int)bi[12]&0xff;
System.out.println("Planes is :"+nplanes); int nbitcount = (((int)bi[15]&0xff)<<8) | (int)bi[14]&0xff;
System.out.println("BitCount is :"+nbitcount); // 查找表明压缩的非零值
int ncompression = (((int)bi[19])<<24)
| (((int)bi[18])<<16)
| (((int)bi[17])<<8)
| (int)bi[16];
System.out.println("Compression is :"+ncompression); int nsizeimage = (((int)bi[23]&0xff)<<24)
| (((int)bi[22]&0xff)<<16)
| (((int)bi[21]&0xff)<<8)
| (int)bi[20]&0xff;
System.out.println("SizeImage is :"+nsizeimage); int nxpm = (((int)bi[27]&0xff)<<24)
| (((int)bi[26]&0xff)<<16)
| (((int)bi[25]&0xff)<<8)
| (int)bi[24]&0xff;
System.out.println("X-Pixels per meter is :"+nxpm); int nypm = (((int)bi[31]&0xff)<<24)
| (((int)bi[30]&0xff)<<16)
| (((int)bi[29]&0xff)<<8)
| (int)bi[28]&0xff;
System.out.println("Y-Pixels per meter is :"+nypm); int nclrused = (((int)bi[35]&0xff)<<24)
| (((int)bi[34]&0xff)<<16)
| (((int)bi[33]&0xff)<<8)
| (int)bi[32]&0xff;
System.out.println("Colors used are :"+nclrused); int nclrimp = (((int)bi[39]&0xff)<<24)
| (((int)bi[38]&0xff)<<16)
| (((int)bi[37]&0xff)<<8)
| (int)bi[36]&0xff;
System.out.println("Colors important are :"+nclrimp); if (nbitcount==24)
{
// 24 位格式不包含调色板数据,但扫描行被补足到
// 4 个字节。
int npad = (nsizeimage / nheight) - nwidth * 3;
int ndata[] = new int [nheight * nwidth];
byte brgb[] = new byte [( nwidth + npad) * 3 * nheight];
fs.read (brgb, 0, (nwidth + npad) * 3 * nheight);
int nindex = 0;
for (int j = 0; j < nheight; j++)
{
for (int i = 0; i < nwidth; i++)
{
ndata [nwidth * (nheight - j - 1) + i] =
(255&0xff)<<24
| (((int)brgb[nindex+2]&0xff)<<16)
| (((int)brgb[nindex+1]&0xff)<<8)
| (int)brgb[nindex]&0xff;
// System.out.println("Encoded Color at ("
+i+","+j+")is:"+nrgb+" (R,G,B)= ("
+((int)(brgb[2]) & 0xff)+","
+((int)brgb[1]&0xff)+","
+((int)brgb[0]&0xff)+")");
nindex += 3;
}
nindex += npad;
} image = createImage
( new MemoryImageSource (nwidth, nheight,
ndata, 0, nwidth));
}
else if (nbitcount == 8)
{
// 必须确定颜色数。如果 clrsused 参数大于 0,
// 则颜色数由它决定。如果它等于 0,则根据
// bitsperpixel 计算颜色数。
int nNumColors = 0;
if (nclrused > 0)
{
nNumColors = nclrused;
}
else
{
nNumColors = (1&0xff)<<nbitcount;
}
System.out.println("The number of Colors is"+nNumColors); // 某些位图不计算 sizeimage 域,请找出
// 这些情况并对它们进行修正。
if (nsizeimage == 0)
{
nsizeimage = ((((nwidth*nbitcount)+31) & ~31 ) >> 3);
nsizeimage *= nheight;
System.out.println("nsizeimage (backup) is"+nsizeimage);
} // 读取调色板颜色。
int npalette[] = new int [nNumColors];
byte bpalette[] = new byte [nNumColors*4];
fs.read (bpalette, 0, nNumColors*4);
int nindex8 = 0;
for (int n = 0; n < nNumColors; n++)
{
npalette[n] = (255&0xff)<<24
| (((int)bpalette[nindex8+2]&0xff)<<16)
| (((int)bpalette[nindex8+1]&0xff)<<8)
| (int)bpalette[nindex8]&0xff;
// System.out.println ("Palette Color "+n
+" is:"+npalette[n]+" (res,R,G,B)= ("
+((int)(bpalette[nindex8+3]) & 0xff)+","
+((int)(bpalette[nindex8+2]) & 0xff)+","
+((int)bpalette[nindex8+1]&0xff)+","
+((int)bpalette[nindex8]&0xff)+")");
nindex8 += 4;
} // 读取图像数据(实际上是调色板的索引)
// 扫描行仍被补足到 4 个字节。
int npad8 = (nsizeimage / nheight) - nwidth;
System.out.println("nPad is:"+npad8); int ndata8[] = new int [nwidth*nheight];
byte bdata[] = new byte [(nwidth+npad8)*nheight];
fs.read (bdata, 0, (nwidth+npad8)*nheight);
nindex8 = 0;
for (int j8 = 0; j8 < nheight; j8++)
{
for (int i8 = 0; i8 < nwidth; i8++)
{
ndata8 [nwidth*(nheight-j8-1)+i8] =
npalette [((int)bdata[nindex8]&0xff)];
nindex8++;
}
nindex8 += npad8;
} image = createImage
( new MemoryImageSource (nwidth, nheight,
ndata8, 0, nwidth));
}
else
{
System.out.println ("Not a 24-bit or 8-bit Windows Bitmap, aborting...");
image = (Image)null;
} fs.close();
return image;
}
catch (Exception e)
{
System.out.println("Caught exception in loadbitmap!");
}
return (Image) null;
}