读取一个返回XML,跪求大神...

Question

<?xml version="1.0" encoding="utf-8"?><string xmlns="http://tempuri.org/">-4456116940642369971</string>
请问如何读取到里面的-4456...的数据?跪求大神教教小弟....

Answer 1

 string xml = @" <?xml version=""1.0"" encoding=""utf-8""?><string xmlns=""http://tempuri.org/"">-4456116940642369971</string>";
            var txt = Regex.Match(xml, @"(?i)<string[^>]+>([^<]+)</string>").Groups[1].Value;
            Console.WriteLine(txt);
           

Answer 2

System.Xml.Linq.XElement ele = XElement.Load("app.xml");
string va = ele.Value;
把这个
<?xml version="1.0" encoding="utf-8"?><string xmlns="http://tempuri.org/">-4456116940642369971</string>
XML字符串写成XML文件，然后使用linq去读取

Answer 3

  XmlDocument xmlDoc=new XmlDocument();
  xmlDoc.Load(System.Web.HttpContext.Current.Server.MapPath("xml路径"));
  XmlNode xn = xmlDoc.SelectSingleNode("string ");
  string value=xn.InnerText;

Answer 4

XmlDocument xmlDoc=new XmlDocument();
xmlDoc.Load(@"路径");
//如果从字符串加载:xmlDoc.LoadXml("xml文本字符串");
Response.Write(xmlDoc.DocumentElement.InnerText);