请教大虾,谁能给我一个32位的md5加密算法

Attribute VB_Name = "mMD5"' MODULE:       CMD5
'*******************************************************************************
Option ExplicitPublic Const BITS_TO_A_BYTE  As Long = 8
Public Const BYTES_TO_A_WORD As Long = 4
Public Const BITS_TO_A_WORD  As Long = BYTES_TO_A_WORD * BITS_TO_A_BYTEPublic m_lOnBits(0 To 30) As Long
Public m_l2Power(0 To 30) As Long'*******************************************************************************
' Class_Initialize (SUB)
'
' DESCRIPTION:
' We will usually get quicker results by preparing arrays of bit patterns and
' powers of 2 ahead of time instead of calculating them every time, unless of
' course the methods are only ever getting called once per instantiation of the
' class.
'*******************************************************************************
Public Sub Initialize()
    ' Could have done this with a loop calculating each value, but simply
    ' assigning the values is quicker - BITS SET FROM RIGHT
    m_lOnBits(0) = 1            ' 00000000000000000000000000000001
    m_lOnBits(1) = 3            ' 00000000000000000000000000000011
    m_lOnBits(2) = 7            ' 00000000000000000000000000000111
    m_lOnBits(3) = 15           ' 00000000000000000000000000001111
    m_lOnBits(4) = 31           ' 00000000000000000000000000011111
    m_lOnBits(5) = 63           ' 00000000000000000000000000111111
    m_lOnBits(6) = 127          ' 00000000000000000000000001111111
    m_lOnBits(7) = 255          ' 00000000000000000000000011111111
    m_lOnBits(8) = 511          ' 00000000000000000000000111111111
    m_lOnBits(9) = 1023         ' 00000000000000000000001111111111
    m_lOnBits(10) = 2047        ' 00000000000000000000011111111111
    m_lOnBits(11) = 4095        ' 00000000000000000000111111111111
    m_lOnBits(12) = 8191        ' 00000000000000000001111111111111
    m_lOnBits(13) = 16383       ' 00000000000000000011111111111111
    m_lOnBits(14) = 32767       ' 00000000000000000111111111111111
    m_lOnBits(15) = 65535       ' 00000000000000001111111111111111
    m_lOnBits(16) = 131071      ' 00000000000000011111111111111111
    m_lOnBits(17) = 262143      ' 00000000000000111111111111111111
    m_lOnBits(18) = 524287      ' 00000000000001111111111111111111
    m_lOnBits(19) = 1048575     ' 00000000000011111111111111111111
    m_lOnBits(20) = 2097151     ' 00000000000111111111111111111111
    m_lOnBits(21) = 4194303     ' 00000000001111111111111111111111
    m_lOnBits(22) = 8388607     ' 00000000011111111111111111111111
    m_lOnBits(23) = 16777215    ' 00000000111111111111111111111111
    m_lOnBits(24) = 33554431    ' 00000001111111111111111111111111
    m_lOnBits(25) = 67108863    ' 00000011111111111111111111111111
    m_lOnBits(26) = 134217727   ' 00000111111111111111111111111111
    m_lOnBits(27) = 268435455   ' 00001111111111111111111111111111
    m_lOnBits(28) = 536870911   ' 00011111111111111111111111111111
    m_lOnBits(29) = 1073741823  ' 00111111111111111111111111111111
    m_lOnBits(30) = 2147483647  ' 01111111111111111111111111111111

    ' Could have done this with a loop calculating each value, but simply
    ' assigning the values is quicker - POWERS OF 2
    m_l2Power(0) = 1            ' 00000000000000000000000000000001
    m_l2Power(1) = 2            ' 00000000000000000000000000000010
    m_l2Power(2) = 4            ' 00000000000000000000000000000100
    m_l2Power(3) = 8            ' 00000000000000000000000000001000
    m_l2Power(4) = 16           ' 00000000000000000000000000010000
    m_l2Power(5) = 32           ' 00000000000000000000000000100000
    m_l2Power(6) = 64           ' 00000000000000000000000001000000
    m_l2Power(7) = 128          ' 00000000000000000000000010000000
    m_l2Power(8) = 256          ' 00000000000000000000000100000000
    m_l2Power(9) = 512          ' 00000000000000000000001000000000
    m_l2Power(10) = 1024        ' 00000000000000000000010000000000
    m_l2Power(11) = 2048        ' 00000000000000000000100000000000
    m_l2Power(12) = 4096        ' 00000000000000000001000000000000
    m_l2Power(13) = 8192        ' 00000000000000000010000000000000
    m_l2Power(14) = 16384       ' 00000000000000000100000000000000
    m_l2Power(15) = 32768       ' 00000000000000001000000000000000
    m_l2Power(16) = 65536       ' 00000000000000010000000000000000
    m_l2Power(17) = 131072      ' 00000000000000100000000000000000
    m_l2Power(18) = 262144      ' 00000000000001000000000000000000
    m_l2Power(19) = 524288      ' 00000000000010000000000000000000
    m_l2Power(20) = 1048576     ' 00000000000100000000000000000000
    m_l2Power(21) = 2097152     ' 00000000001000000000000000000000
    m_l2Power(22) = 4194304     ' 00000000010000000000000000000000
    m_l2Power(23) = 8388608     ' 00000000100000000000000000000000
    m_l2Power(24) = 16777216    ' 00000001000000000000000000000000
    m_l2Power(25) = 33554432    ' 00000010000000000000000000000000
    m_l2Power(26) = 67108864    ' 00000100000000000000000000000000
    m_l2Power(27) = 134217728   ' 00001000000000000000000000000000
    m_l2Power(28) = 268435456   ' 00010000000000000000000000000000
    m_l2Power(29) = 536870912   ' 00100000000000000000000000000000
    m_l2Power(30) = 1073741824  ' 01000000000000000000000000000000
End Sub'*******************************************************************************
' LShift (FUNCTION)
'
' PARAMETERS:
' (In) - lValue     - Long    - The value to be shifted
' (In) - iShiftBits - Integer - The number of bits to shift the value by
'
' RETURN VALUE:
' Long - The shifted long integer
'
' DESCRIPTION:
' A left shift takes all the set binary bits and moves them left, in-filling
' with zeros in the vacated bits on the right. This function is equivalent to
' the << operator in Java and C++
'*******************************************************************************
Private Function LShift(ByVal lValue As Long, _
                        ByVal iShiftBits As Integer) As Long
    ' NOTE: If you can guarantee that the Shift parameter will be in the
    ' range 1 to 30 you can safely strip of this first nested if structure for
    ' speed.
    '
    ' A shift of zero is no shift at all.
    If iShiftBits = 0 Then
        LShift = lValue
        Exit Function

    ' A shift of 31 will result in the right most bit becoming the left most
    ' bit and all other bits being cleared
    ElseIf iShiftBits = 31 Then
        If lValue And 1 Then
            LShift = &H80000000
        Else
            LShift = 0
        End If
        Exit Function

    ' A shift of less than zero or more than 31 is undefined
    ElseIf iShiftBits < 0 Or iShiftBits > 31 Then
        Err.Raise 6
    End If

    ' If the left most bit that remains will end up in the negative bit
    ' position (&H80000000) we would end up with an overflow if we took the
    ' standard route. We need to strip the left most bit and add it back
    ' afterwards.
    If (lValue And m_l2Power(31 - iShiftBits)) Then

        ' (Value And OnBits(31 - (Shift + 1))) chops off the left most bits that
        ' we are shifting into, but also the left most bit we still want as this
        ' is going to end up in the negative bit er position (&H80000000).
        ' After the multiplication/shift we Or the result with &H80000000 to
        ' turn the negative bit on.
        LShift = ((lValue And m_lOnBits(31 - (iShiftBits + 1))) * _
            m_l2Power(iShiftBits)) Or &H80000000

