关于tomcat,部署servlet的问题

Question

小弟的web.xml内容如下
<?xml version="1.0" encoding="ISO-8859-1" ?><!DOCTYPE web-app
    PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.2//EN"
    "http://java.sun.com/j2ee/dtds/web-app_2_2.dtd"><web-app> <servlet>
<servlet-name>chatAdmin</servlet-name>
<servlet-class>baChatAdminServlet</servlet-class>
</servlet>         <context-param>
      <param-name>ADMIN_PATH</param-name>
               <param-value>/chat/servlet/chatAdmin</param-value>
</context-param></web-app>
那位知道为什么启动时总是提示，The content of element type "web-app" must match "(icon?,display-name?,description?,distributable?,context-param*,servlet*,servlet-mapping*,session-config?,mime-mapping*,welcome-file-list?,error-page*,taglib*,resource-ref*,security-constraint*,login-config?,security-role*,env-entry*,ejb-ref*)".

Answer 1

<?xml version="1.0" encoding="ISO-8859-1" ?><!DOCTYPE web-app
    PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.2//EN"
    "http://java.sun.com/j2ee/dtds/web-app_2_2.dtd"><web-app>          <context-param>
      <param-name>ADMIN_PATH</param-name>
               <param-value>/chat/servlet/chatAdmin</param-value>
</context-param>
<servlet>
<servlet-name>chatAdmin</servlet-name>
<servlet-class>baChatAdminServlet</servlet-class>
</servlet></web-app>
ｘｍｌ元素的顺序不对