请教高手,sax解析xml遇到&如何解析,如下面这一条
<menulink>http://www.submenu.jsp?mn=gx&ps=9</menulink>
使用语句 if(currentElementName.equals("menulink")&&textContent!=null&&!textContent.trim().equals("")){
Log.i("textContent age", textContent);
beauty.setMenulink(textContent);但是,得出的值是这样的
12-06 07:46:43.298: INFO/currentElementName(831): menulink
12-06 07:46:43.298: INFO/textContent age(831): http://www.submenu.jsp?mn=gx
12-06 07:46:43.298: INFO/currentElementName(831): menulink
12-06 07:46:43.301: INFO/textContent age(831): &
12-06 07:46:43.301: INFO/currentElementName(831): menulink
12-06 07:46:43.301: INFO/textContent age(831): ps=9
12-06 07:46:43.301: INFO/currentElementName(831): menulink
12-06 07:46:43.301: INFO/currentElementName(831): menulink求助,谢谢~~
<menulink>http://www.submenu.jsp?mn=gx&ps=9</menulink>
使用语句 if(currentElementName.equals("menulink")&&textContent!=null&&!textContent.trim().equals("")){
Log.i("textContent age", textContent);
beauty.setMenulink(textContent);但是,得出的值是这样的
12-06 07:46:43.298: INFO/currentElementName(831): menulink
12-06 07:46:43.298: INFO/textContent age(831): http://www.submenu.jsp?mn=gx
12-06 07:46:43.298: INFO/currentElementName(831): menulink
12-06 07:46:43.301: INFO/textContent age(831): &
12-06 07:46:43.301: INFO/currentElementName(831): menulink
12-06 07:46:43.301: INFO/textContent age(831): ps=9
12-06 07:46:43.301: INFO/currentElementName(831): menulink
12-06 07:46:43.301: INFO/currentElementName(831): menulink求助,谢谢~~
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