    Else

        ' (Value And OnBits(31-Shift)) chops off the left most bits that we are
        ' shifting into so we do not get an overflow error when we do the
        ' multiplication/shift
        LShift = ((lValue And m_lOnBits(31 - iShiftBits)) * _
            m_l2Power(iShiftBits))

    End If
End Function

'*******************************************************************************
' RShift (FUNCTION)
'
' PARAMETERS:
' (In) - lValue     - Long    - The value to be shifted
' (In) - iShiftBits - Integer - The number of bits to shift the value by
'
' RETURN VALUE:
' Long - The shifted long integer
'
' DESCRIPTION:
' The right shift of an unsigned long integer involves shifting all the set bits
' to the right and in-filling on the left with zeros. This function is
' equivalent to the >>> operator in Java or the >> operator in C++ when used on
' an unsigned long.
'*******************************************************************************
Private Function RShift(ByVal lValue As Long, _
                        ByVal iShiftBits As Integer) As Long

    ' NOTE: If you can guarantee that the Shift parameter will be in the
    ' range 1 to 30 you can safely strip of this first nested if structure for
    ' speed.
    '
    ' A shift of zero is no shift at all
    If iShiftBits = 0 Then
        RShift = lValue
        Exit Function

    ' A shift of 31 will clear all bits and move the left most bit to the right
    ' most bit position
    ElseIf iShiftBits = 31 Then
        If lValue And &H80000000 Then
            RShift = 1
        Else
            RShift = 0
        End If
        Exit Function

    ' A shift of less than zero or more than 31 is undefined
    ElseIf iShiftBits < 0 Or iShiftBits > 31 Then
        Err.Raise 6
    End If

    ' We do not care about the top most bit or the final bit, the top most bit
    ' will be taken into account in the next stage, the final bit (whether it
    ' is an odd number or not) is being shifted into, so we do not give a jot
    ' about it
    RShift = (lValue And &H7FFFFFFE) \ m_l2Power(iShiftBits)

    ' If the top most bit (&H80000000) was set we need to do things differently
    ' as in a normal VB signed long integer the top most bit is used to indicate
    ' the sign of the number, when it is set it is a negative number, so just
    ' deviding by a factor of 2 as above would not work.
    ' NOTE: (lValue And  &H80000000) is equivalent to (lValue < 0), you could
    ' get a very marginal speed improvement by changing the test to (lValue < 0)
    If (lValue And &H80000000) Then
        ' We take the value computed so far, and then add the left most negative
        ' bit after it has been shifted to the right the appropriate number of
        ' places
        RShift = (RShift Or (&H40000000 \ m_l2Power(iShiftBits - 1)))
    End If
End Function'*******************************************************************************
' RShiftSigned (FUNCTION)
'
' PARAMETERS:
' (In) - lValue     - Long    -
' (In) - iShiftBits - Integer -
'
' RETURN VALUE:
' Long -
'
' DESCRIPTION:
' The right shift of a signed long integer involves shifting all the set bits to
' the right and in-filling on the left with the sign bit (0 if positive, 1 if
' negative. This function is equivalent to the >> operator in Java or the >>
' operator in C++ when used on a signed long integer. Not used in this class,
' but included for completeness.
'*******************************************************************************
Private Function RShiftSigned(ByVal lValue As Long, _
                              ByVal iShiftBits As Integer) As Long

    ' NOTE: If you can guarantee that the Shift parameter will be in the
    ' range 1 to 30 you can safely strip of this first nested if structure for
    ' speed.
    '
    ' A shift of zero is no shift at all
    If iShiftBits = 0 Then
        RShiftSigned = lValue
        Exit Function

    ' A shift of 31 will clear all bits if the left most bit was zero, and will
    ' set all bits if the left most bit was 1 (a negative indicator)
    ElseIf iShiftBits = 31 Then

        ' NOTE: (lValue And  &H80000000) is equivalent to (lValue < 0), you
        ' could get a very marginal speed improvement by changing the test to
        ' (lValue < 0)
        If (lValue And &H80000000) Then
            RShiftSigned = -1
        Else
            RShiftSigned = 0
        End If
        Exit Function

    ' A shift of less than zero or more than 31 is undefined
    ElseIf iShiftBits < 0 Or iShiftBits > 31 Then
        Err.Raise 6
    End If

    ' We get the same result by dividing by the appropriate power of 2 and
    ' rounding in the negative direction
    RShiftSigned = Int(lValue / m_l2Power(iShiftBits))
End Function'*******************************************************************************
' RotateLeft (FUNCTION)
'
' PARAMETERS:
' (In) - lValue     - Long    - Value to act on
' (In) - iShiftBits - Integer - Bits to move by
'
' RETURN VALUE:
' Long - Result
'
' DESCRIPTION:
' Rotates the bits in a long integer to the left, those bits falling off the
' left edge are put back on the right edge
'*******************************************************************************
Private Function RotateLeft(ByVal lValue As Long, _
                            ByVal iShiftBits As Integer) As Long
    RotateLeft = LShift(lValue, iShiftBits) Or RShift(lValue, (32 - iShiftBits))
End Function'*******************************************************************************
' AddUnsigned (FUNCTION)
'
' PARAMETERS:
' (In) - lX - Long - First value
' (In) - lY - Long - Second value
'
' RETURN VALUE:
' Long - Result
'
' DESCRIPTION:
' Adds two potentially large unsigned numbers without overflowing
'*******************************************************************************

Private Function AddUnsigned(ByVal lX As Long, _
                             ByVal lY As Long) As Long
    Dim lX4     As Long
    Dim lY4     As Long
    Dim lX8     As Long
    Dim lY8     As Long
    Dim lResult As Long

    lX8 = lX And &H80000000
    lY8 = lY And &H80000000
    lX4 = lX And &H40000000
    lY4 = lY And &H40000000

    lResult = (lX And &H3FFFFFFF) + (lY And &H3FFFFFFF)

    If lX4 And lY4 Then
        lResult = lResult Xor &H80000000 Xor lX8 Xor lY8
    ElseIf lX4 Or lY4 Then
        If lResult And &H40000000 Then
            lResult = lResult Xor &HC0000000 Xor lX8 Xor lY8
        Else
            lResult = lResult Xor &H40000000 Xor lX8 Xor lY8
        End If
    Else
        lResult = lResult Xor lX8 Xor lY8
    End If

