待高手解答:xml嵌入jsp页面的问题!!!!!!!!!! 我把xml嵌入jsp循环产生一条一条的超链,但超链地址都一样,怎样才能从xml中读出超链地址,并循环放到“href”中???请高手指教!! 解决方案 » 免费领取超大流量手机卡,每月29元包185G流量+100分钟通话, 中国电信官方发货 你的JSP页面实际就是个XML对把。不管你怎么做方法都很多啊,最简单用XSL做就是了。比如xml文件<root><child>http://xxx</child><child>http://xxx</child></root>xsl文件中只要有<xsl:for-each select="/root/child"><xsl:value-of select="child"/></xsl:for-each>当然在XML文件头上要加<?xml-stylesheet type='text/xsl' href='XSL文件路径'?>会写就看这个页面的源文件。 <?xml version="1.0" encoding="GB2312"?><?xml-stylesheet type='text/xsl' href='/expert/Xsl/2.xsl'?><Topic> <Issue> <PostUserNickName></PostUserNickName> <rank>一级(初级)</rank> <ranknum>user1</ranknum> <credit> 100</credit> <TopicId> 5204193</TopicId> <TopicName>待高手解答:xml嵌入jsp页面的问题!!!!!!!!!!</TopicName> <PostUserId>1530166</PostUserId> <PostUserName>ran_ran</PostUserName> <RoomName>Java Web 开发</RoomName> <ReplyNum>1</ReplyNum> <PostDateTime>2006-12-04 10:17:01</PostDateTime> <Point>100</Point> <ReadNum>0</ReadNum> <RoomId>5409</RoomId> <EndState>0</EndState> <Content>我把xml嵌入jsp循环产生一条一条的超链,但超链地址都一样,怎样才能从xml中读出超链地址,并循环放到“href”中???请高手指教!!</Content> </Issue> <Replys> <Reply><PostUserNickName>旅行中の狗</PostUserNickName><rank>一级(初级)</rank><ranknum>user1</ranknum><credit>100</credit><ReplyID>38185010</ReplyID><TopicID>5204193</TopicID><PostUserId>1078375</PostUserId><PostUserName>bbqqfdl</PostUserName><Point>0</Point><Content>你的JSP页面实际就是个XML对把。不管你怎么做方法都很多啊,最简单用XSL做就是了。比如xml文件<root><child>http://xxx</child><child>http://xxx</child></root>xsl文件中只要有<xsl:for-each select="/root/child"><xsl:value-of select="child"/></xsl:for-each>当然在XML文件头上要加<?xml-stylesheet type='text/xsl' href='XSL文件路径'?>会写就看这个页面的源文件。</Content><PostDateTime>2006-12-04 12:41:32</PostDateTime></Reply></Replys></Topic> 用<xsl>解析xml....................................在JSP里:<xml id="stylesheet_local"><xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:template match="/root"> <table border="1" style="border-collapse: collapse" width="100%"> <tr height="25"> <td align="center" bgcolor="#FFCC99" nowrap="true">ID</td> <td align="center" bgcolor="#FFCC99" nowrap="true">姓名</td> </tr> <xsl:for-each select="./row"> <tr> <td align="center"> <xsl:value-of select="./@recordId" /> </td> <td align="center"> <xsl:value-of select="./@personName" /> </td> <td align="center"> <xsl:choose> <xsl:when test="./@diNumber = ''"> 未知 </xsl:when> <xsl:otherwise> <a target="_blank"> <xsl:attribute name="href"> WorkCenter/Customer.jsp?dialNumber=<xsl:value-of select="./@diNumber" />&areaNumber=<xsl:value-of select="./@arNumber" />&phoneNumber=<xsl:value-of select="./@phNumber" /> </xsl:attribute> <xsl:value-of select="./@diNumber" /> </a> </xsl:otherwise> </xsl:choose> </td> </tr> </xsl:for-each> </table> </xsl:template></xsl:stylesheet></xml><div id="display" align="center"></div>..................................