如何交换两个Panel的位置?

Question

一个Table(一行两列)每个单元格里面有一个Panel,如何点击一个Button交换两个Panel的位置?

Answer 1

如果需要比较准确地对齐排版，使用<table>.

Answer 2

思路:
button的onClick="switch"
function:switch()中,通过DOM来操作,交换两个PANELjavascript不是很熟，好像是这样的：
var table=document.getElementById("table1");
var panel1=table.childNodes[0];
var panel2=table.childNodes[1];
table.removeNamedItem(panel1);
table.removeNamedItem(panel2);
table.appendChild(panel2);
table.appendChild(panel1);

Answer 3

this.panel1.location=new point(x,y);
this.panel2.location=new point(x,y);
x,y是坐标，你试试了`!!!

Answer 4

这个看起来挺好的，试试看吧，
-----
给另外一种思路，有些土。
每个单元格里放两个Panel，通过隐藏Panel来实现楼主的效果。

Answer 5

 <table style="width: 100%;" id="table1" runat="server">
            <tr>
                <td>
                    <asp:Panel ID="Panel1" runat="server">
                        <asp:Label ID="Label1" runat="server" Text="Label1" />
                    </asp:Panel>
                </td>
                <td>
                    <asp:Panel ID="Panel2" runat="server">
                        <asp:Label ID="Label2" runat="server" Text="Label2" />
                    </asp:Panel>
                </td>
            </tr>
            <tr>
                <td colspan="2">
                    <asp:Button ID="Button1" runat="server" Text="点击交换Panel位置" 
                        onclick="Button1_Click" />
                </td>
            </tr>
</table>
protected void Page_Load(object sender, EventArgs e)
        {
            if (!IsPostBack)
                ViewState["Swap"] = false;                   }        protected void Button1_Click(object sender, EventArgs e)
        {
            bool swap = (bool)ViewState["Swap"];
            swap = !swap;
            if (swap)
            {
                table1.Rows[0].Cells[0].Controls.Remove(Panel1);
                table1.Rows[0].Cells[0].Controls.Add(Panel2);
                table1.Rows[0].Cells[1].Controls.Remove(Panel2);
                table1.Rows[0].Cells[1].Controls.Add(Panel1);
            }
            else
            {
                table1.Rows[0].Cells[0].Controls.Remove(Panel2);
                table1.Rows[0].Cells[0].Controls.Add(Panel1);
                table1.Rows[0].Cells[1].Controls.Remove(Panel1);
                table1.Rows[0].Cells[1].Controls.Add(Panel2);
            }
            ViewState["Swap"] = swap;
            
        }

Answer 6

你要做的根本需求不会是类似Google的WebPart吧，为什么要按钮呢，感觉需求比较怪，能否说一下具体应用在什么地方，可能有更好的解决方案。