    AddUnsigned = lResult
End Function'*******************************************************************************
' F (FUNCTION)
'
' DESCRIPTION:
' MD5's F function
'*******************************************************************************
Private Function F(ByVal x As Long, _
                   ByVal y As Long, _
                   ByVal z As Long) As Long
    F = (x And y) Or ((Not x) And z)
End Function'*******************************************************************************
' G (FUNCTION)
'
' DESCRIPTION:
' MD5's G function
'*******************************************************************************
Private Function G(ByVal x As Long, _
                   ByVal y As Long, _
                   ByVal z As Long) As Long
    G = (x And z) Or (y And (Not z))
End Function'*******************************************************************************
' H (FUNCTION)
'
' DESCRIPTION:
' MD5's H function
'*******************************************************************************
Private Function H(ByVal x As Long, _
                   ByVal y As Long, _
                   ByVal z As Long) As Long
    H = (x Xor y Xor z)
End Function'*******************************************************************************
' I (FUNCTION)
'
' DESCRIPTION:
' MD5's I function
'*******************************************************************************
Private Function I(ByVal x As Long, _
                   ByVal y As Long, _
                   ByVal z As Long) As Long
    I = (y Xor (x Or (Not z)))
End Function'*******************************************************************************
' FF (SUB)
'
' DESCRIPTION:
' MD5's FF procedure
'*******************************************************************************
Private Sub FF(a As Long, _
               ByVal b As Long, _
               ByVal c As Long, _
               ByVal d As Long, _
               ByVal x As Long, _
               ByVal s As Long, _
               ByVal ac As Long)
    a = AddUnsigned(a, AddUnsigned(AddUnsigned(F(b, c, d), x), ac))
    a = RotateLeft(a, s)
    a = AddUnsigned(a, b)
End Sub'*******************************************************************************
' GG (SUB)
'
' DESCRIPTION:
' MD5's GG procedure
'*******************************************************************************
Private Sub GG(a As Long, _
               ByVal b As Long, _
               ByVal c As Long, _
               ByVal d As Long, _
               ByVal x As Long, _
               ByVal s As Long, _
               ByVal ac As Long)
    a = AddUnsigned(a, AddUnsigned(AddUnsigned(G(b, c, d), x), ac))
    a = RotateLeft(a, s)
    a = AddUnsigned(a, b)
End Sub'*******************************************************************************
' HH (SUB)
'
' DESCRIPTION:
' MD5's HH procedure
'*******************************************************************************
Private Sub HH(a As Long, _
               ByVal b As Long, _
               ByVal c As Long, _
               ByVal d As Long, _
               ByVal x As Long, _
               ByVal s As Long, _
               ByVal ac As Long)
    a = AddUnsigned(a, AddUnsigned(AddUnsigned(H(b, c, d), x), ac))
    a = RotateLeft(a, s)
    a = AddUnsigned(a, b)
End Sub'*******************************************************************************
' II (SUB)
'
' DESCRIPTION:
' MD5's II procedure
'*******************************************************************************
Private Sub II(a As Long, _
               ByVal b As Long, _
               ByVal c As Long, _
               ByVal d As Long, _
               ByVal x As Long, _
               ByVal s As Long, _
               ByVal ac As Long)
    a = AddUnsigned(a, AddUnsigned(AddUnsigned(I(b, c, d), x), ac))
    a = RotateLeft(a, s)
    a = AddUnsigned(a, b)
End Sub'*******************************************************************************
' ConvertToWordArray (FUNCTION)
'
' PARAMETERS:
' (In/Out) - sMessage - String - String message
'
' RETURN VALUE:
' Long() - Converted message as long array
'
' DESCRIPTION:
' Takes the string message and puts it in a long array with padding according to
' the MD5 rules. Note we are using only the first byte of each character with
' the AscB function, this may well mess up in unicode/dbcs situations where you
' are comparing what was generated on two different PCs with different
' character sets.
'*******************************************************************************

Private Function ConvertToWordArray(sMessage As String) As Long()
    Dim lMessageLength  As Long
    Dim lNumberOfWords  As Long
    Dim lWordArray()    As Long
    Dim lBytePosition   As Long
    Dim lByteCount      As Long
    Dim lWordCount      As Long
    Dim lChar           As Long

    Const MODULUS_BITS      As Long = 512
    Const CONGRUENT_BITS    As Long = 448

    lMessageLength = Len(sMessage)

    ' Get padded number of words. Message needs to be congruent to 448 bits,
    ' modulo 512 bits. If it is exactly congruent to 448 bits, modulo 512 bits
    ' it must still have another 512 bits added. 512 bits = 64 bytes
    ' (or 16 * 4 byte words), 448 bits = 56 bytes. This means lMessageSize must
    ' be a multiple of 16 (i.e. 16 * 4 (bytes) * 8 (bits))
    lNumberOfWords = (((lMessageLength + _
        ((MODULUS_BITS - CONGRUENT_BITS) \ BITS_TO_A_BYTE)) \ _
        (MODULUS_BITS \ BITS_TO_A_BYTE)) + 1) * _
        (MODULUS_BITS \ BITS_TO_A_WORD)
    ReDim lWordArray(lNumberOfWords - 1)

    ' Combine each block of 4 bytes (ascii code of character) into one long
    ' value and store in the message. The high-order (most significant) bit of
    ' each byte is listed first. However, the low-order (least significant) byte
    ' is given first in each word.
    lBytePosition = 0
    lByteCount = 0
    Do Until lByteCount >= lMessageLength
        ' Each word is 4 bytes
        lWordCount = lByteCount \ BYTES_TO_A_WORD

        ' The bytes are put in the word from the right most edge
        lBytePosition = (lByteCount Mod BYTES_TO_A_WORD) * BITS_TO_A_BYTE
        lChar = AscB(Mid(sMessage, lByteCount + 1, 1))
        lWordArray(lWordCount) = lWordArray(lWordCount) Or LShift(lChar, lBytePosition)
        lByteCount = lByteCount + 1
    Loop    ' Terminate according to MD5 rules with a 1 bit, zeros and the length in
    ' bits stored in the last two words
    lWordCount = lByteCount \ BYTES_TO_A_WORD
    lBytePosition = (lByteCount Mod BYTES_TO_A_WORD) * BITS_TO_A_BYTE    ' Add a terminating 1 bit, all the rest of the bits to the end of the
    ' word array will default to zero
    lWordArray(lWordCount) = lWordArray(lWordCount) Or LShift(&H80, lBytePosition)    ' We put the length of the message in bits into the last two words, to get
    ' the length in bits we need to multiply by 8 (or left shift 3). This left
    ' shifted value is put in the first word. Any bits shifted off the left edge
    ' need to be put in the second word, we can work out which bits by shifting
    ' right the length by 29 bits.
    lWordArray(lNumberOfWords - 2) = LShift(lMessageLength, 3)
    lWordArray(lNumberOfWords - 1) = RShift(lMessageLength, 29)

    ConvertToWordArray = lWordArray
End Function'*******************************************************************************
' WordToHex (FUNCTION)
'
' PARAMETERS:
' (In) - lValue - Long - Long value to convert
'
' RETURN VALUE:
' String - Hex value to return
'
' DESCRIPTION:
' Takes a long integer and due to the bytes reverse order it extracts the
' individual bytes and converts them to hex appending them for an overall hex
' value
'*******************************************************************************
Private Function WordToHex(ByVal lValue As Long) As String
    Dim lByte As Long
    Dim lCount As Long

    For lCount = 0 To 3
        lByte = RShift(lValue, lCount * BITS_TO_A_BYTE) And _
            m_lOnBits(BITS_TO_A_BYTE - 1)
        WordToHex = WordToHex & Right("0" & Hex(lByte), 2)
    Next
End Function'*******************************************************************************
' MD5 (FUNCTION)
'
' PARAMETERS:
' (In/Out) - sMessage - String - String to be digested
'
' RETURN VALUE:
' String - The MD5 digest
'
' DESCRIPTION:
' This function takes a string message and generates an MD5 digest for it.
' sMessage can be up to the VB string length limit of 2^31 (approx. 2 billion)
' characters.
'
' NOTE: Due to the way in which the string is processed the routine assumes a
' single byte character set. VB passes unicode (2-byte) character strings, the
' ConvertToWordArray function uses on the first byte for each character. This
' has been done this way for ease of use, to make the routine truely portable
' you could accept a byte array instead, it would then be up to the calling
' routine to make sure that the byte array is generated from their string in
' a manner consistent with the string type.
'*******************************************************************************

Public Function MD5(sMessage As String) As String
    Dim x() As Long
    Dim k   As Long
    Dim AA  As Long
    Dim BB  As Long
    Dim CC  As Long
    Dim DD  As Long
    Dim a   As Long
    Dim b   As Long
    Dim c   As Long
    Dim d   As Long

    Const S11 As Long = 7
    Const S12 As Long = 12
    Const S13 As Long = 17
    Const S14 As Long = 22
    Const S21 As Long = 5
    Const S22 As Long = 9
    Const S23 As Long = 14
    Const S24 As Long = 20
    Const S31 As Long = 4
    Const S32 As Long = 11
    Const S33 As Long = 16
    Const S34 As Long = 23
    Const S41 As Long = 6
    Const S42 As Long = 10
    Const S43 As Long = 15
    Const S44 As Long = 21    ' Steps 1 and 2.  Append padding bits and length and convert to words
    x = ConvertToWordArray(sMessage)