<script language="javaScript"> /* ********** 加载已经导出的XML文件 *******/ var xml = new ActiveXObject("Microsoft.XMLDOM"); xml.async = false; xml.load("/dd/Report1.xml"); window.display.innerHTML = xml.transformNode(stylesheet_local);</script> <xml id="stylesheet_local"><xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:template match="/root"> <table border="1" style="border-collapse: collapse" width="100%"> <tr height="25"> <td align="center" bgcolor="#FFCC99" nowrap="true">ID</td> <td align="center" bgcolor="#FFCC99" nowrap="true">姓名</td> </tr> <xsl:for-each select="./row"> <tr> <td align="center"> <xsl:value-of select="./@recordId" /> </td> <td align="center"> <xsl:value-of select="./@personName" /> </td> <td align="center"> <xsl:choose> <xsl:when test="./@diNumber = ''"> 未知 </xsl:when> <xsl:otherwise> <a target="_blank"> <xsl:attribute name="href"> WorkCenter/Customer.jsp?dialNumber=<xsl:value-of select="./@diNumber" />&areaNumber=<xsl:value-of select="./@arNumber" />&phoneNumber=<xsl:value-of select="./@phNumber" /> </xsl:attribute> <xsl:value-of select="./@diNumber" /> </a> </xsl:otherwise> </xsl:choose> </td> </tr> </xsl:for-each> </table> </xsl:template></xsl:stylesheet></xml><div id="display" align="center"></div> 如何将这些xml代码放到一个jsp或html的table中?<?xml version="1.0" encoding="UTF-8"?><down> <down_id id="8"> <down_name_address> <a id="0" href="ftp://localhost/down/bianchengkaifa/93470.gif">93470.gif </a> </down_name_address> </down_id> <down_id id="7"> <down_name_address> <a id="1" href="ftp://localhost/down/bianchengkaifa/书城1.rar">书城1.rar </a> </down_name_address> </down_id> <down_id id="6"> <down_name_address> <a id="2" href="ftp://localhost/down/bianchengkaifa/计时器.exe">计时器.exe </a> </down_name_address> </down_id> <down_id id="5"> <down_name_address> <a id="3" href="ftp://localhost/down/bianchengkaifa/书城1.rar">书城1.rar </a> </down_name_address> </down_id></down> 你的例子太繁琐了,请结合和我的例子讲讲,谢谢!何别要指出的我的问题是:我已经将xml文件中的内容读到页面中,但超链不能用,请帮帮忙!!谢谢了 我真的不知 <down_id id="8"> <down_name_address> <a id="0" href="ftp://localhost/down/bianchengkaifa/93470.gif">93470.gif </a> </down_name_address> </down_id>也可以解析出来的?? 如果有高手我倒是看看.别人也是这样提这样的问题的,你可以看一下。http://bbs.w3china.org/dispbbs.asp?boardid=1&id=13369 <down_id id="8"> <down_name_address> <a id="0" href="ftp://localhost/down/bianchengkaifa/93470.gif">93470.gif </a> </down_name_address> </down_id>中的<a id="0" href="ftp://localhost/down/bianchengkaifa/93470.gif">93470.gif </a>在页面解析出来还是<a id="0" href="ftp://localhost/down/bianchengkaifa/93470.gif">93470.gif </a>我想让它形成超链怎么办呢? <down_id id="8"> <down_name_address> <url>93470.gif<upl> </down_name_address></down_id>再用xsl解析, 自已试试看,再参考例子...........<a target="_blank"><xsl:attribute name="href">ftp://localhost/down/bianchengkaifa/<xsl:value-of select="./@url" /></xsl:attribute></a>........... 我做出来了,用了SQL for xml的格式,我不用FTP,直接连接的,如果不合你的意你可以改一下。test.xml:<?xml version="1.0" encoding="gb2312" ?><root xmlns:sql="urn:schemas-microsoft-com:xml-sql"><down_id id="8" url="93470.gif"/><down_id id="7" url="书城1.rar"/><down_id id="6" url="计时器.exe"/><down_id id="5" url="书城1.rar"/></root>test.jsp<%@page contentType="text/html;charset=gb2312" %><%@page language="java" %><%@page import="java.util.