ArrayList objList = new ArrayList(); objList.Add(你自己的对象);GridView.DataSource = objList; GridView.DataBind();
<%# ((Person)Container.DataItem).Id %>
to ryoma_fly : 我就是按照你的方法将很多个对象Add到ArrayList中去了,问题是,被加入的对象中有一个属性也是对象(Person),我需要DataGrid显示Person.Name ,你那样写是无法绑定Person.Name的
to youbl : 谢谢! 如果CodeBehind 怎么写?
CodeBehind?绑定到DataGrid,也是一样 Person tmp = (Person)e.Item.DataItem;如果绑定到DropDownList,看如下示例代码: public class test : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { Person tmp; List<Person> arr = new List<Person>(); tmp = new Person("a"); arr.Add(tmp); tmp = new Person("b"); arr.Add(tmp); lst1.DataSource = arr; lst1.DataTextField = "id"; lst1.DataBind(); }}class Person { public Person(string id) { this.id = id; } private string id; public string Id { get { return id; } set { id = value; } } }
楼上没理解我的意思, 我要用DataGrid和DropDownList(两个控件都有这个问题) 绑定 Department,并且要显示 Person.Name 环境:Framework 1.1 我的类是这样的,比如:class Department { public Department() {
} private string id; private Person person;//这个属性本身也是一个对象 public string Id { get { return id; } set { id = value; } } public Person MyPerson { get { return person; } set { person= value; } } } class Person { public Person() { } private string name; public string Name { get { return name; } set { name = value; } } }
objList.Add(你自己的对象);GridView.DataSource = objList;
GridView.DataBind();
Person tmp = (Person)e.Item.DataItem;如果绑定到DropDownList,看如下示例代码:
public class test : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
Person tmp;
List<Person> arr = new List<Person>();
tmp = new Person("a");
arr.Add(tmp); tmp = new Person("b");
arr.Add(tmp); lst1.DataSource = arr;
lst1.DataTextField = "id";
lst1.DataBind();
}}class Person
{
public Person(string id)
{
this.id = id;
}
private string id;
public string Id
{
get { return id; }
set { id = value; }
}
}
环境:Framework 1.1 我的类是这样的,比如:class Department
{
public Department()
{
}
private string id;
private Person person;//这个属性本身也是一个对象 public string Id
{
get { return id; }
set { id = value; }
} public Person MyPerson
{
get { return person; }
set { person= value; }
}
}
class Person
{
public Person()
{ }
private string name;
public string Name
{
get { return name; }
set { name = value; }
}
}