    ' Step 3.  Initialise
    a = &H67452301
    b = &HEFCDAB89
    c = &H98BADCFE
    d = &H10325476    ' Step 4.  Process the message in 16-word blocks
    For k = 0 To UBound(x) Step 16
        AA = a
        BB = b
        CC = c
        DD = d

        ' The hex number on the end of each of the following procedure calls is
        ' an element from the 64 element table constructed with
        ' T(i) = Int(4294967296 * Abs(Sin(i))) where i is 1 to 64.
        '
        ' However, for speed we don't want to calculate the value every time.
        FF a, b, c, d, x(k + 0), S11, &HD76AA478
        FF d, a, b, c, x(k + 1), S12, &HE8C7B756
        FF c, d, a, b, x(k + 2), S13, &H242070DB
        FF b, c, d, a, x(k + 3), S14, &HC1BDCEEE
        FF a, b, c, d, x(k + 4), S11, &HF57C0FAF
        FF d, a, b, c, x(k + 5), S12, &H4787C62A
        FF c, d, a, b, x(k + 6), S13, &HA8304613
        FF b, c, d, a, x(k + 7), S14, &HFD469501
        FF a, b, c, d, x(k + 8), S11, &H698098D8
        FF d, a, b, c, x(k + 9), S12, &H8B44F7AF
        FF c, d, a, b, x(k + 10), S13, &HFFFF5BB1
        FF b, c, d, a, x(k + 11), S14, &H895CD7BE
        FF a, b, c, d, x(k + 12), S11, &H6B901122
        FF d, a, b, c, x(k + 13), S12, &HFD987193
        FF c, d, a, b, x(k + 14), S13, &HA679438E
        FF b, c, d, a, x(k + 15), S14, &H49B40821

        GG a, b, c, d, x(k + 1), S21, &HF61E2562
        GG d, a, b, c, x(k + 6), S22, &HC040B340
        GG c, d, a, b, x(k + 11), S23, &H265E5A51
        GG b, c, d, a, x(k + 0), S24, &HE9B6C7AA
        GG a, b, c, d, x(k + 5), S21, &HD62F105D
        GG d, a, b, c, x(k + 10), S22, &H2441453
        GG c, d, a, b, x(k + 15), S23, &HD8A1E681
        GG b, c, d, a, x(k + 4), S24, &HE7D3FBC8
        GG a, b, c, d, x(k + 9), S21, &H21E1CDE6
        GG d, a, b, c, x(k + 14), S22, &HC33707D6
        GG c, d, a, b, x(k + 3), S23, &HF4D50D87
        GG b, c, d, a, x(k + 8), S24, &H455A14ED
        GG a, b, c, d, x(k + 13), S21, &HA9E3E905
        GG d, a, b, c, x(k + 2), S22, &HFCEFA3F8
        GG c, d, a, b, x(k + 7), S23, &H676F02D9
        GG b, c, d, a, x(k + 12), S24, &H8D2A4C8A

        HH a, b, c, d, x(k + 5), S31, &HFFFA3942
        HH d, a, b, c, x(k + 8), S32, &H8771F681
        HH c, d, a, b, x(k + 11), S33, &H6D9D6122
        HH b, c, d, a, x(k + 14), S34, &HFDE5380C
        HH a, b, c, d, x(k + 1), S31, &HA4BEEA44
        HH d, a, b, c, x(k + 4), S32, &H4BDECFA9
        HH c, d, a, b, x(k + 7), S33, &HF6BB4B60
        HH b, c, d, a, x(k + 10), S34, &HBEBFBC70
        HH a, b, c, d, x(k + 13), S31, &H289B7EC6
        HH d, a, b, c, x(k + 0), S32, &HEAA127FA
        HH c, d, a, b, x(k + 3), S33, &HD4EF3085
        HH b, c, d, a, x(k + 6), S34, &H4881D05
        HH a, b, c, d, x(k + 9), S31, &HD9D4D039
        HH d, a, b, c, x(k + 12), S32, &HE6DB99E5
        HH c, d, a, b, x(k + 15), S33, &H1FA27CF8
        HH b, c, d, a, x(k + 2), S34, &HC4AC5665

        II a, b, c, d, x(k + 0), S41, &HF4292244
        II d, a, b, c, x(k + 7), S42, &H432AFF97
        II c, d, a, b, x(k + 14), S43, &HAB9423A7
        II b, c, d, a, x(k + 5), S44, &HFC93A039
        II a, b, c, d, x(k + 12), S41, &H655B59C3
        II d, a, b, c, x(k + 3), S42, &H8F0CCC92
        II c, d, a, b, x(k + 10), S43, &HFFEFF47D
        II b, c, d, a, x(k + 1), S44, &H85845DD1
        II a, b, c, d, x(k + 8), S41, &H6FA87E4F
        II d, a, b, c, x(k + 15), S42, &HFE2CE6E0
        II c, d, a, b, x(k + 6), S43, &HA3014314
        II b, c, d, a, x(k + 13), S44, &H4E0811A1
        II a, b, c, d, x(k + 4), S41, &HF7537E82
        II d, a, b, c, x(k + 11), S42, &HBD3AF235
        II c, d, a, b, x(k + 2), S43, &H2AD7D2BB
        II b, c, d, a, x(k + 9), S44, &HEB86D391

        a = AddUnsigned(a, AA)
        b = AddUnsigned(b, BB)
        c = AddUnsigned(c, CC)
        d = AddUnsigned(d, DD)
    Next

    ' Step 5.  Output the 128 bit digest
            '=LCase(WordToHex(a) & WordToHex(b) & WordToHex(c) & WordToHex(d))
    MD5 = LCase(WordToHex(b) & WordToHex(c))
End Function

完毕！真TMD长！上面这个模块你也可以到我的FTP上下载～ftp://my99.xicp.net/md5.bas

顶
但是好像有错误
RShiftSigned = Int(lValue / m_l2Power(iShiftBits))
报错说除数为零

555555555md5是不可逆加密算法，～～不能解密，它的原理就像x+y=100一样，有N多种可能，也就是一个加密后的字符串对应N个可能是正确的正确密码～知道了吧～～
这个模块是拿别人的，不过我有个16位的，那个可能还简单些～

Private Const BITS_TO_A_BYTE = 8
Private Const BYTES_TO_A_WORD = 4
Private Const BITS_TO_A_WORD = 32Private m_lOnBits(30)
Private m_l2Power(30)

Private Function LShift(lValue, iShiftBits)
    If iShiftBits = 0 Then
        LShift = lValue
        Exit Function
    ElseIf iShiftBits = 31 Then
        If lValue And 1 Then
            LShift = &H80000000
        Else
            LShift = 0
        End If
        Exit Function
    ElseIf iShiftBits < 0 Or iShiftBits > 31 Then
        Err.Raise 6
    End If    If (lValue And m_l2Power(31 - iShiftBits)) Then
        LShift = ((lValue And m_lOnBits(31 - (iShiftBits + 1))) * m_l2Power(iShiftBits)) Or &H80000000
    Else
        LShift = ((lValue And m_lOnBits(31 - iShiftBits)) * m_l2Power(iShiftBits))
    End If
End FunctionPrivate Function RShift(lValue, iShiftBits)
    If iShiftBits = 0 Then
        RShift = lValue
        Exit Function
    ElseIf iShiftBits = 31 Then
        If lValue And &H80000000 Then
            RShift = 1
        Else
            RShift = 0
        End If
        Exit Function
    ElseIf iShiftBits < 0 Or iShiftBits > 31 Then
        Err.Raise 6
    End If

    RShift = (lValue And &H7FFFFFFE) \ m_l2Power(iShiftBits)    If (lValue And &H80000000) Then
        RShift = (RShift Or (&H40000000 \ m_l2Power(iShiftBits - 1)))
    End If
End FunctionPrivate Function RotateLeft(lValue, iShiftBits)
    RotateLeft = LShift(lValue, iShiftBits) Or RShift(lValue, (32 - iShiftBits))
End FunctionPrivate Function AddUnsigned(lX, lY)
    Dim lX4
    Dim lY4
    Dim lX8
    Dim lY8
    Dim lResult

    lX8 = lX And &H80000000
    lY8 = lY And &H80000000
    lX4 = lX And &H40000000
    lY4 = lY And &H40000000

    lResult = (lX And &H3FFFFFFF) + (lY And &H3FFFFFFF)