*"%><form name="thisForm" method="post" onSubmit="submitIt();return false;"> <OBJECT id="WebBrowser" classid="CLSID:8856F961-340A-11D0-A96B-00C04FD705A2" height="0" width="0"></OBJECT><form name="thisForm" method="post" onSubmit="submitIt();return false;"> <OBJECT id="WebBrowser" classid="CLSID:8856F961-340A-11D0-A96B-00C04FD705A2" height="0" width="0"></OBJECT> <table border="0" cellpadding="0" cellspacing="0" width="100%" > <tr> <td width="100%" nowrap> <input type="button" name="submitIt2" value=" 查询 " onClick="submitIt();"> </td> </tr> </table></form> <XML id='stylesheet_local'> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" xmlns:myxsl="http://www.test.com" version="1.0"> <xsl:template match="/root"> <table border="1" style="border-collapse: collapse" width="100%"> <tr height="25"> <td align="center" bgcolor="#FFCC99" nowrap="true">ID</td> <td align="center" bgcolor="#FFCC99" nowrap="true">URL</td> </tr> <xsl:for-each select="./down_id"> <tr> <td align="center"> <xsl:value-of select="./@id" /> </td> <td align="center"> <xsl:choose> <xsl:when test="./@url = ''"> 未知 </xsl:when> <xsl:otherwise> <a target="_blank"> <xsl:attribute name="href"> /down/bianchengkaifa/xml/<xsl:value-of select="./@url" /> </xsl:attribute> <xsl:value-of select="./@url" /> </a> </xsl:otherwise> </xsl:choose> </td> </tr> </xsl:for-each> </table> </xsl:template> </xsl:stylesheet></XML><!-- 定义一个层 --><div id="displayArea"></div> <script language="javaScript"> function submitIt() { var xml = new ActiveXObject("Microsoft.XMLDOM"); xml.async = false; xml.load("/down/bianchengkaifa/xml/test.xml"); window.displayArea.innerHTML = xml.transformNode(stylesheet_local); }</script> 感谢 jackson416 你将得到问题分数100点!谢谢 java jsp点击次数和回复数量进行统计。这个点击次数和回复数怎么实现 Web布局 IE8正常,IE7和开启兼容模式的IE8Web布局出问题 当用hibernate从sql server 取大数据时报错 hibernate 映射问题! tomcat出错: Unexpected end of file from server jdbc驱动连接mysql的问题 weblogic的redeploy问题 求用java做的视频播放的小demo jetty9怎么编译 jsp文件啊!求大神罩 我要走了 大家都来看看!~~提个小问题! 奇菜的问题:如何用jsp实现把一文件传入制定的目录?
比如xml文件<root><child>http://xxx</child><child>http://xxx</child></root>
xsl文件中只要有<xsl:for-each select="/root/child"><xsl:value-of select="child"/></xsl:for-each>
当然在XML文件头上要加<?xml-stylesheet type='text/xsl' href='XSL文件路径'?>
会写就看这个页面的源文件。
<?xml-stylesheet type='text/xsl' href='/expert/Xsl/2.xsl'?>
<Topic>
<Issue>
<PostUserNickName></PostUserNickName>
<rank>一级(初级)</rank>
<ranknum>user1</ranknum>
<credit> 100</credit>
<TopicId> 5204193</TopicId>
<TopicName>待高手解答:xml嵌入jsp页面的问题!!!!!!!!!!</TopicName>
<PostUserId>1530166</PostUserId>
<PostUserName>ran_ran</PostUserName>
<RoomName>Java Web 开发</RoomName>
<ReplyNum>1</ReplyNum>
<PostDateTime>2006-12-04 10:17:01</PostDateTime>
<Point>100</Point>
<ReadNum>0</ReadNum>
<RoomId>5409</RoomId>
<EndState>0</EndState>
<Content>我把xml嵌入jsp循环产生一条一条的超链,但超链地址都一样,怎样才能从xml中读出超链地址,并循环放到“href”中???
请高手指教!!
