我有一个XML本地文件,路径:C:\abc.xml,
<?xml version="1.0"?>
-<student> <stuid>33</stuid> <stuname>444</stuname> </student>我需要读取stuid 与stuname的内容,初学者不怎么会啊,求赐教。

解决方案 »

  1.   

    http://www.cnblogs.com/XmNotes/archive/2010/08/12/1796162.html
      

  2.   

               XmlDocument xml = new XmlDocument();
                xml.Load(@"C:\abc.xml");
                XmlNode stuid = xml.SelectSingleNode("/student/stuid");
                XmlNode stuname = xml.SelectSingleNode("/student/stuname");
                Console.WriteLine("{0} {1}", stuid.InnerText, stuname.InnerText);http://www.68design.net/Development/Aspnet/Basis-AspNet/11369-1.html
      

  3.   

    XmlDocument xd=XmlDocument.Losd(@"C:\abc.xml");
    - -
      

  4.   

    //读出XML文件,显示在GridView1中
                DataSet ds = new DataSet();
                ds.ReadXml(Server.MapPath("abc.xml"));
                if (ds.Tables.Count > 0)
                {
                    GridView1.DataSource = ds;
                    GridView1.DataBind();
                }