private string fName;
private void button1_Click(object sender, EventArgs e)
{
OpenFileDialog openFileDialog = new OpenFileDialog();
openFileDialog.InitialDirectory = "c:\\";
openFileDialog.Filter = "文本文件|*.*|C#文件|*.cs|所有文件|*.*";
openFileDialog.RestoreDirectory = true;
openFileDialog.FilterIndex = 1;
if (openFileDialog.ShowDialog() == DialogResult.OK)
{
fName =openFileDialog.FileName;
}我想利用openFileDialog打开对话框,选择txt文件,然后在RichTxtBox里面读出来,请问应该怎么做呢?
我程序写到这儿就不知道怎么写了。
谢谢大家了
private void button1_Click(object sender, EventArgs e)
{
OpenFileDialog openFileDialog = new OpenFileDialog();
openFileDialog.InitialDirectory = "c:\\";
openFileDialog.Filter = "文本文件|*.*|C#文件|*.cs|所有文件|*.*";
openFileDialog.RestoreDirectory = true;
openFileDialog.FilterIndex = 1;
if (openFileDialog.ShowDialog() == DialogResult.OK)
{
fName =openFileDialog.FileName;
}我想利用openFileDialog打开对话框,选择txt文件,然后在RichTxtBox里面读出来,请问应该怎么做呢?
我程序写到这儿就不知道怎么写了。
谢谢大家了
rtb.LoadFile(fName);最好在初始化OpenFileDialog时加一句:
openFileDialog.CheckFileExists = true;
确保文件存在
看看:
http://hi.baidu.com/hhh3h