表A
a b c d
张三 100 120 2010-2-1
李四 100 233 2010-2-1
张三 123 123 2010-2-2
王五 736 383 2010-2-1
张三 329 373 2010-2-3
李四 999 251 2010-2-1
王五 736 323 2010-2-3我想按时间排序后,每个人各取2条记录。
就是先distinct一下人名。每个人按时间d排序,top 2
再把所有结果集union一下。请问有别的办法吗
a b c d
张三 100 120 2010-2-1
李四 100 233 2010-2-1
张三 123 123 2010-2-2
王五 736 383 2010-2-1
张三 329 373 2010-2-3
李四 999 251 2010-2-1
王五 736 323 2010-2-3我想按时间排序后,每个人各取2条记录。
就是先distinct一下人名。每个人按时间d排序,top 2
再把所有结果集union一下。请问有别的办法吗
-- Author: flystone
-- Version:V1.001
-- Date:2010-03-04 14:59:54
-------------------------------------- Test Data: tA
If object_id('tA') is not null
Drop table tA
Go
Create table tA(a nvarchar(2),b int,c int,d smalldatetime)
Go
Insert into tA
select '张三',100,120,'2010-2-1' union all
select '李四',100,233,'2010-2-1' union all
select '张三',123,123,'2010-2-2' union all
select '王五',736,383,'2010-2-1' union all
select '张三',329,373,'2010-2-3' union all
select '李四',999,251,'2010-2-1' union all
select '王五',736,323,'2010-2-3'
Go
--Start
Select a.* from tA a,ta b
where a.a = b.a
group by a.a,a.b,a.c,a.d
having sum(case when (a.d < b.d) then 1 else 0 end)< 2
--Result:
/*
a b c d
---- ----------- ----------- ------------------------------------------------------
李四 100 233 2010-02-01 00:00:00
李四 999 251 2010-02-01 00:00:00
王五 736 323 2010-02-03 00:00:00
王五 736 383 2010-02-01 00:00:00
张三 123 123 2010-02-02 00:00:00
张三 329 373 2010-02-03 00:00:00(所影响的行数为 6 行)
*/
--End
select * from [tb] t
where d in (select top 2 d from [tb] where a = t.a order by d)
order by a
(select *,row_number() over(partition by a order by d) as rn from A) AS A
where rn<3
drop table tb
Go
Create table tb([a] nvarchar(2),[b] int,[c] int,[d] Datetime)
Insert tb
select N'张三',100,120,'2010-2-1' union all
select N'李四',100,233,'2010-2-1' union all
select N'张三',123,123,'2010-2-2' union all
select N'王五',736,383,'2010-2-1' union all
select N'张三',329,373,'2010-2-3' union all
select N'李四',999,251,'2010-2-1' union all
select N'王五',736,323,'2010-2-3'
Go
Select * from tb t
where (select count(*) from tb where [a]=t.[a] and [d]>t.[d])<2
order by [a]desc
/*
a b c d
---- ----------- ----------- -----------------------
张三 123 123 2010-02-02 00:00:00.000
张三 329 373 2010-02-03 00:00:00.000
李四 999 251 2010-02-01 00:00:00.000
李四 100 233 2010-02-01 00:00:00.000
王五 736 323 2010-02-03 00:00:00.000
王五 736 383 2010-02-01 00:00:00.000(6 個資料列受到影響)
*/
-- Author: liangCK 小梁
-- Title : 查每个分组前N条记录
-- Date : 2008-11-13 17:19:23
-----------------------------------> 生成测试数据: #T
IF OBJECT_ID('tempdb.dbo.#T') IS NOT NULL DROP TABLE #T
CREATE TABLE #T (ID VARCHAR(3),GID INT,Author VARCHAR(29),Title VARCHAR(39),Date DATETIME)
INSERT INTO #T
SELECT '001',1,'邹建','深入浅出SQLServer2005开发管理与应用实例','2008-05-10' UNION ALL
SELECT '002',1,'胡百敬','SQLServer2005性能调校','2008-03-22' UNION ALL
SELECT '003',1,'格罗夫Groff.J.R.','SQL完全手册','2009-07-01' UNION ALL
