代码模板为
string templete = ""http://www.myside.com/default.aspx?a=stra&b=strb&c=strc""现在已知 a=100,b=150,c=20
求一个函数需要生成如下代码"http://www.myside.com/default.aspx?a=100&b=150&c=20"
string templete = ""http://www.myside.com/default.aspx?a=stra&b=strb&c=strc""现在已知 a=100,b=150,c=20
求一个函数需要生成如下代码"http://www.myside.com/default.aspx?a=100&b=150&c=20"
int a = 100;
int b = 150;
int c = 20;string templete = @"http://www.myside.com/default.aspx?a={0}&b={1}&c={2}";
Text = string.Format(templete, a, b, c);
您的方法是可以解决
但是如果abc的顺序换了
是不是要修改程序阿??
我需要的倒按照已知字符串替换的
string templete = @"http://www.myside.com/default.aspx?a=<%a%>&b=<%b%>&c=<%c%>";
templete = templete.Replace("<%a%>", a.ToString());
templete = templete.Replace("<%b%>", b.ToString());
templete = templete.Replace("<%c%>", c.ToString());
{
if (!query.Contains(obstruct))
return string.Empty; StringBuilder sbStr = new StringBuilder();
int startPosition = 0;
int endPosition = 0; startPosition = query.IndexOf(obstruct, 0, query.Length); if (startPosition <= 0)
return string.Empty; endPosition = query.IndexOf("&", (startPosition + obstruct.Length)); if (endPosition <= 0)
{
endPosition = query.Length;
} sbStr.Append(query.Substring((startPosition + obstruct.Length), (endPosition - (startPosition + obstruct.Length)))); ///(j+obstruct.Length),i-j) return sbStr.ToString();
}