帮我读取一段XML文件，把里面的值读出来

Question

<?xml       version="1.0"       encoding="utf-8"?>   
<?mso-infoPathSolution       name="urn:schemas-microsoft-com:office:infopath:g7EXE:-myXSD-2007-11-28T07-29-38"       solutionVersion="1.0.0.11"       productVersion="12.0.0.0"       PIVersion="1.0.0.0"       href="http://itlp1:2020/DocLib3/Forms/template.xsn"?>   
<?mso-application       progid="InfoPath.Document"       versionProgid="InfoPath.Document.2"?>   
<my:myFields       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"       xmlns:my="http://schemas.microsoft.com/office/infopath/2003/myXSD/2007-11-28T07:29:38"       xmlns:xd="http://schemas.microsoft.com/office/infopath/2003"       xml:lang="zh-CN">   
<my:date>   2007-12-19T00:00:00   </my:date>   
<my:applyer>   
<my:username>   test   </my:username>   
<my:dept>   人力资源部   </my:dept>   
</my:applyer>   
<my:info>   
<my:begin_date>   2007-12-19T00:00:00   </my:begin_date>   
<my:end_date>   2007-12-19T00:00:00   </my:end_date>   
<my:type>   病假   </my:type>   
<my:note>   阿飞上的嘎斯蛋糕               </my:note>   
<my:tianshu>   1   </my:tianshu>   
</my:info>   
</my:myFields>   
能否帮下，读出代码，编码是UTF-8的，编码不能变，谁帮我实现下，谢谢大家

Answer 1

<?xml version="1.0" encoding="utf-8"?>
<?mso-infoPathSolution name="urn:schemas-microsoft-com:office:infopath:g7EXE:-myXSD-2007-11-28T07-29-38" solutionVersion="1.0.0.11" productVersion="12.0.0.0" PIVersion="1.0.0.0" href="http://itlp1:2020/DocLib3/Forms/template.xsn"?>
<?mso-application progid="InfoPath.Document" versionProgid="InfoPath.Document.2"?>
<my:myFields xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:my="http://schemas.microsoft.com/office/infopath/2003/myXSD/2007-11-28T07:29:38" xmlns:xd="http://schemas.microsoft.com/office/infopath/2003" xml:lang="zh-CN">
  <my:date>2007-12-19T00:00:00</my:date>
  <my:applyer>
    <my:username>test</my:username>
    <my:dept>人力资源部</my:dept>
  </my:applyer>
  <my:info>
    <my:begin_date>2007-12-19T00:00:00</my:begin_date>
    <my:end_date>2007-12-19T00:00:00</my:end_date>
    <my:type>病假</my:type>
    <my:note>阿飞上的嘎斯蛋糕</my:note>
    <my:tianshu>1</my:tianshu>
  </my:info>
</my:myFields>//用ASP.NET实现
protected void Page_Load(object sender, EventArgs e)
{
    System.Xml.XmlDocument doc = new XmlDocument();
    doc.Load(Server.MapPath("XMLFile.xml"));    ParseXML(doc.DocumentElement);
     
}//解析XML
private void ParseXML(System.Xml.XmlNode element)
{
    if (element.NodeType == System.Xml.XmlNodeType.Text)
    {
        Response.Write(string.Format("{0}<br />", element.Value));
    }
    else
    {
        foreach (System.Xml.XmlNode ele in element.ChildNodes)
        {
            ParseXML(ele);
        }
    }
}

Answer 2

这个不行， doc.Load(Server.MapPath("XMLFile.xml"))会出错
给定编码中的字符无效。 行 7，位置 16。

Answer 3

帮我读取一段XML文件，把里面的值读出来  
------------
楼主所想要的是那些值?楼主可以参考下一XmlDocument doc = new XmlDocument();        doc.Load(Server.MapPath("data2.xml"));
        XPathNavigator oXPathNav;
        oXPathNav = doc.CreateNavigator();        XPathExpression Expr;
        Expr = oXPathNav.Compile("//my:myFields");        XmlNamespaceManager oxmlNSManager = new XmlNamespaceManager(oXPathNav.NameTable);
        oxmlNSManager.AddNamespace("my", "http://schemas.microsoft.com/office/infopath/2003/myXSD/2007-11-28T07:29:38");
        Expr.SetContext(oxmlNSManager);        XPathNodeIterator iterator = oXPathNav.Select(Expr);        while (iterator.MoveNext())
        {
            
            Response.Write(iterator.Current.Name+":"+iterator.Current.Value+"\r\n");
            
            
        }        oxmlNSManager = null;
        oXPathNav = null;
        doc = null;

Answer 4

XmlDocument xd = new XmlDocument();
   xd.Load(@"C:\Inetpub\wwwroot\number\read.xml");   //load all movies
   XmlNodeList xnl = xd.SelectNodes("//movie");
   foreach(XmlNode xn in xnl)
   {
    //load all attributes of current movie
    foreach (XmlAttribute xa in xn.Attributes)
    {
     Response.Write("<b>" + xa.Name + "</b>:" + xa.InnerText  + ",");
    }
    Response.Write ("<hr size=\"1\" />");    //the child nodes of current node which named movie
    foreach (XmlNode xcn in xn.ChildNodes)
    {
     Response.Write("<b>" +xcn.Name + "</b>:" + xcn.InnerText   + "<br/>");     if (xcn.HasChildNodes)
     {
      Response.Write("<br/>------------------------<br/>");
     }     //load nodes named file
     foreach (XmlNode xccn in xcn.ChildNodes)
     {
      Response.Write("<b>" + xccn.Name + "</b>:" + xccn.InnerText + "<br/>");
     }
    }
    Response.Write("<br/><br/><br/>");
   }lz 参考一下下哈

Answer 5

楼主应该掌握方法后自己解决问题，而不是直接要别人来帮你解决问题先掌握.net操作xml的方法吧在C#.net中如何操作XML 
http://www.cnblogs.com/weekzero/archive/2005/06/21/178140.html

Answer 6

XmlDocument xd = new XmlDocument();
xd.Load(@"C:\Inetpub\wwwroot\number\xml\XMLFile1.xml"); XmlNamespaceManager oxmlNSManager = new XmlNamespaceManager(xd.NameTable);
oxmlNSManager.AddNamespace("my", "http://schemas.microsoft.com/office/infopath/2003/myXSD/2007-11-28T07:29:38");

XmlNodeList xnl = xd.SelectNodes("//my:myFields",oxmlNSManager); foreach(XmlNode xn in xnl)
{
//load all attributes of current movie
foreach (XmlAttribute xa in xn.Attributes)
{
Response.Write("<b>" + xa.Name + "</b>:" + xa.InnerText  + ",");
}
Response.Write ("<hr size=\"1\" />"); //the child nodes of current node which named movie
foreach (XmlNode xcn in xn.ChildNodes)
{
Response.Write("<b>" +xcn.Name + "</b>:" + xcn.InnerText   + "<br/>"); if (xcn.HasChildNodes)
{
Response.Write("<br/>------------------------<br/>");
} //load nodes named file
foreach (XmlNode xccn in xcn.ChildNodes)
{
Response.Write("<b>" + xccn.Name + "</b>:" + xccn.InnerText + "<br/>");
}
}
Response.Write("<br/><br/><br/>");
}