    If lX4 And lY4 Then
        lResult = lResult Xor &H80000000 Xor lX8 Xor lY8
    ElseIf lX4 Or lY4 Then
        If lResult And &H40000000 Then
            lResult = lResult Xor &HC0000000 Xor lX8 Xor lY8
        Else
            lResult = lResult Xor &H40000000 Xor lX8 Xor lY8
        End If
    Else
        lResult = lResult Xor lX8 Xor lY8
    End If

    AddUnsigned = lResult
End FunctionPrivate Function md5_F(x, y, z)
    md5_F = (x And y) Or ((Not x) And z)
End FunctionPrivate Function md5_G(x, y, z)
    md5_G = (x And z) Or (y And (Not z))
End FunctionPrivate Function md5_H(x, y, z)
    md5_H = (x Xor y Xor z)
End FunctionPrivate Function md5_I(x, y, z)
    md5_I = (y Xor (x Or (Not z)))
End FunctionPrivate Sub md5_FF(a, b, c, d, x, s, ac)
    a = AddUnsigned(a, AddUnsigned(AddUnsigned(md5_F(b, c, d), x), ac))
    a = RotateLeft(a, s)
    a = AddUnsigned(a, b)
End SubPrivate Sub md5_GG(a, b, c, d, x, s, ac)
    a = AddUnsigned(a, AddUnsigned(AddUnsigned(md5_G(b, c, d), x), ac))
    a = RotateLeft(a, s)
    a = AddUnsigned(a, b)
End SubPrivate Sub md5_HH(a, b, c, d, x, s, ac)
    a = AddUnsigned(a, AddUnsigned(AddUnsigned(md5_H(b, c, d), x), ac))
    a = RotateLeft(a, s)
    a = AddUnsigned(a, b)
End SubPrivate Sub md5_II(a, b, c, d, x, s, ac)
    a = AddUnsigned(a, AddUnsigned(AddUnsigned(md5_I(b, c, d), x), ac))
    a = RotateLeft(a, s)
    a = AddUnsigned(a, b)
End SubPrivate Function ConvertToWordArray(sMessage)
    Dim lMessageLength
    Dim lNumberOfWords
    Dim lWordArray()
    Dim lBytePosition
    Dim lByteCount
    Dim lWordCount

    Const MODULUS_BITS = 512
    Const CONGRUENT_BITS = 448

    lMessageLength = Len(sMessage)

    lNumberOfWords = (((lMessageLength + ((MODULUS_BITS - CONGRUENT_BITS) \ BITS_TO_A_BYTE)) \ (MODULUS_BITS \ BITS_TO_A_BYTE)) + 1) * (MODULUS_BITS \ BITS_TO_A_WORD)
    ReDim lWordArray(lNumberOfWords - 1)

    lBytePosition = 0
    lByteCount = 0
    Do Until lByteCount >= lMessageLength
        lWordCount = lByteCount \ BYTES_TO_A_WORD
        lBytePosition = (lByteCount Mod BYTES_TO_A_WORD) * BITS_TO_A_BYTE
        lWordArray(lWordCount) = lWordArray(lWordCount) Or LShift(Asc(Mid(sMessage, lByteCount + 1, 1)), lBytePosition)
        lByteCount = lByteCount + 1
    Loop    lWordCount = lByteCount \ BYTES_TO_A_WORD
    lBytePosition = (lByteCount Mod BYTES_TO_A_WORD) * BITS_TO_A_BYTE    lWordArray(lWordCount) = lWordArray(lWordCount) Or LShift(&H80, lBytePosition)    lWordArray(lNumberOfWords - 2) = LShift(lMessageLength, 3)
    lWordArray(lNumberOfWords - 1) = RShift(lMessageLength, 29)

    ConvertToWordArray = lWordArray
End FunctionPrivate Function WordToHex(lValue)
    Dim lByte
    Dim lCount

    For lCount = 0 To 3
        lByte = RShift(lValue, lCount * BITS_TO_A_BYTE) And m_lOnBits(BITS_TO_A_BYTE - 1)
        WordToHex = WordToHex & Right("0" & Hex(lByte), 2)
    Next
End Function

Public Function MD5(sMessage)    '用的时侯就调用这个函数！！！！！
    m_lOnBits(0) = CLng(1)
    m_lOnBits(1) = CLng(3)
    m_lOnBits(2) = CLng(7)
    m_lOnBits(3) = CLng(15)
    m_lOnBits(4) = CLng(31)
    m_lOnBits(5) = CLng(63)
    m_lOnBits(6) = CLng(127)
    m_lOnBits(7) = CLng(255)
    m_lOnBits(8) = CLng(511)
    m_lOnBits(9) = CLng(1023)
    m_lOnBits(10) = CLng(2047)
    m_lOnBits(11) = CLng(4095)
    m_lOnBits(12) = CLng(8191)
    m_lOnBits(13) = CLng(16383)
    m_lOnBits(14) = CLng(32767)
    m_lOnBits(15) = CLng(65535)
    m_lOnBits(16) = CLng(131071)
    m_lOnBits(17) = CLng(262143)
    m_lOnBits(18) = CLng(524287)
    m_lOnBits(19) = CLng(1048575)
    m_lOnBits(20) = CLng(2097151)
    m_lOnBits(21) = CLng(4194303)
    m_lOnBits(22) = CLng(8388607)
    m_lOnBits(23) = CLng(16777215)
    m_lOnBits(24) = CLng(33554431)
    m_lOnBits(25) = CLng(67108863)
    m_lOnBits(26) = CLng(134217727)
    m_lOnBits(27) = CLng(268435455)
    m_lOnBits(28) = CLng(536870911)
    m_lOnBits(29) = CLng(1073741823)
    m_lOnBits(30) = CLng(2147483647)

    m_l2Power(0) = CLng(1)
    m_l2Power(1) = CLng(2)
    m_l2Power(2) = CLng(4)
    m_l2Power(3) = CLng(8)
    m_l2Power(4) = CLng(16)
    m_l2Power(5) = CLng(32)
    m_l2Power(6) = CLng(64)
    m_l2Power(7) = CLng(128)
    m_l2Power(8) = CLng(256)
    m_l2Power(9) = CLng(512)
    m_l2Power(10) = CLng(1024)
    m_l2Power(11) = CLng(2048)
    m_l2Power(12) = CLng(4096)
    m_l2Power(13) = CLng(8192)
    m_l2Power(14) = CLng(16384)
    m_l2Power(15) = CLng(32768)
    m_l2Power(16) = CLng(65536)
    m_l2Power(17) = CLng(131072)
    m_l2Power(18) = CLng(262144)
    m_l2Power(19) = CLng(524288)
    m_l2Power(20) = CLng(1048576)
    m_l2Power(21) = CLng(2097152)
    m_l2Power(22) = CLng(4194304)
    m_l2Power(23) = CLng(8388608)
    m_l2Power(24) = CLng(16777216)
    m_l2Power(25) = CLng(33554432)
    m_l2Power(26) = CLng(67108864)
    m_l2Power(27) = CLng(134217728)
    m_l2Power(28) = CLng(268435456)
    m_l2Power(29) = CLng(536870912)
    m_l2Power(30) = CLng(1073741824)
    Dim x
    Dim k
    Dim AA
    Dim BB
    Dim CC
    Dim DD
    Dim a
    Dim b
    Dim c
    Dim d