SELECT '004',1,'KalenDelaney','SQLServer2005技术内幕存储引擎','2008-08-01' UNION ALL
SELECT '005',2,'Alex.Kriegel.Boris.M.Trukhnov','SQL宝典','2007-10-05' UNION ALL
SELECT '006',2,'飞思科技产品研发中心','SQLServer2000高级管理与开发','2007-09-10' UNION ALL
SELECT '007',2,'胡百敬','SQLServer2005数据库开发详解','2008-06-15' UNION ALL
SELECT '008',3,'陈浩奎','SQLServer2000存储过程与XML编程','2005-09-01' UNION ALL
SELECT '009',3,'赵松涛','SQLServer2005系统管理实录','2008-10-01' UNION ALL
SELECT '010',3,'黄占涛','SQL技术手册','2006-01-01'--SQL查询如下:--按GID分组,查每个分组中Date最新的前2条记录
--1.字段ID唯一时:
SELECT * FROM #T AS T WHERE ID IN(SELECT TOP 2 ID FROM #T WHERE GID=T.GID ORDER BY Date DESC)--2.如果ID不唯一时:
SELECT * FROM #T AS T WHERE 2>(SELECT COUNT(*) FROM #T WHERE GID=T.GID AND Date>T.Date)--SQL Server 2005 使用新方法--3.使用ROW_NUMBER()进行排位分组
SELECT ID,GID,Author,Title,Date
FROM
(
SELECT rid=ROW_NUMBER() OVER(PARTITION BY GID ORDER BY Date DESC),*
FROM #T
) AS T
WHERE rid<=2--4.使用APPLY
SELECT DISTINCT b.*
FROM #T AS a
CROSS APPLY
(
SELECT TOP(2) * FROM #T WHERE a.GID=GID ORDER BY Date DESC
) AS b
--结果
/*ID GID Author Title Date
---- ----------- ----------------------------- --------------------------------------- -----------------------
003 1 格罗夫Groff.J.R. SQL完全手册 2009-07-01 00:00:00.000
004 1 KalenDelaney SQLServer2005技术内幕存储引擎 2008-08-01 00:00:00.000
005 2 Alex.Kriegel.Boris.M.Trukhnov SQL宝典 2007-10-05 00:00:00.000
007 2 胡百敬 SQLServer2005数据库开发详解 2008-06-15 00:00:00.000
009 3 赵松涛 SQLServer2005系统管理实录 2008-10-01 00:00:00.000
010 3 黄占涛 SQL技术手册 2006-01-01 00:00:00.000(6 行受影响)
*/--得到每组前几条数据
--假設每組Col1中, Col3不會重復--建立測試環境
Create Table TEST
(Col1 Varchar(10),
Col2 Varchar(10),
Col3 Int)
--插入數據
Insert TEST Select 'BD1V','Label', 4
Union All Select 'BD1V', 'BATT', 2
Union All Select 'BD1V', 'ODD', 3
Union All Select 'BD1V', 'HDD', 5
Union All Select 'BD1V', 'LCD', 1
Union All Select 'BD1W','HDD', 3
Union All Select 'BD1W','RAM', 8
Union All Select 'BD1W','TP CABLE', 5
Union All Select 'BD1W','LCD', 6
Union All Select 'BD1W','Label', 2
Union All Select 'BL3', 'LCD CABLE', 7
Union All Select 'BL3', 'LABEL', 6
Union All Select 'BL3', 'LCD', 5
Union All Select 'BL3', 'RAM', 1
Union All Select 'BL3D', 'Label', 4
GO
--測試
--方法一:
Select Col1, Col2, Col3 From TEST A
Where (Select Count(*) From TEST Where Col1 = A.Col1 And Col3 > A.Col3) < 3
Order By Col1, Col3 Desc
--方法二:
Select Col1, Col2, Col3 From TEST A
Where Exists (Select Count(*) From TEST Where Col1 = A.Col1 And Col3 > A.Col3 Having Count(*) < 3)
Order By Col1, Col3 Desc
--方法三:
Select Col1, Col2, Col3 From TEST A
Where Col3 In (Select TOP 3 Col3 From TEST Where Col1 = A.Col1 Order By Col3 Desc)
Order By Col1, Col3 Desc
GO
--刪除測試環境
Drop Table TEST
--結果
/*
Col1 Col2 Col3
BD1V HDD 5
BD1V Label 4
BD1V ODD 3
BD1W RAM 8
BD1W LCD 6
BD1W TP CABLE 5
BL3 LCD CABLE 7
BL3 LABEL 6
BL3 LCD 5
BL3D Label 4
*/