怎么实现插入数据后就弹出添加成功？

Question

 protected void Button1_Click(object sender, EventArgs e)
    {
        try
        {
            string name = TextBox1.Text;
            string pwd = TextBox2.Text;
            string cmd = "insert into admin values('"+ name +"','"+ pwd +"')";
            SqlConnection conn = new SqlConnection(ConfigurationManager.AppSettings["sql"]);
            conn.Open();
            SqlCommand com = new SqlCommand(cmd, conn);
            com.ExecuteNonQuery();            conn.Close();
            MessageBox.Show("添加成功");        }
        catch 
        {            RegisterStartupScript("","<script>alert('添加失败')</script>");
        }
    }如何让插入数据后就弹出个对话框，添加成功,这个代码怎么写我忘记了

Answer 1

MessageBox.Show是WinForm程序的写法，
Page.ClientScript.RegisterStartupScript是Web程序的写法

Answer 2

web程序也可以直接写Response.Write("<script>alert('添加成功！');</script>");

Answer 3

RegisterStartupScript("","<script>alert('添加成功!')</script>");这样应可以吧...

Answer 4

强烈建议用
Page.ClientScript.RegisterStartupScript(typeof(string),"","<Script>...</Script>")
不用
Response.Write("<script>alert('添加成功！');</script>");

Answer 5

最好在里面加上判断if(com.ExecuteNonQuery()==1)
{
Response.Write("<script>alert('添加成功！');</script>");
}
else
{
Response.Write("<script>alert('添加失败！');</script>");
}

Answer 6

        ScriptManager.RegisterClientScriptBlock(this, this.GetType(), "", "alert('添加成功');", true);搞错了, 应是这个, 我测试过, 没问题的...

Answer 7

RegisterStartupScript("","<script>alert('添加失败')</script>");自己会写添加失败的代码
成功的就MessageBox????

Answer 8

Page.ClientScript.RegisterStartupScript(this.GetType(), "", "<script language=javascript> window.alert('數據保存成功');</script>");

Answer 9

public  void showJavascript(string showMes)
    {
        Page.ClientScript.RegisterStartupScript(this.GetType(), "", "alert('" + showMes + "');", true);
    }