请教一个从HTML取值的正则

Question

可以的，但必须把你这些HTML代码必须有规律可寻
没有规律就没办法了

Answer 1

有的的节点没有 <a>标签 
那要用不同的方法哟！

Answer 2

每次匹配保存成数组了，没有<a的前两项为0
<div id="con">
<table>
    <tr>
        <td>
            <table >
            </table>
        </td>
        <td>
            <a id="_l" href="http://sites/Person.aspx?accountname=Domain%5CUser">jim Ben</a><span
                class='AAA'>,
                <nobr>USER DESIGNER</nobr>
            </span>
        </td>
    </tr>
 <tr>
        <td>
            <table >
            </table>
        </td>
        <td>
            <a id="_l" href="http://sites/Person.aspx?accountname=Domain%5CUser222">jim Ben222</a><span
                class='AAA'>,
                <nobr>USER DESIGNER222</nobr>
            </span>
        </td>
    </tr>
 <tr>
        <td>
            <table >
            </table>
        </td>
        <td>
            <span
                class='AAA'>,
                <nobr>USER DESIGNER2</nobr>
            </span>
        </td>
    </tr>
</table>
</div>
<script>
var str = document.getElementById('con').innerHTML;
var reg = /<td>(?:<a.+?accountname=(.+?)\">(.+?)<\/a>)?.+?<nobr>(.+?)<\/nobr>.+?<\/td>/gi;
var arr = [], i=0, tem = [];
while(tem = reg.exec(str)){
arr[i++] = [tem[1]?tem[1]:0, tem[2]?tem[2]:0, tem[3]];
}
alert(arr.join('\n'));
</script>

Answer 3

<table>
    <tr>
        <td>
            <table >
            </table>
        </td>
        <td>
            <a id="_l" href="http://sites/Person.aspx?accountname=Domain%5CUser">jim Ben</a><span
                class='AAA'>,
                <nobr>USER DESIGNER</nobr>
            </span>
        </td>
    </tr>
</table>不过不方便分离<a>是否可以直接把<a>当作一部分取出来？arrData[0]="<a id="_l" href="http://sites/Person.aspx?accountname=Domain%5CUser">" 
arrData[1]="jim Ben" 
arrData[2]="USER DESIGNER" 

Answer 4

<table>
    <tr>
        <td>
            <table >
            </table>
        </td>
        <td>
            <a id="_l" href="http://sites/Person.aspx?accountname=Domain%5CUser">jim Ben</a><span
                class='AAA'>,
                <nobr>USER DESIGNER</nobr>
            </span>
        </td>
    </tr>
<tr>
        <td>
            <table >
            </table>
        </td>
        <td>
            <a id="_l" href="http://sites/Person.aspx?accountname=Domain%5CUser1">jim Ben1</a><span
                class='AAA'>
            </span>
        </td>
    </tr>
<tr>
        <td>
            <table >
            </table>
        </td>
        <td>
            <a id="_l" href="http://sites/Person.aspx?accountname=Domain%5CUser2">jim Ben2</a><span
                class='AAA'>
            </span>
        </td>
    </tr>
</table>实际情况是这个样子的还能匹配出来么？

Answer 5

需要不太明确啊， 确定这样格式了？
<div id="con">
<table>
    <tr>
        <td>
            <table >
            </table>
        </td>
        <td>
            <a id="_l" href="http://sites/Person.aspx?accountname=Domain%5CUser">jim Ben</a><span
                class='AAA'>,
                <nobr>USER DESIGNER</nobr>
            </span>
        </td>
    </tr>
<tr>
        <td>
            <table >
            </table>
        </td>
        <td>
            <a id="_l" href="http://sites/Person.aspx?accountname=Domain%5CUser1">jim Ben1</a><span
                class='AAA'>
            </span>
        </td>
    </tr>
<tr>
        <td>
            <table >
            </table>
        </td>
        <td>
            <a id="_l" href="http://sites/Person.aspx?accountname=Domain%5CUser2">jim Ben2</a><span
                class='AAA'>
            </span>
        </td>
    </tr>
</table>
</div>
<script>
    var str = document.getElementById('con').innerHTML;
    var reg = /<td>(?:<a.+?accountname=(.+?)\">(.+?)<\/a>)?.+?(?:<nobr>(.+?)<\/nobr>)?(?=\W*<\/span>).*?<\/td>/gi;
    var arr = [], i=0, tem = [];
    while(tem = reg.exec(str)){
        arr[i++] = [tem[1]?tem[1]:0, tem[2]?tem[2]:0, tem[3]?tem[3]:0];
    }
    alert(arr.join('\n'));
</script>

Answer 6

返回的是这个格式的
arr = [
['Domain%5CUser', 'jim Ben', 'USER DESIGNER'],
['Domain%5CUser1', 'jim Ben1', 0],
['Domain%5CUser2', 'jim Ben2', 0]
]