index.php跳转到chkadmin.php提示(服务器错误
网站在检索 http://localhost/shop/admin/chkadmin.php 时遇到错误。 该网站可能关闭进行维护或配置不正确。
以下是一些建议:
请稍后重新加载此网页。
HTTP 错误 500(Internal Server Error):服务器尝试执行请求时遇到了意外情况。)index.php代码:<html>
<head>
<title></title>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312">
<link href="../css/font.css" rel="stylesheet">
</head>
<body bgcolor="#FFFFFF" leftmargin="0" topmargin="0" marginwidth="0" marginheight="0">
<p>&nbsp;</p>
<p> 
</p>
<p>&nbsp;</p>
<p>&nbsp;</p>
<p>&nbsp;</p>
<script language="javascript">
  function chkinput(form){
    if(form.name.value==""){
  alert("请输入用户名!");
  form.name.select();
  return(false);
}
if(form.pwd.value==""){
  alert("请输入用户密码!");
  form.pwd.select();
  return(false);
}
return(true);
  }
</script>
<form name="form1" method="post" action="chkadmin.php" onSubmit="return chkinput(this)">
  <table width="545" border="0" align="center" cellpadding="0" cellspacing="0" id="__01">
<tr>
<td height="226" background="images/default_01.gif">&nbsp;</td>
</tr>
<tr>
<td height="45" align="right" background="images/default_02.gif">
<table width="407" border="0" cellspacing="0" cellpadding="0">
          <tr>
            <td width="57" align="center">用户名:</td>
            <td width="94" align="center"><input type="text" name="name" size="14" maxlength="20" class="inputcss"></td>
            <td width="53" align="center">&nbsp;密&nbsp;码:</td>
            <td width="104" align="center"><input type="password" name="pwd" size="14" maxlength="20" class="inputcss"></td>
            <td width="99">&nbsp;
                <input name="imageField" type="image" src="images/default_07.gif" width="74" height="24" border="0"></td>
          </tr>
        </table>
</td>
</tr>
<tr>
<td height="23"  background="images/default_04.gif"></td>
</tr>
</table>
</form>
</body>
</html>chkadmin.php代码
<?php class chkinput
 {
   var $name;
   var $pwd;   function chkinput($x,$y)
    {
     $this->name=$x;
     $this->pwd=$y;
    }  function checkinput()
   {
   
     include("conn/conn.php");
     $sql=mysql_query("select * from tb_admin where name='".$this->name."'",$conn);
     $info=mysql_fetch_array($sql);
     if($info==false)
       {
   echo "hello";
          echo "<script language='javascript'>alert('不存在此管理员!');history.back();</script>";
          exit;
       }
      else
       {
          if($info[pwd]==$this->pwd){
               header("location:default.php");
            }
          else
           {
             echo "<script language='javascript'>alert('密码输入错误!');history.back();</script>";
             exit;
           }      }  
   }
 }
    $obj=new chkinput(trim($_POST[name]),md5(trim($_POST[pwd])));

    $obj->checkinput();

?>初学PHP,请各位帮忙分析下,谢谢!