帮忙解析个简单的json数据

JSONObject obj = new JSONObject("");
        String size = obj.optString("size");
        JSONArray array = new JSONArray(obj.optString("array"));
        for(int i = 0 ;i < array.length() ; i++){
            JSONObject objs = new JSONObject(array.getJSONObject(i));
            String uid = objs.optString("uid");
            .....;
        }

用Gson包很简单的，不过要借助下javaBean对象。package com.devil.pojo;import java.util.List;public class A { private List<B> array;
private int size; public List<B> getArray() {
return array;
} public void setArray(List<B> array) {
this.array = array;
} public int getSize() {
return size;
} public void setSize(int size) {
this.size = size;
}}package com.devil.pojo;public class B { private String UID;
private String IP; public String getUID() {
return UID;
} public void setUID(String uID) {
UID = uID;
} public String getIP() {
return IP;
} public void setIP(String iP) {
IP = iP;
}}private void T() {
String json = "{'array':[{'UID':'LACA6C0284SGCM8','IP':'192.168.1.112'},{'UID':'LACA6C0284UMFKY','IP':'192.168.1.127'},{'UID':'LACA6C0284KCXNU','IP':'192.168.1.106'}],'size':3}";
A a = JsonUtil.parse(json, A.class);
for (B b : a.getArray()) {
Log.e("DEVIL", b.getUID() + "  " + b.getIP());
}
}
03-20 14:00:53.869: E/DEVIL(12003): LACA6C0284SGCM8  192.168.1.112
03-20 14:00:53.869: E/DEVIL(12003): LACA6C0284UMFKY  192.168.1.127
03-20 14:00:53.869: E/DEVIL(12003): LACA6C0284KCXNU  192.168.1.106 /**
* 将json字符串转换成对象
*
* @param json
* @param type
* @return
*/
public static <T> T parse(String json, Class<T> type) {
Gson gson = new Gson();
T t = null;
try {
t = gson.fromJson(json, type);
} catch (Exception e) {
e.printStackTrace();
return null;
} return t;
}

    public static List<Map<String, Object>> getListMaps(String key, String jsonString){
        List<Map<String, Object>> listMap = new ArrayList<Map<String, Object>>();
        try {
            JSONObject jsonObject = new JSONObject(jsonString);
            JSONArray jsonArray = jsonObject.getJSONArray(key);
            for(int i = 0; i < jsonArray.length(); i++){
                JSONObject jsonObject2 = jsonArray.getJSONObject(i);
                Map<String, Object> map = new HashMap<String, Object>();
                // 通过org.json中的迭代器来取Map中的值。
                Iterator<String> iterator = jsonObject2.keys();
                while(iterator.hasNext()) {
                    String jsonKey = iterator.next();
                    Object jsonValue = jsonObject2.get(jsonKey);
                    //JSON的值是可以为空的，所以我们也需要对JSON的空值可能性进行判断。
                    if(jsonValue == null){
                        jsonValue = "";
                    }
                    map.put(jsonKey, jsonValue);
                }
                listMap.add(map);
            }
        } catch (Exception e) {
            // TODO: handle exception
        }
        return listMap;
    }

你们的方法都不错，谢谢你们！
t = gson.fromJson(json, type);为什么这个老是得到空值，有没遇到过？

public static List<Bean> pullJson(String jsonStr)
{
List<Bean> list = null;
Bean bean = null;
try {
JSONObject jsonObject = new JSONObject(jsonStr);
JSONArray jArray = jsonObject.getJSONArray("array");
//JSONArray jArray = (JSONArray) jsonObject.get("array");
list = new ArrayList<Bean>();
for (int i = 0; i < jArray.length(); i++) {
bean = new Bean();
JSONObject jsonObject2 = (JSONObject)jArray.get(i);
bean.setuId(jsonObject2.getString("UID"));
bean.setIp(jsonObject2.getString("IP"));
list.add(bean);
}
bean.setSize(jsonObject.getInt("size"));
return list;
} catch (Exception e) {
e.printStackTrace();
}
return null;
}

调试易

帮忙解析个简单的json数据

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