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Question

  public void onActivityResult(int paramInt1, int paramInt2, Intent paramIntent)
  {
    switch (paramInt1)
    {
    default:
    case 1:
    }
    do
      return;
    while (paramInt2 != -1);
     String str = paramIntent.getExtras().getString(DeviceListActivity.EXTRA_DEVICE_ADDRESS);        // paramIntent.getExtras().getString(DeviceListActivity.EXTRA_DEVICE_ADDRESS);
    this._device = this._bluetooth.getRemoteDevice(str);
    try
    {
      this._socket = this._device.createRfcommSocketToServiceRecord(UUID.fromString("00001101-0000-1000-8000-00805F9B34FB"));
       // localButton = (Button)findViewById(2130968586);//2131099658
        Button localButton = (Button)findViewById(2130968586);
    }
    catch (IOException localIOException2)
    {
      try
      {
        Button localButton;
        this._socket.connect();
        Toast.makeText(this, "连接" + this._device.getName() + "成功！", 0).show();
        localButton.setText("断开");       
      }
      catch (IOException localIOException2)
      {
        try
        {
          while (true)
          {
            this.is = this._socket.getInputStream();
            if (this.bThread)
              break;
            this.ReadThread.start();
            this.bThread = true;
            return;
            localIOException1 = localIOException1;
            Toast.makeText(this, "连接失败！", 0).show();
          }
          localIOException2 = localIOException2;
          try                 
          {
            Toast.makeText(this, "连接失败！", 0).show();
            this._socket.close();
            this._socket = null;
            return;
          }
          catch (IOException localIOException3)
          {
            Toast.makeText(this, "连接失败！", 0).show();
            return;
          }
        }
        catch (IOException localIOException4)
        {
          Toast.makeText(this, "接收数据失败！", 0).show();
          return;
        }
      }
    }
    this.bRun = true;
  }
这段老是报错，没办法编译其中      catch (IOException localIOException2)
老是提示Multiple ers at this line
- Syntax error on token "localIOException2", 
 VariableDeclaratorId expected after this token
- localIOException2 cannot be resolved to a type
- Duplicate parameter localIOException2
如果把其中一个catch(IOException localIOException2)内的localIOException2变成localIOException1的话 String str = paramIntent.getExtras().getString(DeviceListActivity.EXTRA_DEVICE_ADDRESS);又报错请指点

Answer 1

 Thread ReadThread = new Thread()
  {
    public void run()
    {
      byte[] arrayOfByte1 = new byte[1024];
      byte[] arrayOfByte2 = new byte[1024];
      BTClient.this.bRun = true;
      while (true)
      {
        int j;
        int k;
        try
        {
          if (BTClient.this.is.available() != 0)
          {
            int i = BTClient.this.is.read(arrayOfByte1);
            j = 0;
            String str1 = new String(arrayOfByte1, 0, i);
            BTClient localBTClient1 = BTClient.this;
            localBTClient1.fmsg += str1;
            k = 0;
            if (k < i)
              continue;
            String str2 = new String(arrayOfByte2, 0, j);
            BTClient localBTClient2 = BTClient.this;
            localBTClient2.smsg += str2;
            if (BTClient.this.is.available() != 0)
              continue;
            BTClient.this.handler.sendMessage(BTClient.this.handler.obtainMessage());
            continue;
            if ((arrayOfByte1[k] == 13) && (arrayOfByte1[(k + 1)] == 10))
            {
              arrayOfByte2[j] = 10;
              k++;
            }
            else
            {
              arrayOfByte2[j] = arrayOfByte1[k];
            }
          }
          if (!BTClient.this.bRun)
            continue;
          continue;
        }
        catch (IOException localIOException)
        {
        }
        continue;
        j++;
        k++;
      }
    }
  };
这里            if ((arrayOfByte1[k] == 13) && (arrayOfByte1[(k + 1)] == 10))
            {
              arrayOfByte2[j] = 10;
              k++;
            }
            else
            {
              arrayOfByte2[j] = arrayOfByte1[k];
            }
老是报错Unreachable code请解