郁闷的很用Tomcat怎么就发布不了呢

Question

  Java文件如下：package ch17.servlet;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.Servlet;
import javax.servlet.ServletConfig;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
public class HelloServlet {
private ServletConfig config;
public void destroy(){}
public ServletConfig getServletConfig(){
return config;
}
public String getServletInfo(){
return "Info:HelloServlet";
}
public void init(ServletConfig config) throws ServletException{
this.config=config;
}
public void service(ServletRequest req,ServletResponse res) throws ServletException,IOException{
PrintWriter out=res.getWriter();
out.println("Hello Servlet");
out.close();
}
}
编译后存放的目录为：
D:\Tomcat6\webapps\ch17\servlet\WEB-INF\classes\HelloServlet.class
----------------------------------------------------------------------------------
webxml文件如下
<?xml version="1.0"  encoding="UTF-8"?>
<web-app  version="2.5"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee"
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd><servlet>
   <servlet-name>HelloServlet</servlet-name>
   <servlet-class>ch17.servlet.HelloServlet</servlet-class>
</servlet>
<servlet-mapping>
   <servlet-name>HelloServlet</servelt-name>
   <url-pattern>/Hello</url-pattern>
</servlet-mapping>
</web-app>存放在
D:\Tomcat6\webapps\ch17\servlet\WEB-INF\web.xml
D:\Tomcat6\webapps\ch17\servlet\src\HelloServlet.java
-----------------------------------------------------------------
通过
http://localhost/ch17/servlet/Hello 怎么访问不了呢？（我用的80端口）
提示：HTTP Status 404 - /ch17/servlet/Hello
最近在学WEB，被这个问题一直迷糊的，搜了很多方法就是找不到为什么？

Answer 1

<url-pattern>/Hello</url-pattern>
直接写http://localhost/ch17/Hello
访问路径跟url-parrern一致

Answer 2

package test;import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletConfig;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
import javax.servlet.http.HttpServlet;
public class HelloServlet extends HttpServlet{
private static final long serialVersionUID = 1L;
private ServletConfig config; public void destroy() {
} public ServletConfig getServletConfig() {
return config;
} public String getServletInfo() {
return "Info:HelloServlet";
} public void init(ServletConfig config) throws ServletException {
this.config = config;
} public void service(ServletRequest req, ServletResponse res)
throws ServletException, IOException {
PrintWriter out = res.getWriter();
out.println("Hello Servlet");
out.close();
}
}
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" 
xmlns="http://java.sun.com/xml/ns/javaee" 
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">

  <servlet>
    <description>DepthPoiService 2010-06-11 world cup</description>
    <display-name>CsdnWeb</display-name>
    <servlet-name>HelloServlet</servlet-name>
    <servlet-class>test.HelloServlet</servlet-class>
  </servlet>  <servlet-mapping>
    <servlet-name>HelloServlet</servlet-name>
    <url-pattern>/HelloServlet</url-pattern>
  </servlet-mapping>
  <welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
  </welcome-file-list>
</web-app>

Answer 3

恩……---
并且由于你映射了访问路径为<url-pattern>/Hello</url-pattern>
所以要写http://localhost /ch17/Hello
//访问路径跟url-parrern一致