    Const S11 = 7
    Const S12 = 12
    Const S13 = 17
    Const S14 = 22
    Const S21 = 5
    Const S22 = 9
    Const S23 = 14
    Const S24 = 20
    Const S31 = 4
    Const S32 = 11
    Const S33 = 16
    Const S34 = 23
    Const S41 = 6
    Const S42 = 10
    Const S43 = 15
    Const S44 = 21    x = ConvertToWordArray(sMessage)

    a = &H67452301
    b = &HEFCDAB89
    c = &H98BADCFE
    d = &H10325476    For k = 0 To UBound(x) Step 16
        AA = a
        BB = b
        CC = c
        DD = d

        md5_FF a, b, c, d, x(k + 15), S11, &HD76AA478
        md5_FF d, a, b, c, x(k + 14), S12, &HE8C7B756
        md5_FF c, d, a, b, x(k + 13), S13, &H242070DB
        md5_FF b, c, d, a, x(k + 12), S14, &HC1BDCEEE
        md5_FF a, b, c, d, x(k + 11), S11, &HF57C0FAF
        md5_FF d, a, b, c, x(k + 10), S12, &H4787C62A
        md5_FF c, d, a, b, x(k + 9), S13, &HA8304613
        md5_FF b, c, d, a, x(k + 8), S14, &HFD469501
        md5_FF a, b, c, d, x(k + 7), S11, &H698098D8
        md5_FF d, a, b, c, x(k + 6), S12, &H8B44F7AF
        md5_FF c, d, a, b, x(k + 5), S13, &HFFFF5BB1
        md5_FF b, c, d, a, x(k + 4), S14, &H895CD7BE
        md5_FF a, b, c, d, x(k + 3), S11, &H6B901122
        md5_FF d, a, b, c, x(k + 2), S12, &HFD987193
        md5_FF c, d, a, b, x(k + 1), S13, &HA679438E
        md5_FF b, c, d, a, x(k + 0), S14, &H49B40821

        md5_GG a, b, c, d, x(k + 1), S21, &HF61E2562
        md5_GG d, a, b, c, x(k + 6), S22, &HC040B340
        md5_GG c, d, a, b, x(k + 11), S23, &H265E5A51
        md5_GG b, c, d, a, x(k + 0), S24, &HE9B6C7AA
        md5_GG a, b, c, d, x(k + 5), S21, &HD62F105D
        md5_GG d, a, b, c, x(k + 10), S22, &H2441453
        md5_GG c, d, a, b, x(k + 15), S23, &HD8A1E681
        md5_GG b, c, d, a, x(k + 4), S24, &HE7D3FBC8
        md5_GG a, b, c, d, x(k + 9), S21, &H21E1CDE6
        md5_GG d, a, b, c, x(k + 14), S22, &HC33707D6
        md5_GG c, d, a, b, x(k + 3), S23, &HF4D50D87
        md5_GG b, c, d, a, x(k + 8), S24, &H455A14ED
        md5_GG a, b, c, d, x(k + 13), S21, &HA9E3E905
        md5_GG d, a, b, c, x(k + 2), S22, &HFCEFA3F8
        md5_GG c, d, a, b, x(k + 7), S23, &H676F02D9
        md5_GG b, c, d, a, x(k + 12), S24, &H8D2A4C8A

        md5_HH a, b, c, d, x(k + 5), S31, &HFFFA3942
        md5_HH d, a, b, c, x(k + 8), S32, &H8771F681
        md5_HH c, d, a, b, x(k + 11), S33, &H6D9D6122
        md5_HH b, c, d, a, x(k + 14), S34, &HFDE5380C
        md5_HH a, b, c, d, x(k + 1), S31, &HA4BEEA44
        md5_HH d, a, b, c, x(k + 4), S32, &H4BDECFA9
        md5_HH c, d, a, b, x(k + 7), S33, &HF6BB4B60
        md5_HH b, c, d, a, x(k + 10), S34, &HBEBFBC70
        md5_HH a, b, c, d, x(k + 13), S31, &H289B7EC6
        md5_HH d, a, b, c, x(k + 0), S32, &HEAA127FA
        md5_HH c, d, a, b, x(k + 3), S33, &HD4EF3085
        md5_HH b, c, d, a, x(k + 6), S34, &H4881D05
        md5_HH a, b, c, d, x(k + 9), S31, &HD9D4D039
        md5_HH d, a, b, c, x(k + 12), S32, &HE6DB99E5
        md5_HH c, d, a, b, x(k + 15), S33, &H1FA27CF8
        md5_HH b, c, d, a, x(k + 2), S34, &HC4AC5665

        md5_II a, b, c, d, x(k + 0), S41, &HF4292244
        md5_II d, a, b, c, x(k + 7), S42, &H432AFF97
        md5_II c, d, a, b, x(k + 14), S43, &HAB9423A7
        md5_II b, c, d, a, x(k + 5), S44, &HFC93A039
        md5_II a, b, c, d, x(k + 12), S41, &H655B59C3
        md5_II d, a, b, c, x(k + 3), S42, &H8F0CCC92
        md5_II c, d, a, b, x(k + 10), S43, &HFFEFF47D
        md5_II b, c, d, a, x(k + 1), S44, &H85845DD1
        md5_II a, b, c, d, x(k + 8), S41, &H6FA87E4F
        md5_II d, a, b, c, x(k + 15), S42, &HFE2CE6E0
        md5_II c, d, a, b, x(k + 6), S43, &HA3014314
        md5_II b, c, d, a, x(k + 13), S44, &H4E0811A1
        md5_II a, b, c, d, x(k + 4), S41, &HF7537E82
        md5_II d, a, b, c, x(k + 11), S42, &HBD3AF235
        md5_II c, d, a, b, x(k + 2), S43, &H2AD7D2BB
        md5_II b, c, d, a, x(k + 9), S44, &HEB86D391

        a = AddUnsigned(a, AA)
        b = AddUnsigned(b, BB)
        c = AddUnsigned(c, CC)
        d = AddUnsigned(d, DD)
    Next

    'MD5 = LCase(WordToHex(a) & WordToHex(b) & WordToHex(c) & WordToHex(d))
    MD5=LCase(WordToHex(b) & WordToHex(c))
End Function

呵呵，您误会了。我不是这个意思
我指的是这样
加密 Txt1=md5(password)
解密 Txt2=unMd5(Txt1, password)
也就是说，我好像没有发现解密的函数
============================
Sorry，小生愚昧，望指点

