removeChild

Question

用addone()动态增加一个回车<br> ,那removeone()方法该如何写，来删除回车符<br>

Answer 1

var newbr = document.createElement("br");
var newinp = document.getElementById("inp_id");
newinp .removeChild(newbr);

Answer 2

var newinp = document.getElementById("inp_id");
var brList = newinp.getElementsByTagName("br");
for(var i=0; i<brList.length; ++i)
  newinp.removeChild(brList[i]);
如果无效的话，就用newinp.childNodes然后一个个判断是否br

Answer 3

 if（newbr ）{
newinp.removeChild（newbr ）；
}

Answer 4

谢过大家， 感谢fosjos

Answer 5

var brList = document.all("inp_id").getElementsByTagName("br");
var brlen = brList.length;
newinp.removeChild(brList[(brlen-1)]);