asmack调用MultiUserChat.isServiceEnabled返回false怎么解？

Question

本帖最后由 jinghuazhi 于 2013-12-18 14:46:31 编辑

Answer 1

ServiceDiscoveryManager sdm = ServiceDiscoveryManager.getInstanceFor(mConnection); 
sdm.addFeature("http://jabber.org/protocol/disco#info");
sdm.addFeature("http://jabber.org/protocol/disco#item");
//对于ServiceDiscoveryManager，需要加上muc协议
sdm.addFeature("http://jabber.org/protocol/muc");

Answer 2

求问，你加上这些之后真的获得群组了吗，另求你的asmack包，谢谢，急

Answer 3

public List<MucRoom> getAllHostedRooms(){
List<MucRoom> rooms = new ArrayList<MucRoom>();
try {
Collection<HostedRoom> hrooms = MultiUserChat.getHostedRooms(con, con.getServiceName());
if(!hrooms.isEmpty()){
for(HostedRoom r:hrooms){
RoomInfo roominfo = MultiUserChat.getRoomInfo(con, r.getJid());
SLog.i("会议室Info", roominfo.toString());
MucRoom mr = new MucRoom();
mr.setDescription(roominfo.getDescription());
mr.setName(r.getName());
mr.setJid(r.getJid());
mr.setOccupants(roominfo.getOccupantsCount());
mr.setSubject(roominfo.getSubject());
rooms.add(mr);
}
}
} catch (XMPPException e) {
SLog.e(tag, " 获取Hosted Rooms 出错");
SLog.e(tag, Log.getStackTraceString(e));
}
return rooms;数据返回正常，可以查询所有 的房间名称
-----------------------------------------------------------------------------------------------------------------------------------------------------
//判断用户是否支持Multi-User聊天协议    
        //注：需要加上资源标识符    
        boolean supports = MultiUserChat.isServiceEnabled(con, con.getUser());      
         //获取某用户所加入的聊天室    
        if(supports) { 
         Iterator<String> jrs = MultiUserChat.getJoinedRooms(con, con.getUser());
  }
supports返回总是false,楼上是怎么解决这个问题的

Answer 4

我这边  supports返回也总是false,  楼上是解决这个问题了吗