VB中实现MD5加密
使用方法：msgbox DigestStrToHexStr("111")源代码:-----------剪切线------------------------------------------------------------Option Explicit'/******************************************************************************
' *  Copyright (C) 2000 by Robert Hubley.                                      *
' *  All rights reserved.                                                      *
' *                                                                            *
' *  This software is provided ``AS IS'' and any express or implied            *
' *  warranties, including, but not limited to, the implied warranties of      *
' *  merchantability and fitness for a particular purpose, are disclaimed.     *
' *  In no event shall the authors be liable for any direct, indirect,         *
' *  incidental, special, exemplary, or consequential damages (including, but  *
' *  not limited to, procurement of substitute goods or services; loss of use, *
' *  data, or profits; or business interruption) however caused and on any     *
' *  theory of liability, whether in contract, strict liability, or tort       *
' *  (including negligence or otherwise) arising in any way out of the use of  *
' *  this software, even if advised of the possibility of such damage.         *
' *                                                                            *
' ******************************************************************************
'
'  CLASS: MD5
'
'  DESCRIPTION:
'     This is a class which encapsulates a set of MD5 Message Digest functions.
'     MD5 algorithm produces a 128 bit digital fingerprint (signature) from an
'     dataset of arbitrary length.  For details see RFC 1321 (summarized below).
'     This implementation is derived from the RSA Data Security, Inc. MD5 Message-Digest
'     algorithm reference implementation (originally written in C)
'
'  AUTHOR:
'     Robert M. Hubley 12/1999
'
'
'  NOTES:
'      Network Working Group                                    R. Rivest
'      Request for Comments: 1321     MIT Laboratory for Computer Science
'                                             and RSA Data Security, Inc.
'                                                              April 1992
'
'
'                           The MD5 Message-Digest Algorithm
'
'      Summary
'
'         This document describes the MD5 message-digest algorithm. The
'         algorithm takes as input a message of arbitrary length and produces
'         as output a 128-bit "fingerprint" or "message digest" of the input.
'         It is conjectured that it is computationally infeasible to produce
'         two messages having the same message digest, or to produce any
'         message having a given prespecified target message digest. The MD5
'         algorithm is intended for digital signature applications, where a
'         large file must be "compressed" in a secure manner before being
'         encrypted with a private (secret) key under a public-key cryptosystem
'         such as RSA.
'
'         The MD5 algorithm is designed to be quite fast on 32-bit machines. In
'         addition, the MD5 algorithm does not require any large substitution
'         tables; the algorithm can be coded quite compactly.
'
'         The MD5 algorithm is an extension of the MD4 message-digest algorithm
'         1,2]. MD5 is slightly slower than MD4, but is more "conservative" in
'         design. MD5 was designed because it was felt that MD4 was perhaps
'         being adopted for use more quickly than justified by the existing
'         critical review; because MD4 was designed to be exceptionally fast,
'         it is "at the edge" in terms of risking successful cryptanalytic
'         attack. MD5 backs off a bit, giving up a little in speed for a much
'         greater likelihood of ultimate security. It incorporates some
'         suggestions made by various reviewers, and contains additional
'         optimizations. The MD5 algorithm is being placed in the public domain
'         for review and possible adoption as a standard.
'
'         RFC Author:
'         Ronald L.Rivest
'         Massachusetts Institute of Technology
'         Laboratory for Computer Science
'         NE43 -324545    Technology Square
'         Cambridge, MA  02139-1986
'         Phone: (617) 253-5880
'         EMail:    Rivest@ theory.lcs.mit.edu
'
'
'
'  CHANGE HISTORY:
'
'     0.1.0  RMH    1999/12/29      Original version
'
'

'=
'= Class Constants
'=
Private Const OFFSET_4 = 4294967296#
Private Const MAXINT_4 = 2147483647Private Const S11 = 7
Private Const S12 = 12
Private Const S13 = 17
Private Const S14 = 22
Private Const S21 = 5
Private Const S22 = 9
Private Const S23 = 14
Private Const S24 = 20
Private Const S31 = 4
Private Const S32 = 11
Private Const S33 = 16
Private Const S34 = 23
Private Const S41 = 6
Private Const S42 = 10
Private Const S43 = 15
Private Const S44 = 21
'=
'= Class Variables
'=
Private State(4) As Long
Private ByteCounter As Long
Private ByteBuffer(63) As Byte
'=
'= Class Properties
'=
Property Get RegisterA() As String
    RegisterA = State(1)
End PropertyProperty Get RegisterB() As String
    RegisterB = State(2)
End PropertyProperty Get RegisterC() As String
    RegisterC = State(3)
End PropertyProperty Get RegisterD() As String
    RegisterD = State(4)
End Property
'=
'= Class Functions
'='
' Function to quickly digest a file into a hex string
'
Public Function DigestFileToHexStr(FileName As String) As String
    Open FileName For Binary Access Read As #1
    MD5Init
    Do While Not EOF(1)
        Get #1, , ByteBuffer
        If Loc(1) < LOF(1) Then
            ByteCounter = ByteCounter + 64
            MD5Transform ByteBuffer
        End If
    Loop
    ByteCounter = ByteCounter + (LOF(1) Mod 64)
    Close #1
    MD5Final
    DigestFileToHexStr = GetValues
End Function'
' Function to digest a text string and output the result as a string
' of hexadecimal characters.
'
Public Function DigestStrToHexStr(SourceString As String) As String
    MD5Init
    MD5Update Len(SourceString), StringToArray(SourceString)
    MD5Final
    DigestStrToHexStr = GetValues
End Function'
' A utility function which converts a string into an array of
' bytes.
'
Private Function StringToArray(InString As String) As Byte()
    Dim I As Integer
    Dim bytBuffer() As Byte
    ReDim bytBuffer(Len(InString))
    For I = 0 To Len(InString) - 1
        bytBuffer(I) = Asc(Mid(InString, I + 1, 1))
    Next I
    StringToArray = bytBuffer
End Function'
' Concatenate the four state vaules into one string
'
Public Function GetValues() As String
    GetValues = LongToString(State(1)) & LongToString(State(2)) & LongToString(State(3)) & LongToString(State(4))
End Function'
' Convert a Long to a Hex string
'
Private Function LongToString(Num As Long) As String
        Dim a As Byte
        Dim b As Byte
        Dim c As Byte
        Dim d As Byte

        a = Num And &HFF&
        If a < 16 Then
            LongToString = "0" & Hex(a)
        Else
            LongToString = Hex(a)
        End If

        b = (Num And &HFF00&) \ 256
        If b < 16 Then
            LongToString = LongToString & "0" & Hex(b)
        Else
            LongToString = LongToString & Hex(b)
        End If

        c = (Num And &HFF0000) \ 65536
        If c < 16 Then
            LongToString = LongToString & "0" & Hex(c)
        Else
            LongToString = LongToString & Hex(c)
        End If

        If Num < 0 Then
            d = ((Num And &H7F000000) \ 16777216) Or &H80&
        Else
            d = (Num And &HFF000000) \ 16777216
        End If

        If d < 16 Then
            LongToString = LongToString & "0" & Hex(d)
        Else
            LongToString = LongToString & Hex(d)
        End If

End Function'

'
' Initialize the class
'   This must be called before a digest calculation is started
'
Public Sub MD5Init()
    ByteCounter = 0
    State(1) = UnsignedToLong(1732584193#)
    State(2) = UnsignedToLong(4023233417#)
    State(3) = UnsignedToLong(2562383102#)
    State(4) = UnsignedToLong(271733878#)
End Sub'
' MD5 Final
'
Public Sub MD5Final()
    Dim dblBits As Double

    Dim padding(72) As Byte
    Dim lngBytesBuffered As Long

    padding(0) = &H80

    dblBits = ByteCounter * 8

    ' Pad out
    lngBytesBuffered = ByteCounter Mod 64
    If lngBytesBuffered <= 56 Then
        MD5Update 56 - lngBytesBuffered, padding
    Else
        MD5Update 120 - ByteCounter, padding
    End If


    padding(0) = UnsignedToLong(dblBits) And &HFF&
    padding(1) = UnsignedToLong(dblBits) \ 256 And &HFF&
    padding(2) = UnsignedToLong(dblBits) \ 65536 And &HFF&
    padding(3) = UnsignedToLong(dblBits) \ 16777216 And &HFF&
    padding(4) = 0
    padding(5) = 0
    padding(6) = 0
    padding(7) = 0

    MD5Update 8, padding
End Sub'
' Break up input stream into 64 byte chunks
'
Public Sub MD5Update(InputLen As Long, InputBuffer() As Byte)
    Dim II As Integer
    Dim I As Integer
    Dim J As Integer
    Dim K As Integer
    Dim lngBufferedBytes As Long
    Dim lngBufferRemaining As Long
    Dim lngRem As Long

    lngBufferedBytes = ByteCounter Mod 64
    lngBufferRemaining = 64 - lngBufferedBytes
    ByteCounter = ByteCounter + InputLen
    ' Use up old buffer results first
    If InputLen >= lngBufferRemaining Then
        For II = 0 To lngBufferRemaining - 1
            ByteBuffer(lngBufferedBytes + II) = InputBuffer(II)
        Next II
        MD5Transform ByteBuffer

        lngRem = (InputLen) Mod 64
        ' The transfer is a multiple of 64 lets do some transformations
        For I = lngBufferRemaining To InputLen - II - lngRem Step 64
            For J = 0 To 63
                ByteBuffer(J) = InputBuffer(I + J)
            Next J
            MD5Transform ByteBuffer
        Next I
        lngBufferedBytes = 0
    Else
      I = 0
    End If

