asp.ne页面中，刷新页面提交数据怎么解决

Question

本帖最后由 rwh871212 于 2011-08-24 12:22:51 编辑

Answer 1

后台代码： 
public partial class Index : System.Web.UI.Page
    {
        protected void Page_Load(object sender, EventArgs e)
        {
        }
          /// <summary>
        /// 新增报名事件
        /// </summary>
        /// <param name="sender"></param>
        /// <param name="e"></param>
        protected void button_Click(object sender, EventArgs e)
        {
            if (CarServer.AddCarServer(
                Server.HtmlEncode(txtCompanyName.Value),
                Server.HtmlEncode(txtUserName.Value),
                Server.HtmlEncode((ddlSex.Value).ToString()),
                Server.HtmlEncode(txtAge.Value),
                Server.HtmlEncode(txtPhone.Value),
                Server.HtmlEncode(txtAddress.Value),
                Server.HtmlEncode((ddlJob.Value).ToString()),
                Server.HtmlEncode((ddlType.Value).ToString()),
                Server.HtmlEncode(txtIDNO.Value),
                Server.HtmlEncode(txtRe.Value)))
            {
                RegisterScript("保存成功！");
              
            }
            else
            {
                RegisterScript("保存失败！");
            }
            Clear();
        }        /// <summary>
        /// 调查事件
        /// </summary>
        /// <param name="sender"></param>
        /// <param name="e"></param>
        protected void btnSub_Click(object sender,EventArgs e)
        {
            string way = "000";
            string isNeed ="00"; 
            if (rdoNeed.Checked)
            {
          isNeed ="10";
            }
            if (rdoNotNeed.Checked)
            {
                isNeed = "01";
            }            if (txtWay1.Checked)
            {
                way = "100";
            }
            if (txtWay2.Checked)
            {
                way = "010";
            }
            if (txtWay3.Checked)
            {
                way = "001";
            }
            if (txtWay1.Checked && txtWay2.Checked)
            {
                way = "110";
            }
            if (txtWay1.Checked && txtWay3.Checked)
            {
                way = "101";
            }
            if (txtWay2.Checked && txtWay3.Checked)
            {
                way = "011";
            }            if (Search.AddSearch(
                isNeed,
                way,
                Server.HtmlDecode(txtAdvise.Value)))
            {
                RegisterScript("保存成功！");
            }else
        {
                RegisterScript("保存失败！");        
        }
            Empty();
        }

Answer 2

Response.Write("<script>location.href=\"当前页面或其它\";</script>")
return;

Answer 3

Server.HtmlDecode(txtAdvise.Value)))
  {
  RegisterScript("保存成功！");
Response.Write("<script>location.href=\"Index.aspx\";</script>")
return;   }else
{
  RegisterScript("保存失败！");   
}
  Empty();不对呀？兄弟

Answer 4

用Response.Write 来写script 这是个很蛋疼的做法 这种破坏性的脚本 建议还是不要
可以用page.scriptmanage里的一些方法实现脚本注册 或者重定向页面加参数以提示结果 
比较推荐的是用ajax来提交 返回json结果判断后操作。

Answer 5

#region 弹窗并跳转，防止刷新
public static void Alert(Page page, string p, string math) {
page.Response.Write("<script language='javascript'>alert('" + p + "');window.location.href='" + math + "';</script>");
}
#endregion

Answer 6

postback 在很多情况下都会影响提交和刷新的，一般建议提交后重定向，或是用ajax。