android新手

Question

做了个web服务端，如何用android客户端交互数据

Answer 1

public static String doPostJson(String urlStr, Map<String, String> heads, String jsonStr)
{
try{
URL url = new URL(urlStr);
        HttpURLConnection connection = ((HttpURLConnection) url.openConnection());
        connection.setDoInput(true);
        connection.setDoOutput(true);
        connection.setUseCaches(false);
        connection.setConnectTimeout(5000);
        connection.setRequestMethod("POST");
        connection.setRequestProperty("Charset", "UTF-8"); 
        //connection.setRequestProperty("Content-Type", "application/json-rpc");
        connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
if (heads != null){
for(Map.Entry<String, String> head : heads.entrySet()){
connection.setRequestProperty(head.getKey(), head.getValue());
}
}

        byte[] sendData = jsonStr.getBytes("UTF-8"); 
        connection.setFixedLengthStreamingMode(sendData.length);
        connection.connect();
        OutputStream out = connection.getOutputStream();
        //out.write(sendData, 0, sendData.length);
        out.write(sendData);
        out.flush();
        out.close();
        
        InputStream input = connection.getInputStream();
        StringBuffer sb = new StringBuffer();
        byte[] buffer = new byte[512];
        int len;
        while ((len = input.read(buffer)) != -1) {
         sb.append(new String(buffer, 0, len));
        }
        input.close();
        connection.disconnect();
        return sb.toString();
}catch(Exception e){
Log.e("System.out", Log.getStackTraceString(e));
}
return "";

}

/**
 * 执行一个Http Get 请求，返回请求响应的HTML
 * @param url
 *  请求的URL地址
 * @param heads
 *  请求时要设置的http头信息，没有设为null
 * */
public static String doGet(String url, Map<String, String> heads)
    {
        HttpResponse httpResponse = null;  
        try  
        {
         //  第1步：创建HttpGet对象  
         HttpGet httpGet = new HttpGet(url);
     if (heads != null){
     for(Map.Entry<String, String> head : heads.entrySet()){
     httpGet.addHeader(head.getKey(), head.getValue());
     }
     }
            //  第2步：使用execute方法发送HTTP POST请求，并返回HttpResponse对象
            httpResponse = new DefaultHttpClient().execute(httpGet);
            int statusCode = httpResponse.getStatusLine().getStatusCode(); 
            if (statusCode == 200)
            {
            //  第3步：使用getEntity方法获得返回结果  
            String result = EntityUtils.toString(httpResponse.getEntity());
            //System.out.println(result);
            return result;
            }
        }  
        catch (Exception e)  
        {
         Log.e("System.out", "Exception: "+Log.getStackTraceString(e));
        }
        return null;
    }

Answer 2

http://hi.baidu.com/yezhonglu/item/ad7b6aa6b1cb021a030a4d37楼主可以参考一下