    ' Buffer any remaining input
    For K = 0 To InputLen - I - 1
        ByteBuffer(lngBufferedBytes + K) = InputBuffer(I + K)
    Next K

End Sub'
' MD5 Transform
'
Private Sub MD5Transform(Buffer() As Byte)
    Dim x(16) As Long
    Dim a As Long
    Dim b As Long
    Dim c As Long
    Dim d As Long

    a = State(1)
    b = State(2)
    c = State(3)
    d = State(4)

    Decode 64, x, Buffer    ' Round 1
    FF a, b, c, d, x(0), S11, -680876936
    FF d, a, b, c, x(1), S12, -389564586
    FF c, d, a, b, x(2), S13, 606105819
    FF b, c, d, a, x(3), S14, -1044525330
    FF a, b, c, d, x(4), S11, -176418897
    FF d, a, b, c, x(5), S12, 1200080426
    FF c, d, a, b, x(6), S13, -1473231341
    FF b, c, d, a, x(7), S14, -45705983
    FF a, b, c, d, x(8), S11, 1770035416
    FF d, a, b, c, x(9), S12, -1958414417
    FF c, d, a, b, x(10), S13, -42063
    FF b, c, d, a, x(11), S14, -1990404162
    FF a, b, c, d, x(12), S11, 1804603682
    FF d, a, b, c, x(13), S12, -40341101
    FF c, d, a, b, x(14), S13, -1502002290
    FF b, c, d, a, x(15), S14, 1236535329

    ' Round 2
    GG a, b, c, d, x(1), S21, -165796510
    GG d, a, b, c, x(6), S22, -1069501632
    GG c, d, a, b, x(11), S23, 643717713
    GG b, c, d, a, x(0), S24, -373897302
    GG a, b, c, d, x(5), S21, -701558691
    GG d, a, b, c, x(10), S22, 38016083
    GG c, d, a, b, x(15), S23, -660478335
    GG b, c, d, a, x(4), S24, -405537848
    GG a, b, c, d, x(9), S21, 568446438
    GG d, a, b, c, x(14), S22, -1019803690
    GG c, d, a, b, x(3), S23, -187363961
    GG b, c, d, a, x(8), S24, 1163531501
    GG a, b, c, d, x(13), S21, -1444681467
    GG d, a, b, c, x(2), S22, -51403784
    GG c, d, a, b, x(7), S23, 1735328473
    GG b, c, d, a, x(12), S24, -1926607734

    ' Round 3
    HH a, b, c, d, x(5), S31, -378558
    HH d, a, b, c, x(8), S32, -2022574463
    HH c, d, a, b, x(11), S33, 1839030562
    HH b, c, d, a, x(14), S34, -35309556
    HH a, b, c, d, x(1), S31, -1530992060
    HH d, a, b, c, x(4), S32, 1272893353
    HH c, d, a, b, x(7), S33, -155497632
    HH b, c, d, a, x(10), S34, -1094730640
    HH a, b, c, d, x(13), S31, 681279174
    HH d, a, b, c, x(0), S32, -358537222
    HH c, d, a, b, x(3), S33, -722521979
    HH b, c, d, a, x(6), S34, 76029189
    HH a, b, c, d, x(9), S31, -640364487
    HH d, a, b, c, x(12), S32, -421815835
    HH c, d, a, b, x(15), S33, 530742520
    HH b, c, d, a, x(2), S34, -995338651

1、
补位：
MD5算法先对输入的数据进行补位，使得数据位长度LEN对512求余的结果是448。即数据扩展至K*512+448位。即K*64+56个字节，K为整数。
具体补位操作：补一个1，然后补0至满足上述要求。 2、
补数据长度：
用一个64位的数字表示数据的原始长度B，把B用两个32位数表示。这时，数
据就被填补成长度为512位的倍数。 3、
初始化MD5参数：
四个32位整数 (A,B,C,D) 用来计算信息摘要，初始化使用的是十六进制表
示的数字
A=0X01234567
B=0X89abcdef
C=0Xfedcba98
D=0X76543210 4、
处理位操作函数：
X，Y，Z为32位整数。
F(X,Y,Z) = X&Y|NOT(X)&Z
G(X,Y,Z) = X&Z|Y?(Z)
H(X,Y,Z) = X xor Y xor Z
I(X,Y,Z) = Y xor (X|not(Z)) 5、
主要变换过程：
使用常数组T[1 ... 64]， T[i]为32位整数用16进制表示，数据用16个32位
的整数数组M[]表示。
具体过程如下： /* 处理数据原文 */
For i = 0 to N/16-1 do /*每一次，把数据原文存放在16个元素的数组X中. */
For j = 0 to 15 do
Set X[j] to M[i*16+j].
end /结束对J的循环/* Save A as AA, B as BB, C as CC, and D as DD.
*/
AA = A
BB = B
CC = C
DD = D /* 第1轮*/
/* 以 [abcd k s i]表示如下操作
a = b + ((a + F(b,c,d) + X[k] + T[i]) <<< s). *//* Do the following 16 operations. */
[ABCD 0 7 1] [DABC 1 12 2] [CDAB 2 17 3] [BCDA 3
22 4]
[ABCD 4 7 5] [DABC 5 12 6] [CDAB 6 17 7] [BCDA 7
22 8]
[ABCD 8 7 9] [DABC 9 12 10] [CDAB 10 17 11] [BCDA
11 22 12]
[ABCD 12 7 13] [DABC 13 12 14] [CDAB 14 17 15]
[BCDA 15 22 16] /* 第2轮* */
/* 以 [abcd k s i]表示如下操作
a = b + ((a + G(b,c,d) + X[k] + T[i]) <<< s). */
/* Do the following 16 operations. */
[ABCD 1 5 17] [DABC 6 9 18] [CDAB 11 14 19] [BCDA
0 20 20]
[ABCD 5 5 21] [DABC 10 9 22] [CDAB 15 14 23]
[BCDA 4 20 24]
[ABCD 9 5 25] [DABC 14 9 26] [CDAB 3 14 27] [BCDA
8 20 28]
[ABCD 13 5 29] [DABC 2 9 30] [CDAB 7 14 31] [BCDA
12 20 32] /* 第3轮*/
/* 以 [abcd k s i]表示如下操作
a = b + ((a + H(b,c,d) + X[k] + T[i]) <<< s). */
/* Do the following 16 operations. */
[ABCD 5 4 33] [DABC 8 11 34] [CDAB 11 16 35]
[BCDA 14 23 36]
[ABCD 1 4 37] [DABC 4 11 38] [CDAB 7 16 39] [BCDA
10 23 40]
[ABCD 13 4 41] [DABC 0 11 42] [CDAB 3 16 43]
[BCDA 6 23 44]
[ABCD 9 4 45] [DABC 12 11 46] [CDAB 15 16 47]
[BCDA 2 23 48] /* 第4轮*/
/* 以 [abcd k s i]表示如下操作
a = b + ((a + I(b,c,d) + X[k] + T[i]) <<< s). */
/* Do the following 16 operations. */
[ABCD 0 6 49] [DABC 7 10 50] [CDAB 14 15 51]
[BCDA 5 21 52]
[ABCD 12 6 53] [DABC 3 10 54] [CDAB 10 15 55]
[BCDA 1 21 56]
[ABCD 8 6 57] [DABC 15 10 58] [CDAB 6 15 59]
[BCDA 13 21 60]
[ABCD 4 6 61] [DABC 11 10 62] [CDAB 2 15 63]
[BCDA 9 21 64] /* 然后进行如下操作 */
A = A + AA
B = B + BB
C = C + CC
D = D + DD end /* 结束对I的循环*/6、
输出结果。

调试易

请教大虾,谁能给我一个32位的md5加密算法

解决方案 »