Struts+Hibernate+Spring 配置问题

Question

新公司要求写一个Struts+Hibernate+Spring的例子,小弟搞了半天还是有问题,求助大家帮忙解决,问题如下:
环境:JDK1.5+Eclipse3.2+MyEclipse5.0+Tomcat5.5+SQL 2000
struts-config.xml内容:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE struts-config PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 1.2//EN" "http://struts.apache.org/dtds/struts-config_1_2.dtd"><struts-config>
  <data-sources />
  <form-beans >
    <form-bean name="userRegisterForm" type="test.struts.user.form.UserRegisterForm" />  </form-beans>  <global-exceptions />
  <global-forwards />
  <action-mappings >
    <action
      attribute="userRegisterForm"
      input="/userRegister.jsp"
      name="userRegisterForm"
      path="/userRegister"
      scope="request"
      type="org.springframework.web.struts.DelegatingActionProxy">
      <forward name="success" path="/success.jsp" />
      <forward name="fail" path="/fail.jsp" />
    </action>  </action-mappings>  <message-resources parameter="test.struts.ApplicationResources" />
  <plug-in className="org.springframework.web.struts.ContextLoaderPlugIn">
   <set-property property="contextConfigLocation" value="/WEB-INF/classes/applicationContext.xml"/>
  </plug-in>
</struts-config>applicationContext.xml内容:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE beans PUBLIC "-//SPRING//DTD BEAN//EN" "http://www.springframework.org/dtd/spring-beans.dtd"><beans>
<bean id="dataSource"
class="org.apache.commons.dbcp.BasicDataSource">
<property name="driverClassName">
<value>com.microsoft.jdbc.sqlserver.SQLServerDriver</value>
</property>
<property name="url">
<value>jdbc:microsoft:sqlserver://localhost:1433</value>
</property>
<property name="username">
<value>test</value>
</property>
<property name="password">
<value>test</value>
</property>
</bean>
<bean id="sessionFactory"
class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
<property name="configLocation">
<value>classpath:hibernate.cfg.xml</value>
</property>
<property name="dataSource">
  <ref bean="dataSource"></ref>
  </property>
</bean>
<bean id="UserDAO" class="test.hibernate.UserDAO">
<property name="sessionFactory">
<ref bean="sessionFactory" />
</property>
</bean>
<bean name="/userRegister" class="test.struts.user.action.UserRegisterAction">
<property name="userDAO">
<ref bean="UserDAO"/>
</property>
</bean>

</beans>UserDAO内容:
package test.hibernate;
// default packageimport java.util.List;
import org.apache.commons.logging.Log;
import org.apache.commons.logging.LogFactory;
import org.hibernate.LockMode;
import org.springframework.context.ApplicationContext;
import org.springframework.orm.hibernate3.support.HibernateDaoSupport;/**
 * Data access object (DAO) for domain model class User.
 * @see .User
 * @author MyEclipse - Hibernate Tools
 */
public class UserDAO extends HibernateDaoSupport {    private static final Log log = LogFactory.getLog(UserDAO.class); //property constants
public static final String USERNAME = "username";
public static final String PASSWORD = "password";
public static final String EMAIL = "email";
public static final String OTHER = "other"; protected void initDao() {
//do nothing
}
    
    public void save(User transientInstance) {
        log.debug("saving User instance");
        try {
            getHibernateTemplate().save(transientInstance);
            log.debug("save successful");
        } catch (RuntimeException re) {
            log.error("save failed", re);
            throw re;
        }
    }
}UserRegisterAction.java内容:
/*
 * Generated by MyEclipse Struts
 * Template path: templates/java/JavaClass.vtl
 */
package test.struts.user.action;import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.struts.action.Action;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;import test.hibernate.User;
import test.hibernate.UserDAO;
import test.struts.user.form.UserRegisterForm;/** 
 * MyEclipse Struts
 * Creation date: 09-17-2007
 * 
 * XDoclet definition:
 * @struts.action path="/userRegister" name="userRegisterForm" input="/userRegister.jsp" scope="request" validate="true"
 */
public class UserRegisterAction extends Action {
/*
 * Generated Methods
 */ /** 
 * Method execute
 * @param mapping
 * @param form
 * @param request
 * @param response
 * @return ActionForward
 */
public ActionForward execute(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response) {
UserRegisterForm userRegisterForm = (UserRegisterForm) form;
try{
UserDAO userDAO = new UserDAO();
User u =new User();
u.setUsername(userRegisterForm.getUsername());
u.setPassword(userRegisterForm.getPassword());
u.setEmail(userRegisterForm.getEmail());
u.setOther(userRegisterForm.getOther());

userDAO.save(u);
return mapping.findForward("success");

}catch(Exception e){
e.printStackTrace();
return mapping.findForward("fail");
} }

private UserDAO userDAO;

public void setUserDAO(UserDAO userDAO){
this.userDAO = userDAO;
}
}问题: java.lang.NullPointerException
at test.hibernate.UserDAO.save(UserDAO.java:33)
at test.struts.user.action.UserRegisterAction.execute(UserRegisterAction.java:49)
at org.springframework.web.struts.DelegatingActionProxy.execute(DelegatingActionProxy.java:106)
at org.apache.struts.action.RequestProcessor.processActionPerform(RequestProcessor.java:419)
at org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:224)
at org.apache.struts.action.ActionServlet.process(ActionServlet.java:1194)
at org.apache.struts.action.ActionServlet.doPost(ActionServlet.java:432)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:710)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:269)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:213)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:174)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:117)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:108)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:151)
at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:874)
at org.apache.coyote.http11.Http11BaseProtocol$Http11ConnectionHandler.processConnection(Http11BaseProtocol.java:665)
at org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:528)
at org.apache.tomcat.util.net.LeaderFollowerWorkerThread.runIt(LeaderFollowerWorkerThread.java:81)
at org.apache.tomcat.util.threads.ThreadPool$ControlRunnable.run(ThreadPool.java:689)
at java.lang.Thread.run(Thread.java:595)先谢谢大家了!

Answer 1

...
getUserDao方法好象没有.
UserDAO userDAO = new UserDAO();这都可以不要吧

Answer 2

真是马虎啊!
UserDAO userDAO = new UserDAO();就是这句话出问题了!
多谢上面的大哥了!
getUserDao方法不用.

Answer 3

呵呵~~,因为我一般都直接自动生成set和get方法.

Answer 4

UserDAO userDAO = new UserDAO();根本就是多余,
<bean name="/userRegister" class="test.struts.user.action.UserRegisterAction">
<property name="userDAO">
<ref bean="UserDAO"/>
</property>
</bean>
spring自动注入了