遍历页面所有Repeater的方法

Question

求遍历页面所有Repeater的方法，请各位朋友帮帮忙。for (int i = 0; i < Page.Controls.Count; i++)
        {
            foreach (System.Web.UI.Control control in Page.Controls[i].Controls)
            {
                if (control is Repeater)  //这里判断是否是Repeater型，可是遍历到最后也没找到Repeater型的
                {
                    Repeater repeater = (control as Repeater);
                    int num = int.Parse(repeater.ID.Substring(repeater.ID.Length - 1, repeater.ID.Length));
                    if (hashTable.ContainsKey(num))
                    {
                        repeater.DataSource = (IList<Info>)hashTable[num];
                        repeater.DataBind();
                    }
                    else
                    {
                        repeater.Visible = false;
                    }
                }
            }
        }
我在后台可以找到这个Repeater，但是我遍历就找不到了

Answer 1

TOP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 2

这样试试：
foreach (System.Web.UI.WebControls.Repeater rep in Page.Controls)
            { 
                
            }

Answer 3

Page.Controls
改为this.form.Controls

Answer 4

foreach (Control objRepeater in this.form1.Controls)
        {
            if (objRepeater.GetType().Name == "Repeater")
            {
               //找到
                
            }
        }这样试试

Answer 5

            foreach (System.Web.UI.Control control in Page.Controls)
            {
                if (control is Repeater)  //这里判断是否是Repeater型，可是遍历到最后也没找到Repeater型的
                {
                    Repeater repeater = (control as Repeater);
                    int num = int.Parse(repeater.ID.Substring(repeater.ID.Length - 1, repeater.ID.Length));
                    if (hashTable.ContainsKey(num))
                    {
                        repeater.DataSource = (IList<Info>)hashTable[num];
                        repeater.DataBind();
                    }
                    else
                    {
                        repeater.Visible = false;
                    }
                }
            }
        这样可以实现的，我做过