</Content>
</Issue>
<Replys>
<Reply><PostUserNickName>旅行中の狗</PostUserNickName><rank>一级(初级)</rank><ranknum>user1</ranknum><credit>100</credit><ReplyID>38185010</ReplyID><TopicID>5204193</TopicID><PostUserId>1078375</PostUserId><PostUserName>bbqqfdl</PostUserName><Point>0</Point><Content>你的JSP页面实际就是个XML对把。不管你怎么做方法都很多啊,最简单用XSL做就是了。
比如xml文件<root><child>http://xxx</child><child>http://xxx</child></root>
xsl文件中只要有<xsl:for-each select="/root/child"><xsl:value-of select="child"/></xsl:for-each>
当然在XML文件头上要加<?xml-stylesheet type='text/xsl' href='XSL文件路径'?>
会写就看这个页面的源文件。</Content><PostDateTime>2006-12-04 12:41:32</PostDateTime></Reply></Replys>
</Topic>
....................................在JSP里:
<xml id="stylesheet_local">
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="/root">
<table border="1" style="border-collapse: collapse" width="100%">
<tr height="25">
<td align="center" bgcolor="#FFCC99" nowrap="true">ID</td>
<td align="center" bgcolor="#FFCC99" nowrap="true">姓名</td>
</tr>
<xsl:for-each select="./row">
<tr>
<td align="center"> <xsl:value-of select="./@recordId" /> </td>
<td align="center"> <xsl:value-of select="./@personName" /> </td>
<td align="center">
<xsl:choose>
<xsl:when test="./@diNumber = ''">
未知
</xsl:when>
<xsl:otherwise>
<a target="_blank">
<xsl:attribute name="href">
WorkCenter/Customer.jsp?dialNumber=<xsl:value-of select="./@diNumber" />&areaNumber=<xsl:value-of select="./@arNumber" />&phoneNumber=<xsl:value-of select="./@phNumber" />
</xsl:attribute>
<xsl:value-of select="./@diNumber" /> </a>
</xsl:otherwise>
</xsl:choose>
</td>
</tr>
</xsl:for-each>
</table>
</xsl:template>
</xsl:stylesheet>
</xml><div id="display" align="center"></div>
..................................<script language="javaScript">
/* ********** 加载已经导出的XML文件 *******/
var xml = new ActiveXObject("Microsoft.XMLDOM");
xml.async = false;
xml.load("/dd/Report1.xml");
window.display.innerHTML = xml.transformNode(stylesheet_local);</script>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="/root">
<table border="1" style="border-collapse: collapse" width="100%">
<tr height="25">
<td align="center" bgcolor="#FFCC99" nowrap="true">ID</td>
<td align="center" bgcolor="#FFCC99" nowrap="true">姓名</td>
</tr>
<xsl:for-each select="./row">
<tr>
<td align="center"> <xsl:value-of select="./@recordId" /> </td>
<td align="center"> <xsl:value-of select="./@personName" /> </td>
<td align="center">
<xsl:choose>
<xsl:when test="./@diNumber = ''">
未知
</xsl:when>
<xsl:otherwise>
<a target="_blank">
<xsl:attribute name="href">
WorkCenter/Customer.jsp?dialNumber=<xsl:value-of select="./@diNumber" />&areaNumber=<xsl:value-of select="./@arNumber" />&phoneNumber=<xsl:value-of select="./@phNumber" />
</xsl:attribute>
<xsl:value-of select="./@diNumber" /> </a>
</xsl:otherwise>
</xsl:choose>
</td>
</tr>
</xsl:for-each>
</table>
</xsl:template>
</xsl:stylesheet>
</xml><div id="display" align="center"></div>
<?xml version="1.0" encoding="UTF-8"?>
<down>
<down_id id="8">
<down_name_address>
<a id="0" href="ftp://localhost/down/bianchengkaifa/93470.gif">93470.gif </a>
</down_name_address>
</down_id>
<down_id id="7">
<down_name_address>
<a id="1" href="ftp://localhost/down/bianchengkaifa/书城1.rar">书城1.rar </a>
</down_name_address>
</down_id>
<down_id id="6">
<down_name_address>
<a id="2" href="ftp://localhost/down/bianchengkaifa/计时器.exe">计时器.exe </a>
</down_name_address>
</down_id>
<down_id id="5">
<down_name_address>
<a id="3" href="ftp://localhost/down/bianchengkaifa/书城1.rar">书城1.rar </a>
</down_name_address>
</down_id>
</down>
何别要指出的我的问题是:我已经将xml文件中的内容读到页面中,但超链不能用,请帮帮忙!!
