jq怎么点击a等于点击b，a和b有多个

Question

<div class="a">
<ul>
<li class="a1">1</li>
<li class="a3">2</li>
<li class="a9">3</li>
</ul>
</div>
<div class="b">
<ul>
<li class="b1">1</li>
<li class="b3">2</li>
<li class="b9">3</li>
</ul>
</div>点击a1=点击b1  a3=b3 ……请教下JQ要怎么写？

Answer 1

$(".a li").click(function(event){
$(".b li").eq($(this).index()).click();
});

Answer 2

不好意思，我写的不是很对，实际的代码是类似这种<div class="a">
<ul class="a">
<li class="a1">1</li>
<li class="b1">2</li>
</ul>
<ul class="b">
<li class="aa1">1</li>
<li class="bb1">2</li>
</ul>
</div><div class="a">
<ul class="a">
<li class="a3">1</li>
<li class="b3">2</li>
</ul>
<ul class="b">
<li class="aa3">1</li>
<li class="bb3">2</li>
</ul>
</div>a1-aa1  b1-bb1
a3-aa3  b3-bb3

Answer 3

<div class="x">
<ul class="a">
<li class="a1">1</li>
<li class="b1">2</li>
</ul>
<ul class="b">
<li class="aa1">1</li>
<li class="bb1">2</li>
</ul>
</div><div class="x">
<ul class="a">
<li class="a3">1</li>
<li class="b3">2</li>
</ul>
<ul class="b">
<li class="aa3">1</li>
<li class="bb3">2</li>
</ul>
</div>

Answer 4

$("ul.a li").click(function(event){
var s = this.className.replace(/^([a-z])/i,"$1$1");
$("ul.b li."+s).click();
});