求算法！！！！！！！！！急

Question

用做一个html日期显示的表格
是7*6格式的(42个格)我用一个
    for (int i = 0; i < 6; i++)  //拼接tr
        {
               for (int i = 0; i < 7; i++)   //拼接td
                 {
                     
                      //这地方没有什么算法根据本月第一天是星期几跳过拼接显示空白
                      //还有就是最后一天的后面也是空白(一共42个格)
                 }            
         }

Answer 1

for   (int   i   =   0;   i   <   6;   i++)     //拼接tr 
                { 
                              for   (int   j   =   0;   j   <   7;   i++)       //拼接td 
                                  { 
                                          
                                            //这地方没有什么算法根据本月第一天是星期几跳过拼接显示空白 
                                            //还有就是最后一天的后面也是空白(一共42个格) 
                                  }                         
                  } 

Answer 2

可以啊
你可以加
for   (int   i   =   0;   i   <   7;   i++)  
{
 if(i<(int)DateTimeFirstDat.DayOfWeek) {
  html+="<td></td>";
}
else
html+="<td>"+0+"</td>";}

Answer 3

本帖最后由 net_lover 于 2011-12-10 15:22:29 编辑

  

Answer 4

private string BuildCalendar(int year, int month)
{
DateTime date = new DateTime(year, month, 1);
int days = date.AddMonths(1).AddDays(-1).Day;

System.Text.StringBuilder table = new System.Text.StringBuilder("<table border='1'>");
string fmt = "<td>{0}</td>"; int week = (int)date.DayOfWeek;
if (week != 0)
table.Append("<tr><td colspan='" + week + "'>空白</td>"); for (int i = 1; i <= days; ++i)
{
week %= 7;
if (week == 0)
table.Append("<tr>");
table.AppendFormat(fmt, i);
if (week == 6)
table.Append("</tr>");
++week;
} if (week < 7)
table.Append("<td colspan='" + (7 - week) + "'>空白</td></tr>"); table.Append("</table>"); return table.ToString();
}

Answer 5

日历表
//给定如何一个日期
DateTime x = new DateTime(2011, 10, 13);
//得到该日期的第一天的星期
DateTime d1 = new DateTime(x.Year, x.Month, 1);
DateTime d2 = d1.AddMonths(1).AddDays(-1);
int startWeek = (int)d1.DayOfWeek;
int endWeek = (int)d2.DayOfWeek;
String html = "<table border=1>";
int day = 0;
String[] weekName = { "日", "一", "二", "三", "四", "五", "六" };
for (int j = 0; j < 6; j++)     //拼接tr 
{
  if (j == 0)
  {
    html += "<tr>";
    for (int i = 0; i < 7; i++)
    {
      html += "<th>星期" + weekName[i] + "</th>";
    }
    html += "</tr>";
  }
  html += "<tr>";
  for (int i = 0; i < 7; i++)       //拼接td 
  {
    if ((i < startWeek && j == 0) || (i > endWeek && 5 == j))
    {
      html += "<td>&nbsp;</td>";
    }
    else
    {
      html += "<td>" + (++day) + "</td>";
    }
  }
  html += "</tr>";
}html += "</table>";
Response.Write(html);

Answer 6

本帖最后由 net_lover 于 2011-12-10 16:05:10 编辑

  

Answer 7

你耍猴呢?看你嵌套循环几个i？if哪个i·不用试了

Answer 8

DateTime x = DateTime.Now;
            //得到该日期的第一天的星期
            DateTime d1 = new DateTime(x.Year, x.Month, 1);
            DateTime d2 = d1.AddMonths(1).AddDays(-1);
            int startWeek = (int)d1.DayOfWeek;
            int endWeek = (int)d2.DayOfWeek;
            int days = d2.Day;
            int day = 0;
            sb.Append("<table id=\"bigCal\" class=\"pripackage_date_list\"  cellpadding=\"0\" cellspacing=\"0\">");
            #region
            for (int t = 0; t < 2; t++)
            {
                if (t == 0)
                {
                    sb.Append("<thead>");
                }
                else
                {
                    sb.Append("</tbody>");
                }                int endStart = t == 1 ? 6 : 1;
                for (int i = 0; i < endStart; i++)
                {                    sb.Append("<tr>");
                    for (int j = 0; j < 7; j++)
                    {
                        #region -加载星期几表头
                        if (endStart == 1) //第一行？
                        {
                            string strClass = "";
                            if (j == 0)
                                strClass = "class=\"pripackage_sun\"";
                            else if (j == 6)
                                strClass = "class=\"pripackage_sat\"";
                            sb.Append("<td " + strClass + ">星期" + nStr1[j] + "</td>");                        }
                        #endregion
                        #region -加载日期
                        else
                        {
                            if ((i < startWeek && j == 0) || (i > endWeek && 5 == j) || (day >= days))
                            {
                                sb.Append("<td></td>");
                            }
                            else
                            {
                                sb.Append("<td class=\"\"><div class=\"pripackage_dateon\"><span></span>" + (++day) + "<dfn class=\"pripackage_state03\">&nbsp;</dfn><div class=\"base_price\"><dfn>&#165;</dfn>3,760起</div></div></td>");
                            }
                        }
                        #endregion
                    }                }
                if (t == 0)
                {
                    sb.Append("</thead>");
                }
                else
                {
                    sb.Append("</tbody>");
                }
            }
            sb.Append("</table>");
            return sb.ToString();

Answer 9

写出来了       if (i == 0)
                            {
                                if (j < firstDayWeek)
                                {                                    sb.Append("<td></td>");
                                }
                                else
                                {
                                    sb.Append("<td class=\"\"><div class=\"pripackage_dateon\"><span></span>" + (++day) + "<dfn class=\"pripackage_state03\">&nbsp;</dfn><div class=\"base_price\"><dfn>&#165;</dfn>3,760起</div></div></td>");
                                    day++;
                                }
                            }
                            else
                            {
                                if (days <= day)
                                    sb.Append("<td></td>");
                                else
                                {
                                    sb.Append("<td class=\"\"><div class=\"pripackage_dateon\"><span></span>" + (++day) + "<dfn class=\"pripackage_state03\">&nbsp;</dfn><div class=\"base_price\"><dfn>&#165;</dfn>3,760起</div></div></td>");
                                    day++;
                                }
                            }

Answer 10

http://topic.csdn.net/u/20111108/23/d28f5539-063b-4754-9879-9a061861ec27.html

Answer 11

这种东西用服务端来做就是个错误
现在人都说ASP性能差，我看最主要的原因是用的人不专业。jquery的ui已经有日历这功能了<!DOCTYPE html>
<html>
<head>
  <link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/>
  <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js"></script>
  <script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script>  <script>
  $(document).ready(function() {
    $("#datepicker").datepicker();
  });
  </script>
</head>
<body style="font-size:62.5%;"><div type="text" id="datepicker"></div></body>
</html>
保存为HTML文件看效果