谢谢了
<down_id id="8">
<down_name_address>
<a id="0" href="ftp://localhost/down/bianchengkaifa/93470.gif">93470.gif </a>
</down_name_address>
</down_id>
也可以解析出来的?? 如果有高手我倒是看看.别人也是这样提这样的问题的,你可以看一下。
http://bbs.w3china.org/dispbbs.asp?boardid=1&id=13369
<down_name_address>
<a id="0" href="ftp://localhost/down/bianchengkaifa/93470.gif">93470.gif </a>
</down_name_address>
</down_id>
中的
<a id="0" href="ftp://localhost/down/bianchengkaifa/93470.gif">93470.gif </a>
在页面解析出来还是
<a id="0" href="ftp://localhost/down/bianchengkaifa/93470.gif">93470.gif </a>
我想让它形成超链
怎么办呢?
<down_name_address>
<url>93470.gif<upl>
</down_name_address>
</down_id>再用xsl解析, 自已试试看,再参考例子
...........
<a target="_blank">
<xsl:attribute name="href">ftp://localhost/down/bianchengkaifa/<xsl:value-of select="./@url" /></xsl:attribute>
</a>
...........
<?xml version="1.0" encoding="gb2312" ?>
<root xmlns:sql="urn:schemas-microsoft-com:xml-sql">
<down_id id="8" url="93470.gif"/><down_id id="7" url="书城1.rar"/><down_id id="6" url="计时器.exe"/><down_id id="5" url="书城1.rar"/>
</root>test.jsp<%@page contentType="text/html;charset=gb2312" %>
<%@page language="java" %>
<%@page import="java.util.*"%><form name="thisForm" method="post" onSubmit="submitIt();return false;">
<OBJECT id="WebBrowser" classid="CLSID:8856F961-340A-11D0-A96B-00C04FD705A2" height="0" width="0"></OBJECT><form name="thisForm" method="post" onSubmit="submitIt();return false;">
<OBJECT id="WebBrowser" classid="CLSID:8856F961-340A-11D0-A96B-00C04FD705A2" height="0" width="0"></OBJECT> <table border="0" cellpadding="0" cellspacing="0" width="100%" >
<tr>
<td width="100%" nowrap>
<input type="button" name="submitIt2" value=" 查询 " onClick="submitIt();">
</td>
</tr>
</table>
</form>
<XML id='stylesheet_local'>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" xmlns:myxsl="http://www.test.com" version="1.0">
<xsl:template match="/root">
<table border="1" style="border-collapse: collapse" width="100%">
<tr height="25">
<td align="center" bgcolor="#FFCC99" nowrap="true">ID</td>
<td align="center" bgcolor="#FFCC99" nowrap="true">URL</td>
</tr>
<xsl:for-each select="./down_id">
<tr>
<td align="center"> <xsl:value-of select="./@id" /> </td>
<td align="center">
<xsl:choose>
<xsl:when test="./@url = ''">
未知
</xsl:when>
<xsl:otherwise>
<a target="_blank">
<xsl:attribute name="href">
/down/bianchengkaifa/xml/<xsl:value-of select="./@url" />
</xsl:attribute>
<xsl:value-of select="./@url" />
</a>
</xsl:otherwise>
</xsl:choose>
</td>
</tr>
</xsl:for-each>
</table>
</xsl:template>
</xsl:stylesheet>
</XML>
<!-- 定义一个层 -->
<div id="displayArea"></div> <script language="javaScript">
function submitIt()
{
var xml = new ActiveXObject("Microsoft.XMLDOM");
xml.async = false;
xml.load("/down/bianchengkaifa/xml/test.xml");
window.displayArea.innerHTML = xml.transformNode(stylesheet_local);
}
</script>