vb.net的,c#也差不多:
http://www.zdnet.com.cn/developer/code/story/0,2000081534,39048920,00.htm
http://www.zdnet.com.cn/developer/code/story/0,2000081534,39048920,00.htm
解决方案 »
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Stream imgDataStream = upFile.PostedFile.InputStream;
int imgDataLen = upFile.PostedFile.ContentLength;
byte[] imgDataTemp = new byte[imgDataLen];
imgDataStream.Read( imgDataTemp, 0, imgDataLen );写回:
Response.BinaryWrite( imgDataTemp );
Response.End();
FileStream f_stream;
f_stream = new FileStream(strFileName, FileMode.Open);
BinaryReader fReader = new BinaryReader(f_stream);FileInfo fi = new FileInfo(strFileName);
int iReadCount = fi.Length;byte[] bBuffer = new byte[iReadCount];bBuffer = fReader.ReadBytes(iReadCount);
StreamReader MySRead=new StreamReader((System.IO.Stream)File.OpenRead("e:\\1.txt"),System.Text.Encoding.Default);
string strHts=MySRead.ReadToEnd();
Response.Write(strHts);
MySRead.Close();
http://expert.csdn.net/Expert/topic/2565/2565728.xml?temp=2.326602E-02
using System.IO;class Test
{
public static void Main()
{
try
{
// Create an instance of StreamReader to read from a file.
// The using statement also closes the StreamReader.
using (StreamReader sr = new StreamReader("TestFile.txt"))
{
String line;
// Read and display lines from the file until the end of
// the file is reached.
while ((line = sr.ReadLine()) != null)
{
Console.WriteLine(line);
}
}
}
catch (Exception e)
{
// Let the user know what went wrong.
Console.WriteLine("The file could not be read:");
Console.WriteLine(e.Message);
}
}
}